2x.<3y-2>+<3y-2>=-55
55^2x÷11^2x=625
\(55^{2x}\div11^{2x}=625\)
\(\left(55:11\right)^{2x}=625\)
\(5^{2x}=5^4\Rightarrow2x=4\Rightarrow x=2\)
Ta có \(55^{2x}\div11^{2x}=625\)
\(\Rightarrow\left(55\div11\right)^{2x}=625\)
\(\Rightarrow5^{2x}=5^4\)
\(\Rightarrow2x=4\)
\(\Rightarrow x=2\)
\(55^{2x}\div11^{2x}=625\)
\(\Leftrightarrow\left(55\div11\right)^{2x}=625\)
\(\Leftrightarrow5^{2x}=5^4\)
\(\Leftrightarrow2x=4\)
\(\Rightarrow x=2\)
125 : (2x - 3x) = 55 : 53
125: (2\(x\) - 3\(x\)) = 55: 53
125: (-\(x\)) = 25
\(x\) = - 125 : 25
\(x\) = - 5
Tìm x
552x:112x=625
Tìm x :
\(55^{2x}:11^{2x}=625\)
\(\Leftrightarrow\left(55:11\right)^{2x}=625\)
\(\Leftrightarrow5^{2x}=625\)
\(\Leftrightarrow5^{2x}=5^4\)
\(\Rightarrow2x=4\)
\(\Leftrightarrow x=4:2\)
\(\Leftrightarrow x=2\)
Vậy x =2
\(55^{2x}:11^{2x}=625\)
\(55^{2x}\cdot\left(\frac{1}{11}\right)^{2x}=625\)
\(\left(55\cdot\frac{1}{11}\right)^{2x}=625\)
\(5^{2x}=5^4\)
\(\Leftrightarrow2x=4\)
\(x=2\)
-(30-2x)-(55+6x)= 45+x
\(-\left(30-2x\right)-\left(55+6x\right)=45+x\\ \Rightarrow-30+2x-55-6x-45-x=0\\ \Rightarrow\left(2x-6x-x\right)+\left(-30-55-45\right)=0\\ \Rightarrow-5x-130=0\\ \Rightarrow x=\dfrac{0+130}{-5}=-26\)
(55-x).(2x-44)=0 help vs :(((
\(\left(55-x\right)\left(2x-44\right)=0\)
⇒ \(\left[{}\begin{matrix}x=55\\x=22\end{matrix}\right.\)
\(\left[{}\begin{matrix}55-x=0\\2x-44=0\end{matrix}\right.\left[{}\begin{matrix}x=55\\x=22\end{matrix}\right.\)
\(\left(55-x\right)\left(2x-44\right)=0\\ \Rightarrow\left[{}\begin{matrix}5-x=0\\2x-44=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=5\\x=22\end{matrix}\right.\)
(2x + 1 ) (3y - 2 ) = -55
(2x+1)(3y-2)=55
(2x+1)(3y-2)=-55
ta có: ( 2x + 1 ) ( 3y - 2 ) = -55
=> 2x + 1 và 3y - 2 \(\in\)Ư(55) = { -55 ; -11 ; -5 ; -1 ; 1 ; 5 ; 11 ; 55 }
vì 3y - 2 : 3 dư 1 => 3y - 2 \(\in\){ -11 ; -5 ; 1 ; 55 }
Ta có bảng giá trị:
2x + 1 | 5 | 11 | -55 | -1 |
3y - 2 | -11 | -5 | 1 | 55 |
2x | 4 | 10 | -56 | -2 |
3y | -9 | -3 | 3 | 57 |
x | 2 | 5 | -28 | -1 |
y | -3 | -1 | 1 | 19 |
Vậy có 4 cặp cặp x,y cần tìm có trong bảng.
[(2x+14).3+55=15
sai đề
(2x+14).3+55=15
(2x+14).3=15-55
(2x+14).3=-40
2x+14=-40:3
2x+14=40/3
2x=40/3-14
2x=40/3-42/3
2x=-2/3
x=-2/3:2
x=-2/3.1/2
x=-1/3
(2x + 1) (3y - 2) = -55
ai cho hỏi đề thầy giao ở online math hả? mai lên tao mách thầy!!!
ta có -55 = -11 x 5 = -5 x 11
tớ làm 1 Th còn Th còn lại cậu làm tương tự nhé
TH 1 2x + 1 = -5
và 3y - 2 = 11
=> x,y