At 8:24 AM,a motorbike travels from A to B at a speed of 36 km/h.At 9:00 AM,a car travels from A to B at a speed of 54km/h and is able to catch up with the motorbike at B.Find the distance from A to B in kilometers.
The route AB is 60km long. At 7 am, one motorbike travels from A to B with a constant speed. When this motorbike reaches B, it returns to A immediately with the speed increase by 10km/h and reaches A at 10.30 am at the same day. What is the original speed of this motorbike?
Note: You must write your answer in English.
Note: You must write your answer in English.
Exchange 2h30' = 2.5h
Let the real speed of the canoe be x (km/h) (x > 0)
=> Speed downstream: x + 8 (km/h)
Upstream speed: x-8 (km/h)
According to the arle we have (x+8).2 = (x-8).2.5 => 2x+16 = 2.5x - 20 => 0.5x = 36 => x = 72 (km/h)
=> distance from A to B = (72+8).2 = 160km
both A and B province 105 km apart. motnguoi at 8 hours 15 minutes cycling from A to B at the same time a car from B to A. the two met at 9 hours 30 minutes
Asian. the velocity of each car knows the speed of each car knows the speed of the automobile velocity 5x bicycle
b. A confluence how many kilometers?
A car travels 170 km at a speed of 42,5 km/h . Find the time car takes to cover this distance .
Distance to car travel time is:
170:42,5=4(km/h)
answer:4km/h
Question 1
Bob drove from City P to City Q. He traveled the first 36km at an average speed of 54km/h. He traveled the remaining 96km at a average speed of 72km/h. Find his average speed for the whole trip.
Answer: km/h.
Question 2
John drove from Town A to Town B in 5 hours. His average speed for the first 3.5 hours was 64km/h. His average speed for the last 1.5 hours was 60km/h. What was the total distance he traveled?
Answer: km.
Question 3
A car traveled at 50km/h for 2 hours and at 60km/h for 3 hours. What is the car’s average speed?
Answer: km/h
Question 1:66 km/h
Question 2:314 km
Question 3:200/9 km/h
Question 1:66 km/h
Question 2:314 km
Question 3:56 km/h
A person travel from A to B at a constant speed v = 4 km / h. After he travelling \(\frac{2}{3}\) of the distance, he speed up 25% velocities. It takes 28 minutes to go A to B. The length of AB is.....
Mr.Joseph drives car from A to B at a constant speed. If the speed of the car is increased by 20%, it takes him one hour less than the usual time. If he drives at the constant speed for the first 100km before increasing the speed by 30%, it also takes him one hour less than the usual. The distance of AB is ..........km.
Gọi S là quãng đường
v là vận tốc
t là thời gian Mr.J đi thường ngày
=>\(\dfrac{S}{120\%v}=t-1\)
\(\dfrac{100}{v}+\dfrac{S-100}{130\%v}=t-1\)
=>\(\dfrac{S}{120\%v}=\dfrac{100}{v}+\dfrac{S-100}{130\%v}\)
<=>\(\dfrac{130S}{156v}=\dfrac{15600+120S-12000}{156v}\)
<=>\(10S=3600\)
<=>\(S=360\)
Xong rầu đó khỏi cảm ơn
A car left from town A for Town B at 8:30 am and drove at a
constant speed of 80 km per hour. A little later, a truck left from
Town B for Town A at 9:15 am at a constant speed of 100 km per
hour. If they cross each other exactly at mid-way (mid-point) of the
route between town A and B, find the distance (in km) between Town A anhd Town B.
Một chiếc ô tô còn lại từ thị trấn A cho thị trấn B lúc 8:30 sáng và thả tại một
Tốc độ không đổi 80 km mỗi giờ. Một chút sau, một chiếc xe tải còn lại từ
Thị trấn B cho thị trấn A lúc 9:15 sáng với tốc độ không đổi 100 km mỗi
Giờ. Nếu họ vượt qua nhau chính xác ở giữa-polay (giữa) của
Tuyến đường giữa thị trấn A và B, tìm khoảng cách (tính bằng km) giữa thị trấn A AHD Town B.
At 7 hours and 30 minutes, an automobile going from A to B, to 11 hours, the cars arrive. The speed of the cars is 60km / h. Calculate the distance AB
Are you sure about ' cars' in the problem. However, I can show you in case the problem can be true.
The car spends 11h-7h30min= 3h30min to go from A to B.
Since the speed of car is 60 km/h.
Applying the operation s=vt, we have
The distance AB=s= 60 × 3h30min= 210km.