(-100):(x+5)=-5

x+5=-100:(-5)

x+5=20

x=20-5

x=15

=> -5(x+5)=-100

=>x+5=20

=>x=20-5=15

Vậy x=15

thấy đúng thì k hộ chị nha,chúc e học tốt

Đề trước đó: 

(x-7)(x+1)-(x-3)^2=(3x-5)(3x+5)-(3x+1)^2+(x-2)^2-x

<=>x^2+x-7x-7-x^2+6x-9=9x^2-25-9x^2-6x-1+x^2-4x+4-x

<=>x^2-11x-6=0

<=>x^2-2x. 11/2 + 121/4-145/4=0

<=>(x-11/2)^2=145/4

<=>|x-11/2|=căn(145)/2

<=>x=[11+-căn(145)]/2

Ta có: \(\left(3x-1\right)\left(2x+7\right)-\left(x+1\right)\left(6x-5\right)=\left(x+2\right)-\left(x-5\right)\)

\(\Leftrightarrow6x^2+21x-2x-7-6x^2+5x-6x+5=x+2-x+5\)

\(\Leftrightarrow18x-2=7\)

\(\Leftrightarrow18x=9\)

hay \(x=\dfrac{1}{2}\)

Nhanh giúp mình với mn

Tìm x hả?

8/x+1/5=2/5+1/3.

8/x+1/5=11/15

x=11/15-1/5

x=8/15

3/25 x ( 15/7 - 2/7 ) + 3/7 x 1/25 

= 3/25 x 13/7 + 3/7 x 1/25 

= (3 x 13/7 + 3/7 ) x 1/25 

= 42/7 x 1/25 

= 6 x 1/25 

= 6/25

\(\dfrac{3}{25}\times\dfrac{15}{7}+\dfrac{3}{7}\times\dfrac{1}{25}-\dfrac{2}{7}\times\dfrac{3}{25}\)

\(=\dfrac{3}{25}\times\left(\dfrac{15}{7}-\dfrac{2}{7}\right)+\dfrac{3}{7}\times\dfrac{1}{25}\)

\(=\dfrac{3}{25}\times\dfrac{13}{7}+\dfrac{3}{7}\times\dfrac{1}{25}\)

\(=\dfrac{3\times13}{25\times7}+\dfrac{3\times1}{7\times25}\)

\(=\dfrac{39}{175}+\dfrac{3}{175}\)

\(=\dfrac{39+3}{175}\)

\(=\dfrac{42}{175}\)

\(=\dfrac{6}{25}\)

A = \(\dfrac{3}{25}\) \(\times\) \(\dfrac{15}{7}\) + \(\dfrac{3}{25}\) \(\times\) \(\dfrac{1}{7}\) - \(\dfrac{2}{7}\times\) \(\dfrac{3}{25}\)

A = \(\dfrac{3}{25}\) \(\times\)( \(\dfrac{15}{7}\) + \(\dfrac{1}{7}-\dfrac{2}{7}\))

A = \(\dfrac{3}{25}\) \(\times\) \(\dfrac{14}{7}\)

A = \(\dfrac{6}{25}\)

\(\Leftrightarrow\frac{5}{7}+\left|\frac{1}{2}-x\right|=\frac{11}{4}\)

\(\Leftrightarrow\left|\frac{1}{2}-x\right|=\frac{11}{4}-\frac{5}{7}=\frac{77-20}{28}=\frac{57}{28}\)

\(\Leftrightarrow\orbr{\begin{cases}\frac{1}{2}-x=\frac{57}{28}\\\frac{1}{2}-x=-\frac{57}{28}\end{cases}}\)\(\Leftrightarrow\orbr{\begin{cases}x=\frac{1}{2}-\frac{57}{28}=\frac{14-57}{28}=\frac{-43}{28}\\x=\frac{1}{2}+\frac{57}{28}=\frac{14+57}{28}=\frac{71}{28}\end{cases}}\)

PT có 2 nghiệm là: -43/28 và 71/28

TH1 : \(x< \frac{1}{2}\), ta có:

\(-\frac{5}{7}-\left(\frac{1}{2}-x\right)=-\frac{11}{4}\)

\(-\frac{5}{7}-\frac{1}{2}+x=-\frac{11}{4}\)

\(-\frac{17}{14}+x=-\frac{11}{4}\)

\(x=-\frac{11}{4}-\left(-\frac{17}{14}\right)\)

\(x=-\frac{43}{28}\)( thỏa mãn )

TH2 : \(x\ge\frac{1}{2}\); ta có:

\(-\frac{5}{7}-\left(x-\frac{1}{2}\right)=-\frac{11}{4}\)

\(-\frac{5}{7}-x+\frac{1}{2}=-\frac{11}{4}\)

\(-\frac{3}{14}-x=-\frac{11}{4}\)

\(x=-\frac{3}{14}-\left(-\frac{11}{4}\right)\)

\(x=\frac{71}{28}\)(thỏa mãn)

Vậy \(\orbr{\begin{cases}x=\frac{-43}{28}\\x=\frac{71}{28}\end{cases}}\)