A=\(\frac{2017^{2017}+2}{2017^{2017}-1}\)=\(\frac{\left(2017^{2017}-1\right)+3}{2017^{2017}-1}\)=\(1\)+\(\frac{3}{2017^{2017}-1}\)

B=\(\frac{2017^{2017}}{2017^{2017}-3}\)=\(\frac{\left(2017^{2017}-3\right)+3}{2017^{2017}-3}\)=\(1\)+\(\frac{3}{2017^{2017}-3}\)

Vì \(2017^{2017}-1\)\(>\)\(2017^{2017}-3\)nên \(\frac{3}{2017^{2017}-1}\)\(< \)\(\frac{3}{2017^{2017}-3}\)=>  A<B

vậy A<B 

chúc bạn học giỏi

k giùm mk nhé

Vi \(\frac{2017^{2017}+1}{2017^{2018}+1}< 1\)

\(\Rightarrow A=\frac{2017^{2017}+1}{2017^{2018}+1}< \frac{2017^{2017}+1+2016}{2017^{2018}+1+2016}=\frac{2017^{2017}+2017}{2017^{2018}+2017}=\frac{2017\left(2017^{2016}+1\right)}{2017\left(2017^{2017}+1\right)}=\frac{2017^{2016}+1}{2017^{2017}+1}=B\)Vay A < B

id nhu 1 tro dua

Ta có: \(A=\frac{2^{2017}+2}{2^{2017}+3}=1-\frac{1}{2^{2017}+3}\)

        \(B=\frac{2^{2017}+1}{2^{2017}+2}=1-\frac{1}{2^{2017}+2}\)

Vì \(\frac{1}{2^{2017}+3}< \frac{1}{2^{2017}+2}\) nên \(1-\frac{1}{2^{2017}+3}>1-\frac{1}{2^{2017}+2}\)

hay A > B

A>B bạn nhé

a: 58/63=3190/3465

36/55=2268/3465

=>58/63>36/55

b: 27/53=1998/3922

36/74=1908/3922

=>27/53>36/74

a, Bn quy đồng rồi làm nha

b,Có  A=2017^2017+1/2017^2018+1

--> 2017A=2017^2018+2017/2017^2018+1

2017A=2017^2018+1/2017^2018+1 + 2016/2017^2018+1

2017A=1+ 2016/2017^2018+1

Có B=2017^2016+1/2017^2017+1

--> 2017B=2017^2017+2017/2017^2017+1

2017B=2017^2017+1/2017^2017+1 + 2016/2017^2017+1

2017B=1+2016/2017^2017+1

        Vì 1+2016/2017^2018+1 < 1+2016/2017^2017+1

nên 2017A<2017B

-->A<B

A.Ta có : 

\(A=-\frac{15}{46}>-\frac{15}{45}=-\frac{51}{153}>-\frac{51}{151}=B\)

\(\Rightarrow A>B\)

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