\(=\frac{1.2.4\left(1+2.2.2+4.4.4+8.8.8+16.16.16\right)}{1.3.4\left(1+2.2.2+4.4.4+8.8.8+16.16.16\right)}=\frac{2}{3}\)

1202 

8899

\(=\frac{2\left(4+2.2.8+4.4.16+8.8.32\right)}{3\left(4+2.2.8+4.4.16+8.8.32\right)}=\frac{2}{3}\)

thế thì có nhiều chi tiết bạn có thể giải hộ mình đc ko ?

Tí nữa có điện mình làm cho .-. 

ok bạn

2.4+2.4.8+ 4.8.16 + 8.16.32/ 3.4 + 2.6.8 + 4.12.16 + 8.24.32

= 2.4( 1+ 8+ 8.8 + 8.8.8) / 3.4(1+ 8 + 8.8 +8.8.8)

= 2.4/3.4

= 2/3

\(\frac{2.4+2.4.8+4.8.16+8.16.32}{3.4+2.6.8+4.12.16+8.24.32}\)

=\(\frac{4.2+2.8.2.2+4.16.4.2+8.32.8.2}{4.3+2.8.2.3+4.16.4.3+8.32.8.3}\)

=\(\frac{2.\left(4+2.8.2+4.16.4+8.32.8\right)}{3.\left(4+2.8.2+4.16.4+8.32.8\right)}\)

=\(\frac{2}{3}\)

Ủng hộ mik nhé !!!

Đặt biểu thức trên là A. Ta có:

A=\(\frac{2^3+2^6+2^9+2^{12}}{2^2.3+2^5.3+2^8.3+2^{11}.3}\)

 =\(\frac{2^3.\left(1+2^3+2^6+2^9\right)}{2^2.3.\left(1+2^3+2^6+2^9\right)}\)

= \(\frac{2^3}{2^2.3}\)

=\(\frac{2}{3}\)

\(\frac{2.4+2.4.8+4.8.16+8.16.32}{3.4+2.6.8+4.12.16+8.24.32}\)

\(=\frac{8+8.8+8.64+8.512}{12+12.8+12.64+8.\left(12.2\right).32}\)

\(=\frac{=8.\left(1+8+64+512\right)}{12.\left(1+8+64+12.16.32\right)}\)

\(=\frac{8.\left(1+8+64+512\right)}{12.\left(1+8+64\right)+12.512}\)

\(=\frac{8.\left(1+8+64+512\right)}{12.\left(1+8+64+512\right)}\)

\(=\frac{8}{12}\)

\(=\frac{2}{3}\)

\(\dfrac{\text{2.4 + 2.4.8 + 4.8.16 + 8.16.32 + 16.32.64 }}{3.4+2.6.8+4.12.16+8.24.32+16.48.64}\)

= \(\dfrac{2+4+8+16+32}{3+6+12+24+48}\)= \(\dfrac{2+2+2+2+2}{3+3+3+3+3}\)

= \(\dfrac{10}{15}\) = \(\dfrac{2}{3}\)

\(\dfrac{2.4+2.4.8+4.8.16+16.32.64}{3.4+2.6.8+4.12.16+8.24.32+16.48.64}\)

=\(\dfrac{8+64+512+4096+32768}{12+96+768+6144+49152}\)

=\(\dfrac{37448}{56172}\)=\(\dfrac{2}{3}\)