\(=\text{201553920}\)

ai trả lời giùm mình câu hỏi này đi ai đang online thì giúp với chiều nay mình đi kiểm tra rồi help me

x + x : 0,2 = 1,35
x * 1 + x * 5 = 1,35
x * ( 1 + 5 ) = 1,35
x * 6 = 1,35
x = 1,35 : 6
x = 0,225

hok tốt nha ^_^

\(\left(\frac{4}{3}\right)^{2018}:\left(\frac{16}{9}\right)^{1008}-x=0,6^3:0,2^3\)

\(\Leftrightarrow\left[\left(\frac{4}{3}\right)^2\right]^{1009}:\left(\frac{16}{9}\right)^{1008}-x=27\)

\(\Leftrightarrow\left(\frac{16}{9}\right)^{1009}:\left(\frac{16}{9}\right)^{1008}-x=27\)

\(\Leftrightarrow\frac{16}{9}-x=27\)

\(\Leftrightarrow x=\frac{-227}{9}\)

Vậy x = \(\frac{-227}{9}\)

 a) x + x : 4 *1,6 + x : 6*3,6 = 222

\(\Rightarrow x+x\cdot0,4+x.0,6=222\)

\(\Rightarrow x.\left(1+0,4+0,6\right)=222\)

\(\Rightarrow x.2=222\)

\(\Rightarrow x=222:2=111\)

b) \(\left(x+0,2\right)+\left(x+0,4\right)+...+\left(x+1\right)=9,6\)

\(\Rightarrow\left(x+x+x+x+x\right)+\left(0,2+0,4+0,6+0,8+1\right)\) =9,6

\(\Rightarrow5.x+\left[\left(1-0,2\right):0,2+1\right].\left(1+0,2\right):2\) = 9,6

\(\Rightarrow5.x+3=9,6\)

\(\Rightarrow5.x=9,6-3=6,6\)

\(\Rightarrow x=6,6:5=1,32\)

(x+0,2)+(x+0,4)+(0,6)+(0,8)+(x+1)=9,6

5x+(0,2+0,4+0,6+0,8+1)=9,6

5x+3=9,6

5x     =9,6-3

5x      =6,6

  x      =6,6:5

  x       =1,32

a) kq = 111

b) kq = 1,32

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a) \(\dfrac{\left(0,6\right)^5}{\left(0,2\right)^6}=\dfrac{\left(0,2.3\right)^5}{\left(0,2\right)^5.\left(0,2\right)}=\dfrac{\left(0,2\right)^5.3^5}{\left(0,2\right)^5.\left(0,2\right)}=\dfrac{3^5}{0,2}=\dfrac{243}{0,2}=1215\)

c) \(2:\left(\dfrac{1}{2}-\dfrac{2}{3}\right)^2=2:\left(\dfrac{3}{6}-\dfrac{4}{6}\right)^2=2:\left(-\dfrac{1}{6}\right)^2=2:\dfrac{1}{36}=72\)

a: \(\Leftrightarrow x^2=900\)

=>x=30 hoặc x=-30

b: \(\Leftrightarrow\dfrac{2}{3}:\left(-0.1x\right)=\dfrac{4}{3}:\dfrac{-2}{25}=-\dfrac{4}{3}\cdot\dfrac{25}{2}=-\dfrac{100}{6}=\dfrac{-50}{3}\)

=>0,1x=2/3:50/3=2/3x3/50=1/25

=>1/10x=1/25

hay x=1/25:1/10=10/25=2/5

d: \(\Leftrightarrow x^2=\dfrac{144}{25}\)

=>x=12/5 hoặc x=-12/5

b: \(x+\dfrac{5}{6}=\dfrac{3}{8}\)

=>\(x=\dfrac{3}{8}-\dfrac{5}{6}\)

=>\(x=\dfrac{9}{24}-\dfrac{20}{24}=-\dfrac{11}{24}\)

c: \(\dfrac{2}{3}x-\dfrac{1}{2}=\dfrac{5}{6}\)

=>\(\dfrac{2}{3}x=\dfrac{5}{6}+\dfrac{1}{2}=\dfrac{8}{6}=\dfrac{4}{3}\)

=>2x=4

=>x=4/2=2

d: \(\dfrac{x}{7}=\dfrac{6}{-21}\)

=>\(\dfrac{x}{7}=\dfrac{-2}{7}\)

=>x=-2

e: \(\left(\dfrac{7}{3}x-0,6\right):\dfrac{3^2}{5}=1\)

=>\(\dfrac{7}{3}x-0,6=\dfrac{3^2}{5}=1,8\)

=>\(\dfrac{7}{3}x=2,4\)

=>\(x=2,4:\dfrac{7}{3}=2.4\cdot\dfrac{3}{7}=\dfrac{7.2}{7}=\dfrac{36}{35}\)

f: \(\dfrac{x}{45}=\dfrac{5}{6}+\dfrac{-29}{30}\)

=>\(\dfrac{x}{45}=\dfrac{25}{30}-\dfrac{29}{30}=-\dfrac{4}{30}=-\dfrac{2}{15}\)

=>\(x=-\dfrac{2}{15}\cdot45=-6\)

g: \(\left(4,5-2x\right)\cdot\left(-\dfrac{1^4}{7}\right)=\dfrac{11}{14}\)

=>\(4,5-2x=\dfrac{11}{14}:\dfrac{-1}{7}=\dfrac{-11}{2}\)

=>\(2x=4,5+\dfrac{11}{2}=\dfrac{20}{2}=10\)

=>x=10/2=5

h: \(-\dfrac{2}{7}+\dfrac{4}{7}x=\dfrac{5}{7}\)

=>\(\dfrac{4}{7}x=\dfrac{5}{7}+\dfrac{2}{7}=\dfrac{7}{7}\)

=>4x=7

=>\(x=\dfrac{7}{4}\)