Ta có : \(A=\frac{1}{7}+\frac{1}{91}+\frac{1}{247}+...+\frac{1}{1147}\)

\(=\frac{1}{1\cdot7}+\frac{1}{7\cdot13}+\frac{1}{13\cdot19}+...+\frac{1}{31\cdot37}\)

\(=\frac{1}{6}\cdot\left(\frac{6}{1\cdot7}+\frac{6}{7\cdot13}+...+\frac{6}{31\cdot37}\right)\)

\(=\frac{1}{6}\cdot\left(1-\frac{1}{7}+\frac{1}{7}-\frac{1}{13}+...+\frac{1}{31}-\frac{1}{37}\right)\)

\(=\frac{1}{6}\cdot\left(1-\frac{1}{37}\right)\)

\(=\frac{1}{6}\cdot\frac{36}{37}=\frac{6}{37}\)

Vậy \(A=\frac{6}{37}\)

chắc bạn viết sai đầu bài rồi

A= 6/37

\(A=\frac{1}{7}+\frac{1}{91}+\frac{1}{247}+...+\frac{1}{1147}\)

\(A=\frac{1}{1.7}+\frac{1}{7.13}+\frac{1}{13.19}+....+\frac{1}{31.37}\)

\(A=\frac{6}{6}\left(\frac{1}{1.7}+\frac{1}{7.13}+\frac{1}{13.19}+...+\frac{1}{31.37}\right)\)

\(A=\frac{1}{6}\left(\frac{6}{1.7}+\frac{6}{7.13}+\frac{6}{13.19}+...+\frac{6}{31.37}\right)\)

\(A=\frac{1}{6}\left(1-\frac{1}{7}+\frac{1}{7}-\frac{1}{13}+\frac{1}{13}-\frac{1}{19}+....+\frac{1}{31}-\frac{1}{37}\right)\)

\(A=\frac{1}{6}\left(1-\frac{1}{37}\right)\)

\(A=\frac{1}{6}.\frac{36}{37}=\frac{6}{37}\)

\(A=\frac{1}{6}.\left(\frac{6}{1.7}+\frac{6}{7.13}+\frac{6}{13.19}+...+\frac{6}{31.37}\right)\)

    \(=\frac{1}{6}.\left(1-\frac{1}{7}+\frac{1}{7}-\frac{1}{13}+...+\frac{1}{31}-\frac{1}{37}\right)\)

    \(=\frac{1}{6}.\left(1-\frac{1}{37}\right)=\frac{1}{6}.\frac{36}{37}=\frac{6}{37}\)

A = \(\frac{1}{7}+\frac{1}{91}+\frac{1}{247}+...+\frac{1}{1147}\)

A = \(\frac{1}{1.7}+\frac{1}{7.13}+\frac{1}{13.19}+...+\frac{1}{31.37}\)

A = \(\frac{1}{6}.\left(1-\frac{1}{7}+\frac{1}{7}-\frac{1}{13}+\frac{1}{13}-\frac{1}{19}+...+\frac{1}{31}-\frac{1}{37}\right)\)

A = \(\frac{1}{6}.\left(1-\frac{1}{37}\right)\)

A = \(\frac{1}{6}.\frac{36}{37}=\frac{6}{37}\)

\(\dfrac{1}{7}+\dfrac{1}{91}+\dfrac{1}{247}+\dfrac{1}{475}+\dfrac{1}{775}+\dfrac{1}{1147}\)

\(=\dfrac{1}{1.7}+\dfrac{1}{7.13}+\dfrac{1}{13.19}+\dfrac{1}{19.25}+\dfrac{1}{25.31}+\dfrac{1}{31.37}\)

\(=\dfrac{1}{6}\left(1-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{13}+\dfrac{1}{13}-\dfrac{1}{19}+\dfrac{1}{19}-\dfrac{1}{25}+\dfrac{1}{25}-\dfrac{1}{31}+\dfrac{1}{31}-\dfrac{1}{37}\right)\)

\(=\dfrac{1}{6}\left(1-\dfrac{1}{37}\right)\)

\(=\dfrac{1}{6}.\dfrac{36}{37}\)

\(=\dfrac{6}{37}\)

\(#Wendy.Dang\)

#)Giải :

\(A=\frac{1}{7}+\frac{1}{91}+\frac{1}{247}+\frac{1}{475}+\frac{1}{775}+\frac{1}{1147}\)

\(A=\frac{1}{1.7}+\frac{1}{7.13}+\frac{1}{13.19}+\frac{1}{19.25}+\frac{1}{25.31}+\frac{1}{31.37}\)

\(A=1+\frac{1}{7}-\frac{1}{7}+\frac{1}{13}-\frac{1}{13}+\frac{1}{19}-\frac{1}{19}+\frac{1}{25}-\frac{1}{25}+\frac{1}{31}-\frac{1}{31}+\frac{1}{37}\)

\(A=\frac{1}{7}+\frac{1}{37}\)

\(A=\frac{44}{259}\)

   P/s : Đề bn ghi thiếu nha, còn có 1/475 nữa ( xem đầu phần giải của mình )

      #~Will~be~Pens~#

= 0,1621963429 tk m nhé

=0.1621963429

k mik nha

lôi cái máy tính cầm tay ra là giải đc ấy mà

1/7 +1/91 +1/247 + 1/475 + 1/775 + 1/1147 
Đặt A=1/7 +1/91 +1/247 + 1/475 + 1/775 + 1/1147 
A=1/(1.7)+1/(7.13)+1/(13.19)+...+1/(31... 
A=(1/6)x( 1 - 1/7 + 1/7 - 1/13 +... +1/31-1/37) 
A=(1/6)x(1-1/37) 
A=(1/6)x(36/37) 
A=6/37 

kết quả là 6/37

0,1621963429

= 6/37 nha

đúng 10000000000000000000000000% đó nếu có sai thì trách cái máy tính của mk nha vì k pải mk tính mờ là nó tính....

tk mk nha đg âm 439 kìa....

T_T

lấy máy tính mà tính

bằng 5/31 nha bạn