2323/4545 = 2323 : 101/4545:101=23/45

đều chia cho 101 nhé

2323:101=23

4545:101=45

phân số còn:23/45

\(\frac{2323}{4545}\)=\(\frac{2323:101}{4545:101}\)=\(\frac{23}{45}\)

Kb vc mk nha !

Bài giải

a) Ta có : \(\frac{4545+101}{6969-303}=\frac{45.101+101}{69.101-101.3}=\frac{101.\left(45+1\right)}{101.\left(69-3\right)}=\frac{101.46}{101.66}=\frac{23}{33}\)

b) Ta có : \(\frac{2929-101}{2.1919+404}=\frac{29.101-101}{2.19.101+4.101}=\frac{101.\left(29-1\right)}{101.\left(19.2+4\right)}=\frac{28}{42}=\frac{2}{3}\)

a)\(\frac{4545+101}{6969-303}\)= \(\frac{\left(4545:45\right)+101}{\left(6969:69\right)-303}\)= \(\frac{101+101}{101-303}\)=\(\frac{202}{-202}\)=-1 

b)\(\frac{2929-101}{2.1919+404}\)= \(\frac{2929-101}{3838+404}\)=\(\frac{\left(2929:29\right)-101}{\left(3838:38\right)+404}\)=\(\frac{101-101}{101+404}\)=\(\frac{0}{505}\)=0

học tốt 

a)\(\frac{4545+101}{6969-303}=\frac{\left(4545:45\right)+101}{\left(6969:69\right)-303}=\frac{101+101}{101-303}=\frac{202}{-202}=-1\)

b)\(\frac{2929-101}{2.1919+404}=\frac{2929-101}{3838+404}=\frac{\left(2929:29\right)-101}{\left(3838:38\right)+404}=\frac{101-101}{101+404}=0\)

Học tốt

@@

./ có nghĩa là phần đó 

4545/3535=4545:505/3535:505=9/7

2323/6767=2323:101/6767:101=23/67

HT

\(\frac{4545}{3535}=\frac{9}{7}\)

\(\frac{6767}{2323}=\frac{67}{23}\)

rút gọn thành 9/7 và 23/67 nha.

\(1,\)Rút gọn : \(\frac{-24}{56};\frac{1212}{-4545}\)

\(\frac{-24}{56}=\frac{-24:8}{56:8}=\frac{-3}{7}\)

\(\frac{1212}{-4545}=\frac{1212:(-101)}{(-4545):(-101)}=\frac{-12}{45}=\frac{-4}{15}\)

Tự so sánh

\(\dfrac{4545}{3636}=\dfrac{4545:909}{3636:909}=\dfrac{5}{4}\)

4545/3636 = 5/4.

rút gọn thành phân số 5/4

a )   − 1212 − 2424 = ( − 1212 ) : ( − 1212 ) ( − 2424 ) : ( − 1212 ) = 1 2

b )   120120 − 240240 = 120120 : ( − 120120 ) − 240240 : ( − 120120 ) = − 1 2

c)  1313 − 1414 = 1313 : ( − 101 ) − 1414 : ( − 101 ) = − 13 14

\(A=\left(\dfrac{2-x}{2+x}-\dfrac{16}{4-x^2}-\dfrac{2+x}{2-x}\right)\)

\(\Rightarrow A=\left(\dfrac{\left(2-x\right)^2}{\left(2+x\right)\left(2-x\right)}-\dfrac{16}{\left(2+x\right)\left(2-x\right)}-\dfrac{\left(2+x\right)^2}{\left(2+x\right)\left(2-x\right)}\right)\)\(\Rightarrow A=\left(\dfrac{4-4x+x^2}{\left(2+x\right)\left(2-x\right)}-\dfrac{16}{\left(2+x\right)\left(2-x\right)}-\dfrac{4+4x+x^2}{\left(2+x\right)\left(2-x\right)}\right)\)

\(\Rightarrow A=\dfrac{4-4x+x^2-16-4-4x-x^2}{\left(2+x\right)\left(2-x\right)}\)

\(\Rightarrow A=\dfrac{-8x-16}{\left(2+x\right)\left(2-x\right)}\)

\(\Rightarrow A=\dfrac{-8\left(x+2\right)}{\left(2+x\right)\left(2-x\right)}\)

\(\Rightarrow A=\dfrac{-8}{2-x}\)

\(\Rightarrow A=\dfrac{8}{x-2}\)

a là:

      ( 7525 + 903 ) /2 = 4214

b là:

      7525 - 4214 = 3311

a/b là 4214/3311= 14/11

a + b = 7525 và b - a = 903 nên : a = ( 7525 - 903 ) : 2 = 3311

                                                    : b = 7525 - 331 = 4214

Vậy phân số đó là: 3311/4214 = 3311 : 301/4214 : 301 = 11/14

a là : (7525+903) : 2 = 4214

b là : 7525 - 4214 = 3311

a/b = 4214/3311 = 14/11