\(\frac{27}{23}+\frac{-4}{23}+\frac{1}{2}+\frac{-4}{8}< x< \frac{7}{3}+\frac{13}{41}+\frac{28}{41}\)

\(\Rightarrow\frac{27}{23}-\frac{4}{23}+\frac{1}{2}-\frac{4}{8}< x< \frac{7}{3}+\frac{13}{41}+\frac{28}{41}\)

\(\Rightarrow1+0< x< \frac{7}{3}+\frac{3}{3}\)

\(\Rightarrow1< x< \frac{10}{3}\)

\(\Rightarrow1< x< 3,333333333\)

\(\Rightarrow x\in\left\{2;3\right\}\)

Vậy : ....

ta co : \(\frac{27}{23}+\frac{-4}{23}+\frac{1}{2}+\frac{-4}{8}< x< \frac{7}{3}+\frac{13}{41}+\frac{28}{41}\)

  =>  \(1< x< \frac{10}{3}\)

vi x la so nguyen => \(1< x\le3\)

con lai ban tu lam

A.-9/2

b.-5/7

C.5/287

D.302/105

nêu cách tính nha bạn 

kho the

2/15-2/65-4/39=4/39-4/39=0

32/13-(7/23+8/23)=32/13-15/23=541/299

(1/3+12/67+13/41) - (79/67 - 28/41)=6836/8241-1363/2747=1/3

38/145 - (8/45-17/51-3/11)=38/145-(-212/495)=1982/2871

( x + 2 )³ = 41 + 23

( x + 2 )^{3 =} 64

( x + 2 )^{3 =} 4³

=> x + 2 = 4

x = 4 - 2

x = 2

Vậy x =2

\(\left(2+x\right)^3-23=41\\ \left(2+x\right)^3=64\\ 2+x=4\\ x=2\)

giúp mik với

\(\left(2+x\right)^3-23=41\)

\(\Rightarrow\left(2+x\right)^3=64\)

\(\Rightarrow\left(2+x\right)^3=4^3\)

\(\Rightarrow2+x=4\)

\(\Rightarrow x=2\)

\(=>8.x^3-23=41\)

\(8.x^3=41+23=64\)

\(x^3=8\)

\(=>x=2\)

2

Mik cần lời giải chi tiết nha

( x + 2 )³ = 41 + 23

( x + 2 )^{3 =} 64

( x + 2 )^{3 =} 4³

=> x + 2 = 4

x = 4 - 2

x = 2

( 2 + x )³ - 23 = 41

( 2 + x )³ = 64 = 4³

=>  2 + x = 4

x = 2

lam hộ tao đã

\(\left(2+x\right)^3-23=41\\ \Rightarrow\left(2+x\right)^3=64\\ \Rightarrow2+x=4\\ \Rightarrow x=2\)