a, x = 108 : ( 2 + 3 + 4 )

x = 108 : 9

x = 12

b, x = 104 : (23 - 8 -7 )

x = 104 : 8

x = 13

a)bằng:2x+3x+4x=9x

108:9=12

b)bằng:23x-8x-7x=8x

104:8=13

nhơ cho mình một coin

giúp mềnh đi mà

a) (x+8).(x+60) -x² =104

x²+6x+ 8x- 48 - x² =104

14x + 48 =104

14x =104 -48

14x =56

x =\(\frac{56}{14}\)

x =4

b) 6x² -( 2x-3)(3x+2)=0

6x² -(6x²+4x-9x-6)-1=0

6x²-(6x²-5x-6)-1=0

6x²-6x²+5x+6-1=0

5x+5=0

5x=-5

x=\(\frac{-5}{5}\)=-1

Vậy.....

\(a,\left(x+8\right)\left(x+6\right)-x^2=104\)

\(\Rightarrow x^2+14x+48-x^2=104\)

\(\Rightarrow14x=56\)

\(\Rightarrow x=4\)

Vậy x=4  

Câu 2:

a: x-158=32

=>x=158+32

=>x=190

b: \(x\cdot24=264\)

=>\(x=\dfrac{264}{24}\)

=>x=11

c: \(6x+9=3^7:3^4\)

=>\(6x+9=3^3\)

=>6x+9=27

=>6x=18

=>x=18/6=3

Câu 1:

a: \(86\cdot19+14\cdot19\)

\(=19\left(86+14\right)\)

\(=19\cdot100=1900\)

b: \(4\cdot\left(-5\right)^2-104\cdot\left(-5\right)^2\)

\(=4\cdot25-104\cdot25\)

\(=25\left(4-104\right)=-100\cdot25=-2500\)

c: \(7\cdot\left(-2\right)\cdot8\left(-5\right)\)

\(=7\cdot2\cdot8\cdot5\)

\(=56\cdot10=560\)

d: \(59-\left[59+\left(-76\right)\right]\)

\(=59-59+76\)

=76

a)

104 x 7 = 7 x 104

b)

9 x 30 = (20+10) x 9

c)

(6 x 15) x 21 = 6 x (15 x 21)

d)

23 x 3 x 4 = 4 x 69= 12 x 23