1. Tìm x biết
x.(4,6+0,6)=7,2-8,15
\(x.\left(4,6+\frac{3}{5}\right)=7,2-8,15\) \(\left(x-\frac{-7}{8}\right)+2,3=3,24\)
Tìm x, biết:
a) \(\left(x-\frac{-7}{8}\right)+2,3=3,24\) ; b) \(x.\left(4,6+\frac{3}{5}\right)=7,2-8,15\) ; c) |2x-3|+3=16 ; d) \(42+\frac{3}{7}.\left|3x-1\right|=12\)
e) \(\left(x-\frac{1}{2}\right).\left(1+5x\right)=0\) ; f) |2x-1|=|x+2| ; g) \(2.3^x.3^2=18\left(x\in N\right)\) ; h) \(\frac{x+2}{5}=\frac{2-3x}{3}\)
4,5-x+1,8=1,14
1,5-4,6+x=0,6
tìm x???
Tìm x :
a) 4,5 - x + 1,8 = 1,14
b) 1,5 - 4,6 + x = 0,6
a)4,5-x+1,8=1,14
4,5-x = 1,14+1,8
4,5-x = 2,94
x = 4,5-2.94 =1,56
Bài 2: Tìm x, biết:
a/ 1,5 - |x - 0,3| = 0
b/| 2𝑥+3|−24=−9
c/ |𝑥+13|—12=0
d/ (-4,6)+ x =(-3,5)
e/ |1,5𝑥|−|−0,6| = -2+|0,4|
d: Ta có: (-4,6)+x=-3,5
nên x=-3,5+4,6
hay x=1,1
a: Ta có: \(1.5-\left|x-0.3\right|=0\)
\(\Leftrightarrow\left|x-0.3\right|=1.5\)
\(\Leftrightarrow\left[{}\begin{matrix}x-0.3=1.5\\x-0.3=-1.5\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1.8\\x=-1.2\end{matrix}\right.\)
1,5- 4,6+ x = 0,6
1,5-4,6+x=0,6
-3,1+x=0,6
x=3,7
1,5 - 4,6 + x = 0,6
4,6 + x = 1,5 - 0,6
4,6 + x = 0,9
x = 0,9 - 4,6
x = -3,7
x chia hết cho 5
Tìm số nguyên x biết
x-1/8= 4/x-2
\(x-\dfrac{1}{8}=\dfrac{4}{x-2}\) hay \(x-\dfrac{1}{8}=\dfrac{4}{x}-2\) vậy bạn?
\(\dfrac{x-1}{8}=\dfrac{4}{x-2}\)
=>\(\dfrac{\left(x-1\right)\left(x-2\right)}{8.\left(x-2\right)}=\dfrac{4.8}{\left(x-2\right).8}\)
=>khử mẫu
=>(x-1)(x-2)=32
.......
Tìm x biết
x^2-3x^2+3x-1=-8
\(x^3-3x^2+3x-1=-8\)
\(\Leftrightarrow x-1=-2\)
hay x=-1
Tìm x, biết
x=7/25 + -1/5
x=5/11 + 4/-9
5/9 - x/-1=-1/3
\(x=\dfrac{7}{25}+\dfrac{-1}{5}=\dfrac{7}{25}-\dfrac{1}{5}=\dfrac{2}{25}.\\ x=\dfrac{5}{11}+\dfrac{4}{-9}=\dfrac{5}{11}-\dfrac{4}{9}=\dfrac{1}{99}.\\ \dfrac{5}{9}-\dfrac{x}{-1}=\dfrac{-1}{3}\Leftrightarrow\dfrac{5}{9}+x=-\dfrac{1}{3}.\Leftrightarrow x=-\dfrac{8}{9}.\)
\(x=\dfrac{7}{25}+-\dfrac{1}{5}=>\dfrac{7}{25}+-\dfrac{5}{25}=>x=\dfrac{2}{25}\)
\(x=\dfrac{5}{11}+\dfrac{4}{-9}=>\dfrac{-45}{-99}+\dfrac{44}{-99}=>x=\dfrac{-1}{-99}=\dfrac{1}{99}\)
\(\dfrac{5}{9}-\dfrac{x}{-1}=-\dfrac{1}{3}=>-\dfrac{1}{3}-\dfrac{5}{9}=>\dfrac{x}{-1}=-\dfrac{8}{9}=>x=-\dfrac{8}{9}\)
\(x=\dfrac{7}{25}+\dfrac{-1}{5}\\ \Rightarrow x=\dfrac{7}{25}+\dfrac{-5}{25}\\ \Rightarrow x=\dfrac{2}{25}\\ x=\dfrac{5}{11}+\dfrac{4}{-9}\\ \Rightarrow x=\dfrac{-45}{-99}+\dfrac{44}{-99}\\ \Rightarrow x=\dfrac{45}{99}+\dfrac{44}{99}\\ \Rightarrow x=\dfrac{95}{99}\\ \dfrac{5}{9}-\dfrac{x}{-1}=\dfrac{-1}{3}\\ \Rightarrow\dfrac{x}{-1}=\dfrac{5}{9}-\dfrac{-1}{3}\\ \Rightarrow\dfrac{x}{-1}=\dfrac{5}{9}-\dfrac{-3}{9}\\ \Rightarrow\dfrac{x}{-1}=\dfrac{8}{9}\Rightarrow x\cdot9=-1\cdot8=-8\\ \Rightarrow x\cdot9=-8\\ \Rightarrow x=\dfrac{-8}{9}\)