HELP ME.................!!!!!!!!!!
TÍNH :A=(1-1/2^2)(1-1/3^2)...(1-1/10^2)
B=1+1/2+1/2^2+1/2^3+...+1/2^2016
help me,please!=(((
1)tính hợp lí :
a/1/5-(1/2+3/4):5/2
b/1,5.(1/3-2/3)
c/9/10.23/11-1/11.9/10+9/10
a) 1/5 - (1/2 + 3/4 ) : 5/2
= 1/5 - ( 1/4 + 3/4 ) : 5/2
=1/5 - 1 : 5/2
= 1/5 - 1 . 2/5
= 1/5 - 2/5
= -1/5
b) 1,5 . (1/3 - 2/3)
=3/2 . ( -1/3)
=-1/2
c) 9/10 . 23/11 - 1/11 . 9/10 + 9/10
= 9/10 . ( 23/11 - 1/11 ) + 9/10
= 9/10 . 1 + 9/10
= 9/10 + 9/10
= 18/10 = 9/5
Cho A = 1/2 + 1/2^2 +1/2^3 + ... + 1/2^2016. Chứng tỏ A < 1.
Help me, please!!!!!!!!!!!!!!
Cho A= 1/2 + 1/3 + 1/4 + ... + 1/2016
B= 2015/1 + 2014/2 + ... + 2/2014 + 1/2015
Tính : A/B
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Please help me!!!
Làm ơn.
Tính A = 1/2-2/3-2/3+1/4+2/4+3/4-1/5-2/5-3/5-4/5+...+1/10+2/10+3/10+...+9/10. HELP ME!
Cho A = 1/2 + 1/2^2 +1/2^3 + ... + 1/2^2016. Chứng tỏ A < 1.
Help me, please!!!!!!!!!!!!!!
\(A=\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{2016}}\)
\(2A=1+\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{2015}}\)
\(2A-A=\left(1+\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{2015}}\right)-\left(\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{2016}}\right)\)
\(A=1-\frac{1}{2^{2016}}< 1\)
A=(1-\(\dfrac{1}{2^2}\)).(1-\(\dfrac{1}{3^2}\)).............(1-\(\dfrac{1}{10^2}\)) help me
Bài 1: Cho a,b,c thỏa mãn (a+b-c)/c=(b+c-a)/a=(c+a-b)/b
tính P=(1+b/a)*(1+c/b)*(1+a/c)
Bài 2: Cho a+b+c=0
tính B=((a^2+b^2-c^2)*(b^2+c^2-a^2)*(c^2+a^2-b^2))/(10*a^2*b^2*c^2)
Bài 3: cho a^3*b^3+b^3*c^3+c^3*a^3=3*a^3*b^3*c^3
tính M(1+a/b)*(1+b/c)*(1+c/a)
Bài 4: cho 3 số a,b,c TM a*b*c=2016
tính P=2016*a/(a*b+2016*a+2016) + b/(b*c+b+2016) + c/(a*c+c+1)
Bài 5: cho a+b+c=0
tính Q=1/(a^2+b^2-c^2) + 1/(b^2+c^2-a^2) + 1/(a^2+c^2-b^2)
A = ( 3/2 - 2/5 + 1/10 ) : ( 3/2 - 2/3 + 1/12 )
B = 2016. ( 1/2 - 1 ).( 1/3 - 1)..( 1/2015 - 1 ).( 1/2016 - 1)
1.Tính
a,2^4:2^3+3/10/-(-18) ("/" là trị tuyệt đối)
b,1/2-1/3+9(-1/2)^2-1/-6 ("/" là phần)
Help me
a, \(2^4:2^3+3\left|10\right|-\left(-18\right)\)
\(=2+3\cdot10+18\)
\(=20+30=50\)
b, \(\frac{1}{2}-\frac{1}{3}+9\left(-\frac{1}{2}\right)^2-\frac{1}{-6}\)
\(=\frac{1}{2}-\frac{1}{3}+9\cdot\frac{1}{4}+\frac{1}{6}\)
\(=\frac{3}{6}-\frac{2}{6}+\frac{9}{4}+\frac{1}{6}\)
\(=\frac{1}{6}+\frac{1}{6}+\frac{9}{4}=\frac{1}{3}+\frac{9}{4}=\frac{4}{12}+\frac{27}{12}=\frac{31}{12}\)