Tìm X X x 5 + X =120
Tìm x, biết:
a) 120 - 20 : x = 110
b) 213 - ( x - 13 ) = 1442 : 14
c) 2550 : [ 120 - ( x - 5 ) ] = 25
a) 120 - 20 : x = 110
20:x= 120 - 110
20:x= 10
x= 20:10=2
b) 213 - ( x - 13 ) = 1442 : 14
213 - (x-13)=103
x-13= 213 - 103
x-13=110
x=110+13
x=123
c) 2550 : [ 120 - ( x - 5 ) ] = 25
120 - (x-5) = 2550:25
120 - (x-5)=102
x-5 = 120 - 102
x-5= 18
x=18+5
x=23
a,120-20:X=110
20:X=120-110
20:X=10
X=20:10
X=2
b, 213-[X-13]=1442:14
213-[x-13]=103
x-13=213-103
x-13=110
x=110+13
x=123
c,2550:[120-{x-5}]=25
120-{x-5}=2550:25
120-x-5=102
x-5=120-102
x-5=18
x=18+5
x=23
Tìm x, biết:
a) x - 120: 30 = 40;
b) (x + 120) : 20 = 8;
c) (x + 5). 3 = 300;
d) x.2 + 21 : 3= 27
a) x = 44.
b) x = 40.
c) x = 95.
d) x = 10.
a) x - 120: 30 = 40
x -40 =40
x =40+40
x =80
b) (x + 120) : 20 = 8
(x+ 120) = 8x20
x+120 =160
x = 160-120
x = 40
c) (x + 5). 3 = 300
x+5=300:3
x+5=100
x=100-5
x=95
d) x.2 + 21 : 3= 27
x.2 +7=27
x.2 = 27-7
x.2= 20
x=20:2
x=10
Tìm x: 720 :[ 41 - (2 x X : 5) ] = 120
\(720:\left[41-\left(2.x:5\right)\right]=120\)
\(\left[41-\left(2.x:5\right)\right]=720:120\)
\(41-\left(2.x:5\right)=6\)
\(2.x:5=41-6\)
\(2.x:5=35\)
\(2.x=35.5\)
\(2.x=175\)
\(x=\dfrac{175}{2}\)
(x-42)-17=127 (tìm x) x_x
23(x+1)=69(tìm x)x_x
2.x+5=120:2(tìm x) x_x
5.x-2=613(tìm x) x_x
(x-42) - 17 = 127
=> x - 42 = 127 + 17 = 144
=> x = 144 + 42 = 186
23(x+1) = 69
=> x + 1 = 69 : 23 = 3
x = 3 - 1 = 2
2x + 5 = 120 : 2 = 60
=> 2x = 60 - 5 = 55
x = 55 : 2 = 27,5
5x - 2 = 613
=> 5x = 613 + 2 = 615
x = 615 : 5 = 123
a)(x-42)-17=127
(x-42)=127+17
(x-42)=144
x=144+42
x=186
b)23(x+1)=69
(x+1)=69:23
(x+1)=3
x=3-1
x=2
c)2.x+5=120:2
2.x+5=60
2.x=60-5
2.x=55
x=55:2
x=27,5
d)5.x-2=613
5.x=613+2
5.x=615
x=615:5
x=123
(x-42)-17=127(tim x)xx
23(x+1)=69(timx)xx
2x+5=120:2(Timx)xx
5x-2=613(timx)xx
Tìm X
X : 8 x 32 + X : 3 x 18 - X : 5 x 10 = 120
X : 8 x 32 + X : 3 x 18 - X : 5 x 10 = 120
X : (32 :8 ) + X : ( 18 :3 ) - X : ( 10 : 5 )
X = ( 4 +6 -2 )=120
X= 8 = 120
X=120 :8
X = 15
\(x\div8\times32+x\div3\times18-x\div5\times10=120\)
\(x\div\left(8\div32\right)+x\div\left(3\div18\right)-x\div\left(5\div10\right)=120\)
\(x\div\frac{1}{4}+x\div\frac{1}{6}-x\div\frac{1}{2}=120\)
\(x\div\left(\frac{1}{4}+\frac{1}{6}-\frac{1}{2}\right)=120\)
\(x\div\frac{-1}{12}=120\)
\(x=120\times\frac{-1}{12}\)
\(x=-10\)
Tìm x ,biết: 120 -5(30 - x)=5
120-5(30-x)=5
5(30-x)=120-5
5(30-x)=115
30-x=115:5
30-x=23
x=30-23
x=7
ai thấy đún tick mình nha
Tìm x, biết:
a) x - 280: 35 - 5.54;
b) ( x - 120) : 35 = 5;
c) (x + 100). 4 = 800;
d) x . 5 + 10.9 = 990
a) x = 278.
b) x = 295.
c) x = 100.
d) x = 180.
Tìm x, biết:
a) x - 280: 35 - 5.54;
b) ( x - 120) : 35 = 5
c) (x + 100). 4 = 800;
d) x . 5 + 10.9 = 990
a) x = 278.
b) x = 295.
c) x = 100.
d) x = 180
Câu 1 : 14:x+0,16/x+5=12 Tìm X
Câu 2 : 120: x+13/x=60 Tìm X