\(842\times65+842\times36-842\)

=\(842\times\left(65-36-1\right)\)

=\(842\times100\)

=\(84200\)

= 842 . 65 + 842 . 36 - 842 .1

= 842 .( 65 + 36 - 1)

=842 . 100

= 84200

TL:

842 x 65 + 842 x 36 - 842

=842 x 65 + 842 x 36 - 842 x 1

=842 x ( 65 + 36 - 1)

=842 x 100

=84200

HT~

`A(x)=7x^3-5x^2-7x+3-7x^3+5x^2+17x+27`

`A(x)=(7x^3-7x^3)-(5x^2-5x^2)+(-7x+17x)+(3+27)`

`A(x)=10x+30`

Cho `A(x)=0`

`=>10x+30=0`

`=>10x=-30`

`=>x=-3`

Vậy nghiệm của đa thức `A(x)` là `x=-3`

Đặt \(A\left(x\right)=0\)

\(\rightarrow7x^3-5x^2-7x+3-7x^3+5x^2+17x+27=0\)

\(\Leftrightarrow10x+30=0\)

\(\Leftrightarrow10x=-30\)

\(\Leftrightarrow x=-3\)

Vậy \(x=-3\) là nghiệm của đa thức \(A\left(x\right)\)

A(x) = 7x³ - 5x² - 7x + 3 - 7x³ + 5x² +17x +27

= 10x + 30

đặt A(x) = 0

<=> 10x + 30 = 0

<=> 10x = -30

<=> x = -3

vậy x = -3 là nghiệm của A(x)

a) -2x - (x-17) = 34-(-x + 25)

-2x- x+17= 34+x-25

-2x-x-x= -17 +34-25

-4x = -8

x = 2

b)17x-(-16x-27) = 2x+43

17x + 16x + 27 = 2x + 43

17x + 16x -2x= -27 +43

31x= 26

x= 21/31

c)- 2x- 3(x-17) = 34- 2(-x + 25)

-2x - 3x + 51 = 34 + 2x -50

-2x - 3x -2x = -51 + 34 -50

-7x = -67

x = 67/7

d) 17x +3(-16x-37) = 2x+ 43 -4x

17x -48x -111 = 2x + 43 -4x

17x - 48x -2x + 4x = 111 -43

-29x = 68

x = -68/29

a) 6x - 35 + 5x - 21 = (6x + 5x) - (35 + 21) = 11x - 56 = 17x - 20 => 11x = 17x - 20 + 56 = 17x + 36

=> 36 = 11x - 17x = -6x => x = 36 : (-6) = -6

b) 5x + 35 - 4x - 27 = (5x - 4x) + (35 - 27) = x + 8 = 14x + 34 => x = 14x + 34 - 8 = 14x + 26

=> 26 = x - 14x = -13x => x = 26 : (-13) = -2

(6x+5x)+(-35-21)=17x-20

11x-56=17x-20

11x-17x=-20+56

-6x=36

x=36/-6

x=-6

vậy x=-6

a) \(6x-35+5x-21=17x-20\)

\(\Rightarrow6x-25+5x-21+20=17x\)

\(\left(6x+5x\right)+\left(20-25-21\right)=17x\)

\(11x+\left(-36\right)=17x\)

\(17x-11x=-36\)

\(6x=-36\)

\(x=\frac{-36}{6}=-6\)

Vậy \(x=-6\)

b) \(5x+35-4x-27=14x+34\)

\(\Rightarrow5x+35-4x-27-34=14x\)

\(\left(5x-4x\right)+\left(35-27-34\right)=14x\)

\(x+\left(-26\right)=14x\)

\(14x-x=-26\)

\(13x=-26\)

\(x=-\frac{26}{13}=-2\)

Vậy \(x=-2\)

49 (6x-12 ) = 0                                  17 (15x-45) =0                                      105 ( 17x-34 ) = 0                            57 ( 9x -27 ) = 0

6x -12 = 0                                         15x -45 = 0                                           17x - 34 = 0                                    9x - 27 = 0

6x = 12                                             15x = 45                                              17x = 34                                         9x = 27

x = 2                                                 x =3                                                     x = 2                                             x = 3

25 + ( 15 - x ) =30                                              3 ( x + 7 ) -15 =27

15 - x = 25                                                        3 ( x + 7 ) = 42                       ( k cho mình nhé )

      x = -10                                                        x + 7 = 14

                                                                              x = 7

\(B=\frac{1}{17}+\frac{7}{17\cdot27}+\frac{7}{27\cdot37}+...+\frac{7}{1997\cdot2007}\)

\(B=\frac{1}{17}+\frac{7}{10}\left(\frac{10}{17\cdot27}+\frac{10}{27\cdot37}+...+\frac{10}{1997\cdot2007}\right)\)

\(B=\frac{1}{17}+\frac{7}{10}\left(\frac{1}{17}-\frac{1}{27}+\frac{1}{27}-\frac{1}{37}+...+\frac{1}{1997}-\frac{1}{2007}\right)\)

\(B=\frac{1}{17}+\frac{7}{10}\left(\frac{1}{17}-\frac{1}{2007}\right)\)

\(B=\frac{1}{17}+\frac{7}{10}\cdot\frac{1990}{34119}\)

\(B=\frac{1}{17}+\frac{1393}{34119}\)

\(B=\frac{200}{2007}\)

\(c)\) \(C=\frac{\frac{2}{7}+\frac{2}{5}+\frac{2}{17}-\frac{2}{293}}{\frac{3}{7}+\frac{3}{5}+\frac{3}{17}-\frac{3}{293}}\)

\(C=\frac{2\left(\frac{1}{7}+\frac{1}{5}+\frac{1}{17}-\frac{1}{293}\right)}{3\left(\frac{1}{7}+\frac{1}{5}+\frac{1}{17}-\frac{1}{193}\right)}\)

\(C=\frac{2}{3}\)

Bạn Cô nàng Thiên Bình làm đúng hết òi =.= 

a=7.[1/8+1/27-1/49]

   ------------------------

11.[1/8+1/27-1/49]

=7/11

cau b,c tuong tu nha h mk   

a)\(A=\frac{\frac{7}{8}+\frac{7}{27}-\frac{7}{49}}{\frac{11}{8}+\frac{11}{27}-\frac{11}{49}}\)

\(A=\frac{7.\left(\frac{1}{8}+\frac{1}{27}-\frac{1}{49}\right)}{11.\left(\frac{1}{8}+\frac{1}{27}-\frac{1}{49}\right)}\).

\(A=\frac{7}{11}\)

b)\(B=\frac{\frac{8}{9}-\frac{8}{27}-\frac{8}{81}+\frac{8}{243}}{4-\frac{4}{3}-\frac{4}{9}+\frac{4}{27}}\)

\(B=\frac{\frac{8}{9}.\left(1-\frac{1}{3}-\frac{1}{9}+\frac{1}{27}\right)}{4.\left(1-\frac{1}{3}-\frac{1}{9}+\frac{1}{27}\right)}\)

\(B=\frac{8}{9}:4=\frac{2}{9}\)

c)\(C=\frac{\frac{2}{7}+\frac{2}{5}+\frac{2}{17}-\frac{2}{293}}{\frac{3}{7}+\frac{3}{5}+\frac{3}{17}-\frac{3}{293}}\)\(C=\frac{2.\left(\frac{1}{7}+\frac{1}{5}+\frac{1}{17}-\frac{1}{239}\right)}{3.\left(\frac{1}{7}+\frac{1}{5}+\frac{1}{17}-\frac{1}{239}\right)}\)

C=\(\frac{2}{3}\)

ko có đáp án đúng

Trần Quốc Quân /cảm ơn bạn/

Ko có đáp án đúng đâu