|9-7x|=5x-3

=> 9-7x=5x-3           hoặc 9-7x=-(5x-3)

=> -7x-5x=-3-9       hoặc  9-7x=-5x+3

=> -12x = -12           hoặc -7x+5x=3-9

=> x=1                     hoặc  -2x=-6 

                                hoặc  x=3

8x-|4x+1|=x+2

=> |4x+1|=8x-(x+2)

=> |4x+1|=8x-x-2

=> |4x+1|=7x-2

=> 4x+1=7x-2          hoặc 4x+1=-(7x-2)

=> 4x-7x=-2-1         hoặc 4x+1=-7x+2

=> -3x=-3                 hoặc 4x+7x=2-1

=> x=1                     hoặc 11x=1

                               hoặc  x=1/11

Happy birthday to you, my friend !!!

a,    x = -4

b,    x = 1

c,    x = 1/3

Bạn hãy vui vẻ trong ngày sinh nhật nhá ^_^"

a) |x - 5| - 2x = 3

| x - 5| = 3 + 2x

=> x - 5 = 3 + 2x hoặc x - 5 = -3 - 2x

=> -5 - 3 = 2x - x -5 + 3 = -2x - x

=> x = -8 -2 = -3x

=> x = 2/3

b) |2x - 1| + 3x = 1

|2x - 1| = 1 - 3x

=> 2x - 1 = 1 - 3x hoặc 2x - 1 = -1 + 3x

=> -1 - 1 = -3x - 2x -1 + 1 = 3x - 2x

=> -2 = -5x 0 = x

=> x = 2/5

c) | x - 5| = 3x - 2

=> x - 5 = 3x - 2 hoặc x - 5 = -3x + 2

=> -5 + 2 = 3x - x -5 - 2 = -3x - x

=> -3 = 2x -7 = -4x

=> x = -3/2 x = 7/4

d) |9 - 7x| = 5x - 3

=> 9 - 7x = 5x - 3 hoặc 9 - 7x = -5x + 3

=> 9 + 3 = 5x + 7x 9 - 3 = -5x + 7x

=> 12 = 12x 6 = 2x

=> x = 1 x = 3

d./9-7x/=5x-3 c./9-7x/=5x-3

\(\Rightarrow\) 9-7x=5x-3 \(\Rightarrow\)

9+3=5x+7x

12=(5+7)x

12=12x

vậy x=1

a , 5^-1 . 25^x = 125

\(\frac{1}{5}.25^x=125\)

\(25^x=125.5=625\)

\(25^x=25^2\)

x = 2

b , 5x - | 9 - 7x | = 3

Với x < \(\frac{9}{7}\)

9 - 7x < 0

| 9 - 7x | = - ( 9 - 7x ) = 7x - 9

5x - ( 7x - 9 ) = 3

5x - 7x + 9 = 3

-2x = -6

x = -6 : (-2 )

x = 3

Với x >= \(\frac{7}{9}\)

9 - 7x >= 0

| 9 - 7x | = 9 - 7x

5x - 9 - 7x = 3

-2x - 9 = 3

-2x = 3 + 9

-2x = 12

x = 12 : ( -2 ) = -6

\(a,=x^2-6x-x+6=\left(x-6\right)\left(x-1\right)\\ b,=x\left(x^2-4x+4\right)=x\left(x-2\right)^2\\ c,=x^3-x^2+2x^2-2x+2x-2=\left(x-1\right)\left(x^2+2x+2\right)\\ d,=x^2+2x+3x+6=\left(x+2\right)\left(x+3\right)\\ e,=x^2\left(x-6\right)+\left(x-6\right)=\left(x^2+1\right)\left(x-6\right)\\ f,=x^3\left(x^2+1\right)+\left(x^2+1\right)=\left(x^3+1\right)\left(x^2+1\right)\\ =\left(x+1\right)\left(x^2-x+1\right)\left(x^2+1\right)\)

a) \(x^2-7x+6\)

\(=x^2-x-6x+6\)

\(=x\left(x-1\right)-6\left(x-1\right)\)

\(=\left(x-6\right)\left(x-6\right)\)

a)x=-4

b)x=1

c)x=\(\frac{1}{3}\)1/3

kik cho mik rồi mik kik lại cho

a, (x-1)³=8

(x-1)³=2³    hoac      (x-1)³ =(-2)³

x-1=2                        x-1= -2

x=3                           x= -1

Vay x=3 hoac x= -1

a ) \(\left(x-1\right)^3=8\)

\(\Leftrightarrow\left(x-1\right)=\sqrt[3]{8}\)

\(\Leftrightarrow\left(x-1\right)=2\)

\(\Leftrightarrow x=3\)

Vậy \(x=3\) .

c

a/(x-1)^3=8

→(x-1)^3=2^3

x-1=2

x=2+1

x=3

Bài 3: 

a: \(x^2-16=\left(x-4\right)\cdot\left(x+4\right)\)

b: \(x^2+2x+1-y^2=\left(x+1+y\right)\left(x+1-y\right)\)

c: \(=\left(x-y\right)^2-4=\left(x-y-2\right)\left(x-y+2\right)\)