A=101+100+99+98+....+3+2+1/101-100+99-98+...+3-2+1
B=423134.846267-423133/423133.846267+423134
Những câu hỏi liên quan
Tính
a, \(\frac{101+100+....+2+1}{101-100+99-98+...+3-2+1}\)
b, \(\frac{423134.846267-423133}{423133.846267+423134}\)
Tính
a, A=\(\frac{101-100+99-98+...+3-2+1}{101+100+99+98+...+3+2+1}\)
b, B=\(\frac{423133.846267+423134}{423134.846267-423133}\)
Tính:
a) A = \(\frac{101+100+99+98+...+3+2+1}{101-100+99-98+...+3-2+1}\)
b) B = \(\frac{423134.546267-423133}{423133.846267+423134}\)
tinh nhanh
a) A= 33(1-2/3)(1-2/5)...(1-2/99)
b) B=101+100+99+98+...+3+2+1/101-100+99-98+...+3-2+1
c) C=423134x846267-423133/423133x846267+423134
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a) A\(\frac{101+100+99+98+.....+3+2+1}{101-100+99-98+.....+3-2+1}\)
b) B=\(\frac{423134\cdot846267-423133}{423134\cdot846267-423134}\)
ai nhanh mình tích cho
Thực hiện phép tính
a) A= 33(1-2/3)(1-2/5)...(1-2/99)
b) B=101+100+99+98+...+3+2+1 / 101-100+99-98+...+3-2+1
c) C=423134x846267-423133 / 423133x846267+423134
Tính
a)A=101+100+99+98+…+3+2+
101-100+99+98+…+3-2+1
b)B=3737.43-4343.37
2+4+6+…+100
A=101+100+99+98+...+3+2+1/101-100+99-98+...+3-2+1
Lời giải:
Xét tử số:
$101+100+99+98+...+3+2+1=(101+1).101:2=5151$
Xét mẫu số:
$101-100+99-98+...+3-2+1$
$=(101-100)+(99-98)+...+(3-2)+1=\underbrace{1+1+....+1}_{50} +1=1.50+1=51$
Vậy $A=\frac{5151}{51}=101$
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A=101+100+99+98+...+3+2+1/101-100+99-98+...+3-2+1
B=3737.43/4343.37
\(A=\dfrac{101+100+99+98+...+3+2+1}{101-100+99-98+...+3-2+1}\\ A=\dfrac{\left[\left(101-1\right):1+1\right]\times\left(101+1\right):2}{1+1+...+1+1}\\ A=\dfrac{5151}{51}=101\\ B=\dfrac{3737.43}{4343.37}\\ B=\dfrac{37.101.43}{43.101.37}\\ B=1\)
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