tìm x biết 11+13+...+x=2376
tính bằng cách thuận tiện nhất:a) (77,63 + 567,89+222,37)x01
b) tìm x biết:
1624 x X + X x 2376=2,8
giải hộ mình nhanh nha
Tìm số nguyên x biết: 11-(13-x)=(13-11)
11-(13-x)=(13-11)
=>11-13+x=2
=>x-2=2
=>x=4
Tìm x biết : x+2/10^10+x+2/11^11=x+2/12^12+x+2/13^13
Tìm x
a, 2376 + x = 1254 × 4
b, (234 + x) × 2 = 4168
c, 2312 - x = 1684∶2
d, (x - 1284) ∶ 4 = 1264
Tìm x , biết
(x-11/14) - (x-13/12 )=(x-14/11) + (x-12/13)
tìm x biết
11/13 - ( 5/42 - x ) = - ( 15 - 11/13 )
11/12-(5/42-x)=-(15-11/13)
=>11/13-(5/42-x)=184/13
=>5/42-x=11/13- (-184/13)
=>5/42-x=15
=>x=5/42-15
=>x=-625/42
5/42-x=11/13- [-(15-11/13)]=11/13+15-11/13
5/42-x=(11/13-11/13)+15=15
x=5/42-15=5/42-630/42
x=-625/42
Vậy x=-625/42
Tìm x biết
x+2/10^10+x+2/11^11=x+2/12^12+x+2/13^13
Tìm x, biết:
11/13 - (5/42 - x) = - (15/28 -11/13)
mong mọi người giúp :)
\(\frac{11}{13}-\left(\frac{5}{42}-x\right)=-\left(\frac{15}{28}-\frac{11}{13}\right)\)
\(\frac{11}{13}-\frac{5}{42}+x=-\frac{15}{28}+\frac{11}{13}\)
\(\frac{-5}{42}+x=-\frac{15}{28}+\left(\frac{11}{13}-\frac{11}{13}\right)\)
\(\frac{-5}{42}+x=-\frac{15}{28}\)
\(x=-\frac{15}{28}+\frac{5}{42}\)
\(x=-\frac{45}{84}+\frac{10}{84}\)
\(x=-\frac{35}{84}\)
Vậy \(x=-\frac{35}{84}\).
\(\frac{11}{13}-\left(\frac{5}{42}-x\right)=\frac{113}{364}\)
\(\left(\frac{5}{42}-x\right)=\frac{11}{13}-\frac{113}{364}\)
\(\left(\frac{5}{42}-x\right)=\frac{15}{28}\)
\(x=\frac{5}{42}-\frac{15}{28}\)
\(x=-\frac{5}{12}\)
vậy \(x=-\frac{5}{12}\)
Bài làm :
Ta có :
\(\frac{11}{13}-\left(\frac{5}{42}-x\right)=-\left(\frac{15}{28}-\frac{11}{13}\right)\)
\(\Leftrightarrow\frac{11}{13}-\left(\frac{5}{42}-x\right)=\frac{113}{364}\)
\(\Leftrightarrow\frac{5}{42}-x=\frac{11}{13}-\frac{113}{364}\)
\(\Leftrightarrow\frac{5}{42}-x=\frac{15}{28}\)
\(\Leftrightarrow x=\frac{5}{42}-\frac{15}{28}=-\frac{5}{12}\)
Chúc bạn học tốt !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Tìm x biết (x+1)/10+(x+1)/11+(x+11)/12=(x+1)/13+(x+1)/14
\(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}-\frac{x+1}{13}-\frac{x+1}{14}=0\)
\(\left(x+1\right)\left(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}\right)=0\)
=> x + 1 = 0 ( vì 1/10 + 1/11 + 1/12 - 1/13 - 1/14 khac 0 )
=> x = -1