\(\left(2x+1\right)^2=\left(\dfrac{6}{5}\right)^2\\ 2x+1=\dfrac{6}{5}\) 

Còn lại tự tính;-;

\(\Leftrightarrow\left[{}\begin{matrix}2x+1=\dfrac{6}{5}\\2x+1=-\dfrac{6}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=\dfrac{1}{5}\\2x=-\dfrac{11}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{10}\\x=-\dfrac{11}{10}\end{matrix}\right.\)

\(\left(2x+1\right)^2=\dfrac{36}{25}\\ \Leftrightarrow\left[{}\begin{matrix}\left(2x+1\right)^2=\left(\dfrac{6}{5}\right)^2\\\left(2x+1\right)^2=\left(-\dfrac{6}{5}\right)^2\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}2x+1=\dfrac{6}{5}\\2x+1=-\dfrac{6}{5}\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}2x=\dfrac{1}{5}\\2x=-\dfrac{11}{5}\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{10}\\x=-\dfrac{11}{10}\end{matrix}\right.\\ \Rightarrow S=\text{ }\left\{-\dfrac{11}{10};\dfrac{1}{10}\right\}\)

\(36\left(x-y\right)^2-25\left(2x-1\right)^2\)

\(=36\left(y^2-2xy+x^2\right)-25\left(4x^2-4x+1\right)\)

\(=36y^2-72xy+36x^2-100x^2+100x-25\)

\(=36y^2-72xy-64x^2+100x-25\)

1, \(\frac{x^2+2x+1}{2x^2-2}=\frac{\left(x+1\right)^2}{2\left(x^2-1\right)}=\frac{\left(x+1\right)^2}{2\left(x+1\right)\left(x-1\right)}=\frac{x+1}{2\left(x-1\right)}\)= \(\frac{x+1}{2x-2}\)

2 \(\frac{x^2-6x+9}{5x^2-45}=\frac{\left(x-3\right)^2}{5\left(x^2-9\right)}=\frac{\left(x-3\right)^2}{5\left(x-3\right)\left(x+3\right)}=\frac{x-3}{5x+15}\)

3 \(\frac{x^2-12x+36}{2x^2-4x}=\frac{\left(x-6\right)^2}{2x\left(x-2\right)}\)

4 \(\frac{x^2-10x+25}{2x^2-50}=\frac{\left(x-5\right)^2}{2\left(x^2-25\right)}=\frac{\left(x-5\right)^2}{2\left(x-5\right)\left(x+5\right)}=\frac{x-5}{2x+10}\)

a)(2x+1)²=25=5²=(-5)²

=>2x+1=5 hoặc 2x+1=-5

2x=5-1              2x=-5-1

2x=4                 2x=-6

x=4/2                x=-6/2

x=2                  x=-3

Vậy x=2 hoặc x=-3

b)(2x-3)²=36=6²=(-6)²

=>2x-3=6 hoặc 2x-3=-6

2x=6+3            2x=-6+3

2x=9                2x=-3

x=9/2               x=-3/2

Vậy x=9/2 hoặc x=-3/2

(2x+1)² = 25

=> 2x² + 1² = 25

=> 2x² + 1 = 25

=> 2x² = 24

=> x² = 12

=> x = \(\sqrt{12}\) 

(2x - 3)² = 36

=> 2x² - (3²) = 36

=> 2x² - 9 = 36

=> 2x² = 45

=> x² = 22,5

=> x = \(\sqrt{22,5}\)

t i c k nha!! 65768769789890

a)(2x+1)² =25

<=>(2x+1)² =5²

<=>2x+1=5

<=>2x=4

<=>x=2

b)(2x-3)² =36

<=>(2x-3)² =6²

<=>2x-3=6

<=>2x=9

<=>x=4,5

1) ( 2x + 1 )² = 25

=> ( 2x + 1 )² = 5²

=> 2x + 1 = 5 hoặc 2x + 1 = -5

=> 2x = 4 hoặc 2x = -6

=> x = 2 hoặc x = -3

2) 5^x+2 = 625

=> 5^x+2 = 5⁴

=> x + 2 = 4

=> x = 2

3) ( 2x - 3 )² = 36

=> ( 2x - 3 )² = 6²

=> 2x - 3 = 6 hoặc 2x - 3 = -6

=> 2x = 9 hoặc 2x = -3

=> x = 9/2 hoặc x = -3/2

4) ( 2x - 1 )³ = -8

=> ( 2x - 1 )³ = ( -2 )³

=> 2x - 1 = -2

=> 2x = -1

=> x = -1/2

a, (2x-3)³ = -64

=> (2x-3)³ = -4³

=> 2x-3=-4

=> 2x = -1

=> x = -1 : 2

=> x = -1/2

b, (2x-3)² =25

=>  (2x-3)² =5^2

=> 2x-3 = 5

=> 2x = 8

=> x = 4

c, (3x-4)² =36

=> (3x-4)² =6²

=> 3x-4 = 6

=> 3x = 10

=> x = 3.(3)

d, 2^x+1 = 64

=> 2^x+1  = 2⁶

=> x+1 = 6

=> x = 5

a/ (2x - 3)³ = -64 => (2x - 3)³ = (-4)³ =>  2x - 3 = -4 => 2x = -1 => x = -1/2

b/ (2x - 3)² = 25 => (2x - 3)² = 5² => 2x - 3 = 5 => 2x = 8 => x = 4

c/ (3x - 4)² = 36 => (3x - 4)² = 6² => 3x - 4 = 6 => 3x = 10 => x = 10/3

d/ 2^x+1 = 64 => 2^x+1 = 2⁶ => x + 1 = 6 => x = 5

1, \(x^2\) - 9 = 0

 (\(x\) - 3)(\(x\) + 3) = 0

 \(\left[{}\begin{matrix}x-3=0\\x+3=0\end{matrix}\right.\)

\(\left[{}\begin{matrix}x=3\\x=-3\end{matrix}\right.\)

 vậy \(x\) \(\in\) {-3; 3}

7, (3\(x\) + 1)² - 16 = 0

    (3\(x\) + 1 - 4)(3\(x\) + 1 + 4) = 0

    (3\(x\) - 3).(3\(x\) + 5) = 0

     \(\left[{}\begin{matrix}3x-3=0\\3x+5=0\end{matrix}\right.\)

      \(\left[{}\begin{matrix}3x=3\\3x=-5\end{matrix}\right.\)

       \(\left[{}\begin{matrix}x=1\\x=\dfrac{-5}{3}\end{matrix}\right.\)

Vậy \(x\) \(\in\) {1; - \(\dfrac{5}{3}\)}

10, (\(x\) + 3)² - \(x^2\) = 45

      [(\(x\) + 3) - \(x\)].[(\(x\) + 3) + \(x\)] = 45

                 3.(2\(x\) + 3)  = 45

                     2\(x\) + 3   = 15

                     2\(x\)          = 12

                       \(x\)          = 6