1,

a,=4/7:4/9.3

=9/7.3

=27/7

b,=(7/11+4/11).5/6

=1.5/6

=5/6

`(6/7-2/7):4/9xx3=4/7xx9/4xx3=[4xx9xx3]/[7xx4]=27/7`

`7/11xx5/6+4/11xx5/6=(7/11+4/11)xx5/6=11/11xx5/6=5/6`

2/5+11/9+3/5+7/9= (2/5+3/5)+(11/9+7/9)                             = 1+2                             = 3

9/5 + 4/7 + 6/5 + 3/7

=  ( 9/5 + 6/5 ) + ( 4/7 + 3/7)

=            3        + 1

=        4

9/5 + 4/7 + 6/5 + 3/7 = (9/5 + 6/5) + (4/7 + 3/7)

= 15/5 + 7/7

= 3 + 1

= 4

1/2 x 45/33 x 1/9 x 11/6 = (1/2 x 1/9) x (45/33 x 11/6)

= 1/18 x 45/18

= 5/2

1/2 x 45/33 x 1/9 x 11/6

= (1/2 x 1/9) x (45/33 x 11/6)

= 1/18 x 45/18

= 5/2

a, (6/11+5/11)x3/17

c1:=1x3/17

    =3/17

c2:=6/11x3/17+5/11x3/17

    =18/197+15/187

    =33/187

    =3/17

b,3/5x7/9-3/5x2/9

c1:=21/45-6/45

=15/45

=1/3

c2:=3/5x(7/9-2/9)

=3/5x5/9

=1/3

c,( 6/7-4/7):2/5

c1:=2/7:2/5

=2/7x5/2

=5/7

c2,6/7:2/5-4/7:2/5

=6/7x5/2-4/7x5/2

=15/7-10/7

=5/7

d,8/15:2/11+7/15:2/11

c1:=(8/15+7/15):2/11

=1x11/2

=11/2

c2:=8/15x11/2+7/15x11/2

=88/30+77/30

=165/30

=11/2

a) (\(\frac{6}{11}\) + \(\frac{5}{11}\)) x \(\frac{3}{17}\)=  \(\frac{11}{11}\) x \(\frac{3}{17}\)= \(1\) x\(\frac{3}{17}\)= \(\frac{3}{17}\)

b) \(\frac{3}{5}\)x\(\frac{7}{9}\)- \(\frac{3}{5}\)x \(\frac{2}{9}\) = \(\frac{3}{5}\)x (\(\frac{7}{9}\)- \(\frac{2}{9}\))= \(\frac{3}{5}\) x  \(\frac{5}{9}\)= \(\frac{3}{9}\)

c) (\(\frac{6}{7}\)- \(\frac{4}{7}\)) : \(\frac{2}{5}\)= \(\frac{2}{7}\) x \(\frac{5}{2}\)= \(\frac{5}{7}\)

d) \(\frac{8}{15}\) : \(\frac{2}{11}\) + \(\frac{7}{15}\): \(\frac{2}{11}\)=  ( \(\frac{8}{15}\)+ \(\frac{7}{15}\)) x \(\frac{11}{2}\)= 1 x \(\frac{11}{2}\)= \(\frac{11}{2}\)

Chúc học tốt nha!

a,3/17

b,1/3

c,5/7

d,11/2

chúc bạn hk tốt nhé(nhớ k cho tiu)

nhiều thế ren giải được ma bik giải xng rồi có dc chi hông?

giải đc k mà

nhiều quá

a: \(=\dfrac{7\cdot5+3\cdot9}{45}\cdot\dfrac{2}{3}=\dfrac{62}{45}\cdot\dfrac{2}{3}=\dfrac{124}{135}\)

b: \(=\dfrac{6}{11}\cdot\dfrac{5}{7}=\dfrac{30}{77}\)

c: \(=\dfrac{7}{8}\cdot\dfrac{8-3}{9}=\dfrac{7}{8}\cdot\dfrac{5}{9}=\dfrac{35}{72}\)

yyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyy

\(\text{#TNam}\)

`a, (7/9+3/5) \times 2/3`

`C1:`

`=62/45 \times 2/3`

`= 124/135`

`C2:`

`= 7/9 \times 2/3 + 3/5 \times 2/3`

`= 14/27 +2/5`

`= 124/135`

`b, `

`C1:`

`= 6/11 \times 5/7`

`=`30/77`

`C2:

`= 9/11 \times 5/7-3/11 \times 5/7`

`= 45/77 -15/77`

`= 30/77`

`c,`

`C1:`

`= 7/8 \times 5/9`

`=35/72`

`C2:`

`= 7/8 \times 8/9- 7/8 \times 1/3`

`= 7/9-7/24`

`=35/72`