Lần sau ghi đề rõ ra nhé:

a) 6^x + 99 = 20^y​

\(\Leftrightarrow105=20^y\) , mà:

105 : 20 = 5,25 = 5 \(\Rightarrow\orbr{\begin{cases}y=5\\x=5-\left(20:10\right)=3\end{cases}}\)   (ở đây   20 : 10  số 20 thực ra là 20^y nhưng trong này ta không tính số mũ nên mình bỏ)

b) \(2n+9⋮n+1\)

\(\Rightarrow\left(2n-1\right)+9⋮n\). Thử lần lượt các số từ 1 - 9. Ta có :

Cứ thử lần lượt như vậy đến 9. Ta có:

\(\Rightarrow n=1\)

Sai thì thôi nhé! Vì mk không chắc đâu! với lại câu trả lời của mình đang chờ duyệt

B) (2n+9)\(⋮\)(n+1)

(2n+9)=2(n+1)+8

2(n+1)+8\(⋮\)(n+1)(1)

2(n+1)\(⋮\)(n+1)(2)

Từ(1)(2)\(\Rightarrow\)8\(⋮\)(n+1)

\(\Rightarrow\)(n+1) \(\in\)Ư(8)

\(\Leftrightarrow\)(n+1)\(\in\){1,2,4,8}

TH1:(n+1) =1\(\Rightarrow\)n=0

TH2:(n+1)=2\(\Rightarrow\)n=1

TH3:(n+1)=4\(\Rightarrow\)n=3

TH4:(n+1)=8\(\Rightarrow\)n=7

\(\Rightarrow\)n\(\in\){0,1,3,7}

kb vs mk nha

\(a,\)\(9-25=\left(7-x\right)-\left(25+7\right)\)

\(-16=\left(7-x\right)-32\)

\(7-x=-16+32\)

\(7-x=16\)

\(x=7-16=-9\)

\(b,-7624+\left(1543+7624\right)-x=25\)

\(-7624+9167-x=25\)

\(1543-x=25\)

\(x=1543-25\)

\(x=1518\)

\(c,\left(27-514\right)-\left(486-73\right)+x=7\)

\(-487-413+x=7\)

\(-900+x=7\)

\(x=7+900\)

\(x=907\)

 từ đề suy ra 7x-7+3x-6=-3

suy ra 10x-13+3=0

suy ra 10x-10=0

suy ra 10x=10

suy ra x=1

\(7\left(x-1\right)+3.\left(x-2\right)=-3\)

\(\Rightarrow7x-7+3x-6=-3\)

\(\Rightarrow\left(7x+3x\right)+\left(-7-6\right)=-3\)

\(\Rightarrow10x-13=-3\)

\(\Rightarrow10x=10\)

\(\Rightarrow x=1\)

Vậy x=1.

_Học tốt_

7. ( x - 1)+ 3 . ( x - 2 ) = -3

7x - 7 + 3x - 6= -3

7x +3x = -3 +7+6

10x =10

x = 10:10

x= 1

x=5 

y=3

X=1

Y=-6

x=2

y=3

\(\frac{1}{3.5}+\frac{1}{5.7}+\frac{1}{7.9}+...+\frac{1}{\left(2x+1\right).\left(2x+3\right)}=\frac{15}{93}\)

\(2.\left(\frac{1}{3.5}+\frac{1}{5.7}+\frac{1}{7.9}+...+\frac{1}{\left(2x+1\right).\left(2x+3\right)}\right)=2.\frac{15}{93}\)

\(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+...+\frac{2}{\left(2x+1\right).\left(2x+3\right)}=\frac{30}{93}\)

\(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{2x+1}-\frac{1}{2x+3}=\frac{10}{31}\)

\(\frac{1}{3}-\frac{1}{2x+3}=\frac{10}{31}\)

\(\frac{1}{2x+3}=\frac{1}{3}-\frac{10}{31}\)

\(\frac{1}{2x+3}=\frac{1}{93}\)

=> 2x + 3 = 93

=> 2x = 93 - 3

=> 2x = 90

=> x = 90 : 2

=> x = 45

Vậy x = 45

sai rồi

Đặt \(A=\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{\left(2x+1\right).\left(2x+3\right)}\)

\(2A=\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{\left(2x+1\right).\left(2x+3\right)}\)

\(2A=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{2x+1}-\frac{1}{2x+3}\)

\(2A=\frac{1}{3}-\frac{1}{2x+3}\)

\(A=\frac{2x}{3\left(2x+3\right)}:2\)

\(\Rightarrow\frac{2x}{3\left(2x+3\right)}:2=\frac{15}{93}\)

\(\frac{2x}{3\left(2x+3\right)}=\frac{15}{93}.2=\frac{30}{93}=\frac{10}{31}\)

\(\frac{2x}{6x+9}=\frac{10}{31}\)

\(\Rightarrow2x.31=10.\left(6x+9\right)\)

\(\Rightarrow62x=60x+90\)

\(62x-60x=90\)

\(2x=90\)

\(x=45\)

Vậy x = 45

Ủng hộ mk nha !!! ^_^

\(9-25=\left(7-x\right)-\left(25+7\right)\)

\(7-x-25-7=-16\)

\(0-x-25=-16\)

\(0-x=9\)

\(\Rightarrow x=-9\)

9 - 25 = ( 7 - x ) - ( 25 + 7 )

-16   = ( 7 - x ) - 32

-16 + 32 =7 - x

\(9-25=\left(7-x\right)-\left(25+7\right)\Rightarrow-16=\left(7-x\right)-32\Rightarrow-\left(7-x\right)=-32+16\)

\(\Rightarrow-7+x=-16\Rightarrow x=-16+7\Rightarrow x=-9\)

Ta có : \(\frac{1}{2}.\frac{2}{3}.\frac{3}{4}......\frac{9}{10}=\frac{x}{2010}\)

=> \(\frac{1.2.3.....9}{2.3.4....10}=\frac{x}{2010}\)

=> \(\frac{1}{10}=\frac{x}{2010}\)

=> x = 2010/10

=> x = 201

5.3.8.9.3682=3976560(chú ý . là phép nhân)

x/3 + 1/3 . 3/8 = 3/4

=> x . 1/3 + 1/3 . 3/8 = 3/4

=> ( x + 3/8 ) . 1/3 = 3/4

=> x + 3/8 = 9/4

=> x = 15/8

7/9:1/3-x/3=7/12

=> 7/3 - x : 3 = 7/12

=> x : 3 = 7/3 - 7/12 = 7/4

=> x = 7/4 . 3

=> x = 21/4