x+4*25%=200
So sánh: 101 x 4 ... 200 – 25 x
A. <
B. >
C. =
x-4*25%+10=200
giup mik
\(x-4\times25\%+10=200\)
\(=x-1+10=200\)
\(x-1=200-10\)
\(x-1=190\)
\(x=190+1\)
\(x=191\)
\(a.25\) x \(432\) x \(4\) \(=\)
\(b.456 \) x \(200-\) \(456\) x \(100=\)
`a)25xx532xx4`
`=(25xx4)xx432`
`=432xx100=43200`
`b)456xx200-456xx100`
`=456xx(200-100)`
`=456xx100=45600`
\(a,25\times432\times4=25\times4\times432=100\times432=4320\\ b,456\times200-456\times100=456\times\left(200-100\right)=456\times100=45600\)
`25 xx 432 xx 4 = (25xx4 ) xx 432 = 100 xx 432 = 43200`
`456 xx200 - 456 xx 100 = 456 xx ( 200 - 100 ) = 456 xx 100 = 45600`
155-25/2×4×1/10+X÷3/4=200
\(155-\frac{25}{2}\times4\times\frac{1}{10}+x\div\frac{3}{4}=200\)
\(\rightarrow155-5+x\div\frac{3}{4}=200\)
\(\rightarrow150+x\div\frac{3}{4}=200\)
\(\rightarrow x\div\frac{3}{4}=200-150\)
\(\rightarrow x\div\frac{3}{4}=50\)
\(\rightarrow x=50\times\frac{3}{4}\)
\(\rightarrow x=\frac{75}{2}\)
Vậy \(x=\frac{75}{2}\)
Tìm x biết
A, 200÷25 -(12-x)=4. B, (x-10).5=100-20.4
\(200:25-\left(12-x\right)=4\\ 8-\left(12-x\right)=4\\ 12-x=8-4\\ 12-x=4\\ x=12-4\\ x=8\\ ---\\ \left(x-10\right).5=100-20.4\\ \left(x-10\right).5=100-80=20\\ x-10=\dfrac{20}{5}=4\\ x=4+10=14\)
a)\(200:25-\left(12-x\right)=4\)
\(\Rightarrow8-\left(12-x\right)=4\)
\(\Rightarrow12-x=8-4\)
\(\Rightarrow12-x=4\)
\(\Rightarrow x=12-4\)
\(\Rightarrow x=8\)
b) \(\left(x-10\right)\cdot5=100-20\cdot4\)
\(\Rightarrow\left(x-10\right)\cdot5=100-80\)
\(\Rightarrow\left(x-10\right)\cdot5=20\)
\(\Rightarrow x-10=4\)
\(\Rightarrow x=10+4\)
\(\Rightarrow x=14\)
97/20 x ( 25/8 - 221/200 )< x < 91/10 x (137/20 + 11/4)
Đề bài : \(\dfrac{97}{20}\times\left(\dfrac{25}{8}-\dfrac{221}{200}\right)< x< \dfrac{91}{10}\times\left(\dfrac{137}{20}+\dfrac{11}{4}\right)\)
\(\dfrac{97}{20}\times\left(\dfrac{25}{8}-\dfrac{221}{200}\right)=\dfrac{97}{20}\times\dfrac{101}{50}=\dfrac{9797}{1000}\)
\(\dfrac{91}{10}\times\left(\dfrac{137}{20}+\dfrac{11}{4}\right)=\dfrac{91}{10}\times\dfrac{48}{5}=\dfrac{2184}{25}=\dfrac{2184\times40}{25\times40}=\dfrac{87360}{1000}\)
\(\Rightarrow\dfrac{9797}{1000}< x< \dfrac{87360}{1000}\)
Vậy \(x\in\left(\dfrac{9797}{1000};\dfrac{87360}{1000}\right)\)
tìm y:
a) (y + 5) x 2020 = (200 + 5) x 2020
b) y - 45600 = (2019 - 419) x 4 x 25
a) (y + 5) x 2020 = 205 x 2020
(y + 5) x 2020 = 414100
y + 5 = 414100 : 2020 = 205
y = 205 - 5 = 200
a) y= 200
b) y-45600 = 1600 × 4 ×25
y-45600=160000
y= 114400
b) y - 45600 = (2019 - 419) x 4 x 25
y - 45600 = 1600 x 100
y - 45600 = 160000
y = 160000 + 45600 = 205 600
97/20 - ( 25/8 - 221/200 )< x < 91/10 - (137/20 - 11/4)
phần mik gửi vừa nãy là vt nhầm , nên mik gửi lại
tim x
[x-128+20] : 192= 0
x:15 +42 = 13 + 25 =0
460 +85 . 4 = [ x + 200 ] . 4
1)[x-128+20] :192=0
x-128+20 = 192
x-128 = 192-20
x-128 = 172
x = 172+128
x = 300
2) bạn nhớ check lại câu này giùm Nhi nha!
3) 460+85.4 = [ x+200] .4
460+ 340 = 4x+ 800
4x+800 = 800
4x = 800-800
4x = 0
x = 0:4
x = 0
bạn nhai ơi ban giải thích cho mình câu a đc ko vì sao lại bằng 192 chả nhẽ ko nhân hay làm gì với số ko ạ