Tìm x
a) \(\frac{x}{17}\)=\(\frac{60}{204}\)b) \(\frac{6+x}{33}\) = \(\frac{7}{11}\) c) \(\frac{12+x}{43-x}\) = \(\frac{2}{3}\)
có lời giải chi tiết nha
Tìm x là số tự nhiên biết :
a) \(\frac{x}{17}=\frac{60}{204}\) b) \(\frac{6+x}{33}=\frac{7}{11}\) c) \(\frac{12+x}{43-x}=\frac{2}{3}\)
d)\(\frac{x}{5}< \frac{3}{7}\) e) \(1< \frac{11}{x}< 2\) g) \(\frac{15}{26}+\frac{x}{16}=\frac{46}{52}\)
HELP ME !
a)\(\frac{x}{17}=\frac{60}{204}=\frac{5}{17}\Rightarrow x=5\)
b)\(\frac{6+x}{33}=\frac{7}{11}\Rightarrow11\left(6+x\right)=7.33\Rightarrow11.6+11x=231\Rightarrow66+11x=231\)
\(\Rightarrow11x=231-66\Rightarrow11x=165\Rightarrow x=\frac{165}{11}=15\)
c)\(\frac{12+x}{43-x}=\frac{2}{3}\Rightarrow2\left(43-x\right)=3\left(12+x\right)\Rightarrow2.43-2x=3.12+3x\)
\(86-2x=36+3x\Rightarrow86-36=3x+2x\Rightarrow50=5x\Rightarrow x=\frac{50}{5}=10\)
Tìm x là số tự nhiên biết :
A)\(\frac{x}{17}\)= \(\frac{60}{204}\)
B) \(\frac{6+x}{33}\)= \(\frac{7}{11}\)
C)\(\frac{12+x}{43-x}\)= \(\frac{2}{3}\)
A/ \(\frac{x}{17}=\frac{60}{204}\)
\(204x=60.17\)
\(204x=1020\)
\(x=\frac{1020}{204}\)
\(x=\frac{17}{4}=4,25\)
vậy x= 4,25
B/ \(\left(6+x\right).11=33.7\)
\(66+11x=231\)
\(11x=231-66=165\)
\(x=\frac{165}{11}\)
\(x=15\)
vậy x = 15
C/ \(\left(12+x\right).3=\left(43-x\right).2\)
\(36+3x=86-2x\)
\(3x+2x=86-36\)
\(5x=50\)
\(x=\frac{50}{5}=10\)
vậy x=10
mk nhầm
phần a là \(\frac{1020}{204}\)= 5 nha
mk nhầm, xin lỗi
Tìm x biết \(\frac{x+2}{17}+\frac{x+4}{15}+\frac{x+6}{13}\)\(=\frac{x+8}{11}+\frac{x+10}{9}+\frac{x+12}{7}\)
Giải chi tiết cho tớ nha, tớ tk liền luôn nha!!
tử số gồm x ,y ,z
mẫu số gồm a,b,c
[laTEX]\frac{x}{2}=\frac{y}{3}=\frac{z}{5} = t \\ \\ \frac{a}{5}=\frac{b}{4}=\frac{c}{6} = h \\ \\ \frac{x}{a} + \frac{y}{b}+ \frac{z}{c} = -\frac{187}{60} \\ \\ \frac{2t}{5h} + \frac{3t}{4h}+\frac{5t}{6h} = -\frac{187}{60} \\ \\ \frac{t}{h} = -\frac{11}{7} \\ \\ t = -11 \\ \\ h = 7[/laTEX]
3 phân số đó là
[laTEX] -\frac{22}{35} \\ \\ -\frac{33}{28} \\ \\ -\frac{55}{42}[/laTEX]
giải các pt sau:
a. x4 - 3x3 + 3x2 -x = 80
b. (x2 + x + 1) (x2 + x + 2) = 12
c. \(\frac{2+29}{31}-\frac{x+27}{33}=\frac{x+17}{43}-\frac{x-15}{45}\)
b) Đặt x2 + x + 1 = t > 0 (dễ c/m t > 0 rồi ha)
Khi đó, pt tương đương: \(t\left(t+1\right)=12\Leftrightarrow t^2+t-12=0\Leftrightarrow\left[{}\begin{matrix}t=3\\t=-4\left(L\right)\end{matrix}\right.\)
t = 3 suy ra \(x^2+x+1=3\Leftrightarrow x^2+x-2=0\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-2\end{matrix}\right.\)
Vậy...
c) Chị xem lại đề giúp em ạ.
tìm x biết :
a) \(\left(x+\frac{1}{2}\right).\left(\frac{2}{3}-2x\right)=0\)
b) \(\left(x.6\frac{2}{7}+\frac{3}{7}\right).2\frac{1}{5}-\frac{3}{7}=-2\)
c) \(x.3\frac{1}{4}+\left(-\frac{7}{6}\right).x-1\frac{2}{3}=\frac{5}{12}\)
d) \(5\frac{8}{17}:x+\left(-\frac{4}{17}\right):x+3\frac{1}{7}:17\frac{1}{3}=\frac{4}{11}\)
e) \(\frac{17}{2}-\left|2x-\frac{3}{4}\right|=-\frac{7}{4}\)
a) (x + 1/2) . (2/3 − 2x) = 0
\(\Rightarrow\left[\begin{array}{nghiempt}x+\frac{1}{2}=0\\\frac{2}{3}-2x=0\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=-\frac{1}{2}\\2x=\frac{2}{3}\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=-\frac{1}{2}\\x=\frac{1}{3}\end{array}\right.\)
b) \(\left(x.6\frac{2}{7}+\frac{3}{7}\right).2\frac{1}{5}-\frac{3}{7}=-2\)
\(\Rightarrow\left(x.\frac{44}{7}+\frac{3}{7}\right).\frac{11}{5}=-2+\frac{3}{7}\)
\(\Rightarrow\left(x.\frac{44}{7}+\frac{3}{7}\right).\frac{11}{5}=-\frac{11}{7}\)
\(\Rightarrow x.\frac{44}{7}+\frac{3}{7}=-\frac{11}{7}:\frac{11}{5}=-\frac{11}{7}.\frac{5}{11}\)
\(\Rightarrow x.\frac{44}{7}+\frac{3}{7}=-\frac{5}{7}\)
\(\Rightarrow x.\frac{44}{7}=-\frac{5}{7}-\frac{3}{7}\)
\(\Rightarrow x.\frac{44}{7}=-\frac{8}{7}\)
\(\Rightarrow x=-\frac{8}{7}:\frac{44}{7}=-\frac{8}{7}.\frac{7}{44}\)
\(\Rightarrow x=-\frac{2}{11}\)
c) \(x.3\frac{1}{4}+\left(-\frac{7}{6}\right).x-1\frac{2}{3}=\frac{5}{12}\)
\(\Rightarrow x\left(3\frac{1}{4}-\frac{7}{6}\right)=\frac{5}{12}+\frac{5}{3}\)
\(\Rightarrow x\left(\frac{13}{4}-\frac{7}{6}\right)=\frac{25}{12}\)
\(\Rightarrow x.\frac{25}{12}=\frac{25}{12}\)
\(\Rightarrow x=\frac{25}{12}:\frac{25}{12}\)
\(\Rightarrow x=1\)
d) \(5\frac{8}{17}:x+\left(-\frac{4}{17}\right):x+3\frac{1}{7}:17\frac{1}{3}=\frac{4}{11}\)
\(\Rightarrow\left(5\frac{8}{17}-\frac{4}{17}\right):x+\frac{22}{7}:\frac{52}{3}=\frac{4}{11}\)
\(\Rightarrow5\frac{4}{17}:x+\frac{33}{182}=\frac{4}{11}\)
\(\Rightarrow\frac{89}{17}:x=\frac{4}{11}-\frac{33}{182}\)
\(\Rightarrow\frac{89}{17}:x=\frac{365}{2002}\)
\(\Rightarrow x=\frac{89}{17}:\frac{365}{2002}\)
\(\Rightarrow x\approx28,7\) (số hơi lẻ)
e) \(\frac{17}{2}-\left|2x-\frac{3}{4}\right|=-\frac{7}{4}\)
\(\Rightarrow\left|2x-\frac{3}{4}\right|=\frac{17}{2}+\frac{7}{4}\)
\(\Rightarrow\left|2x-\frac{3}{4}\right|=\frac{41}{4}\)
\(\Rightarrow\left[\begin{array}{nghiempt}2x-\frac{3}{4}=\frac{41}{4}\\2x-\frac{3}{4}=-\frac{41}{4}\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}2x=11\\2x=-\frac{19}{2}\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=\frac{11}{2}\\x=-\frac{19}{4}\end{array}\right.\)
Phạm Tuấn Kiệt câu a sao nhìn không đc vậy ???
\(1+\frac{1}{1+\frac{1}{x+\frac{1}{a}}}=\frac{17}{11}\)
Tìm a
Mình đang cần lời giải (chi tiết). Cảm ơn nhiều
Ta có : \(\frac{17}{11}=1+\frac{1}{1+\frac{1}{1+\frac{1}{5}}}\)
=> a = 5
loi giai: \(1+\frac{1}{1+\frac{1}{x+\frac{1}{a}}}=\frac{17}{11}\)
\(\frac{17}{11}=1+\frac{6}{11}=1+\frac{1}{1+\frac{5}{6}}=1+\frac{1}{1+\frac{1}{1+\frac{1}{5}}}\)
a=5
tim x biết x là số tự nhiên : a) \(\frac{6+x}{33}\)= \(\frac{7}{11}\) b)\(\frac{12+x}{43-x}\)=\(\frac{2}{3}\)
ai nhanh mk tick
a, \(\frac{6+x}{33}=\frac{7}{11}\)
\(\Leftrightarrow\left(6+x\right).11=7.33\)
\(\Leftrightarrow66+11x=231\)
\(\Leftrightarrow11x=231-66\)
\(\Leftrightarrow x=\frac{165}{11}=15\)
Vậy x = 15.
b,\(\frac{12+x}{43-x}=\frac{2}{3}\)
\(\Leftrightarrow3.\left(12+x\right)=2\left(43-x\right)\)
\(\Leftrightarrow36+3x=86-2x\)
\(\Leftrightarrow3x+2x=-36+86\)
\(\Leftrightarrow5x=50\)
\(\Leftrightarrow x=10\)
Vây x = 10.
Tìm số nguyên dương x:
a) \(\frac{x}{9}<\frac{7}{x}<\frac{x}{6}\)
b) \(\frac{3}{x}<\frac{x}{7}<\frac{4}{x}\)
GIẢI CHI TIẾT ĐẦY ĐỦ VÀ DỄ HIỂU CHO MÌNH NHA