hoàn thành dãy chuyển đổi
Al2S3
^
Al2O3->Al->AlCl3->Al(OH)3
^
Al2O3->Al2(SO4)3->AlCl3
viết pthh hoàn thành dãy chuyển hóa sau
a) al2o3 -> al -> alcl3 -> al(oh)3 -> al2o3 -> al2(so4)3
b) cu -> cuo -> cucl2 -> cu(oh)2 -> cuo
*giúp tớ vs ạ :<<
\(a,2Al_2O_3\rightarrow\left(đpnc,criolit\right)4Al+3O_2\\ 2Al+6HCl\rightarrow2AlCl_3+3H_2\\ AlCl_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaCl\\ 2Al\left(OH\right)_3\rightarrow\left(t^o\right)Al_2O_3+3H_2O\\ Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\)
\(b,2Cu+O_2\rightarrow\left(t^o\right)2CuO\\ CuO+2HCl\rightarrow CuCl_2+H_2O\\ CuCl_2+2KOH\rightarrow Cu\left(OH\right)_2+2KCl\\ Cu\left(OH\right)_2\rightarrow\left(t^o\right)CuO+H_2O\)
Hoàn thành dãy biến hóa sau:
Al ––> Al2(SO4)3 ––> AlCl3 ––> Al(OH)3 ––> Al2O3
Al+H2SO4 -> Al2(SO4)3+ H2 \(\uparrow\)
Al2(SO4)3 +HCl -> AlCl3+ H2SO4
AlCl3 +Ca(OH)2 -> Al(OH)3 +CaCl2
Al(OH)3 - to> Al2O3 +H20
\(2Al+3H_2SO_4\to Al_2(SO_4)_3+3H_2\\ Al_2(SO_4)_3+3BaCl_2\to 3BaSO_4\downarrow+2AlCl_3\\ AlCl_3+3NaOH\to Al(OH)_3\downarrow+3NaCl\\ 2Al(OH)_3\xrightarrow{t^o} Al_2O_3+3H_2O\)
Al+H2SO4 -> Al2(SO4)3+ H2
↑
Al2(SO4)3 +HCl -> AlCl3+ H2SO4
AlCl3 +Ca(OH)2 -> Al(OH)3 +CaCl2
Al(OH)3 - to> Al2O3 +H20
Viết pt dãy chuyển đổi hoá học sau AL---> Al2O3---> al2(SO4)3--->Ạl(OH)3-->AlCl3
\(4Al+3O_2\underrightarrow{^{^{t^o}}}2Al_2O_3\)
\(Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\)
\(Al_2\left(SO_4\right)_3+6NaOH\rightarrow2Al\left(OH\right)_3+3Na_2SO_4\)
\(Al\left(OH\right)_3+3HCl\rightarrow AlCl_3+3H_2O\)
\(4Al+3O_2--^{t^o}->2Al_2O_3\)
\(Al_2O_3+3H_2SO_4--->Al_2\left(SO_4\right)_3+3H_2O\)
\(Al_2\left(SO_4\right)_3+3Cu\left(OH\right)_2--->2Al\left(OH\right)_3+3CuSO_4\)
\(Al\left(OH\right)_3+3HCl---->AlCl_3+3H_2O\)
Bài 3: Hoàn thành chuỗi phản ứng sau:
a. Al → Al2O3→Al2(SO4)3→Al(OH)3 →Al2O3→Al →NaAlO2
b.Al→AlCl3→Al(NO3)3→Al(OH)3→Al2(SO4)3→AlCl3→Al
c. Fe→FeCl2→Fe(OH)2→FeSO4→Fe(NO3)2→Fe→Fe3O4→Fe
d.Fe→FeCl3→Fe→Fe3O4→FeSO4.
Bài 3: Hoàn thành chuỗi phản ứng sau:
a. Al → Al2O3→Al2(SO4)3→Al(OH)3 →Al2O3→Al →NaAlO2
b.Al→AlCl3→Al(NO3)3→Al(OH)3→Al2(SO4)3→AlCl3→Al
c. Fe→FeCl2→Fe(OH)2→FeSO4→Fe(NO3)2→Fe→Fe3O4→Fe
d.Fe→FeCl3→Fe→Fe3O4→FeSO4.
a, Al=Al2O3= AlCl3=Al(OH)3=Al2O3=Al2S3
b, Al2O3=Al=Al2(SO4)3=AlCl3=Al(OH)3=Al2O3
Cho các chất: AlCl3, Al, Al2O3, Al(OH)3, Al2(SO4)3. Hãy chọn những chất có quan hệ với nhau để lập thành 2 dãy chuyển đổi hóa học và viết các PTHH.
Hoàn thành chuỗi biến hóa sau:
a) Fe → FeCl2 → Fe(OH)2 → Fe(OH)3 → Fe2O3 → FeCl3
b) Al → Al2O3 → AlCl3 → Al(OH)3 → Al2O3 → Al2(SO4)3
a.
\(\left(1\right)Fe+2HCl--->FeCl_2+H_2\)
\(\left(2\right)FeCl_2+2NaOH--->2NaCl+Fe\left(OH\right)_2\)
\(\left(3\right)4Fe\left(OH\right)_2+O_2+2H_2O\overset{t^o}{--->}4Fe\left(OH\right)_3\)
\(\left(4\right)2Fe\left(OH\right)_3\overset{t^o}{--->}Fe_2O_3+3H_2O\)
\(\left(5\right)Fe_2O_3+6HCl--->2FeCl_3+3H_2O\)
b.
\(\left(1\right)4Al+3O_2\overset{t^o}{--->}2Al_2O_3\)
\(\left(2\right)Al_2O_3+6HCl--->2AlCl_3+3H_2O\)
\(\left(3\right)AlCl_3+3NaOH--->Al\left(OH\right)_3+3NaCl\)
\(\left(4\right)2Al\left(OH\right)_3\overset{t^o}{--->}Al_2O_3+3H_2O\)
\(\left(5\right)Al_2O_3+3H_2SO_4--->Al_2\left(SO_4\right)_3+3H_2O\)
Hoàn thành chuỗi biến hóa sau:
a) Fe → FeCl2 → Fe(OH)2 → Fe(OH)3 → Fe2O3 → FeCl3
b) Al → Al2O3 → AlCl3 → Al(OH)3 → Al2O3 → Al2(SO4)3
\(b,\left(1\right)4Al+3O_2\rightarrow^{t^o}2Al_2O_3\\ \left(2\right)Al_2O_3+6HCl\rightarrow2AlCl_3+3H_2O\\ \left(3\right)AlCl_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaCl\\ \left(4\right)2Al\left(OH\right)_3\rightarrow^{t^o}Al_2O_3+3H_2O\\ \left(5\right)Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\)
\(a,\left(1\right)Fe+2HCl\rightarrow FeCl_2+H_2\\ \left(2\right)FeCl_2+2NaOH\rightarrow Fe\left(OH\right)_2+2NaCl_2\\ \left(3\right)4Fe\left(OH\right)_2+O_2+2H_2O\rightarrow4Fe\left(OH\right)_3\\ \left(4\right)2Fe\left(OH\right)_3\rightarrow^{t^o}Fe_2O_3+3H_2O\\ \left(5\right)Fe_2O_3+6HCl\rightarrow2FeCl_3+3H_2O\)
viết PTHH hoàn thành dãy biến hóa sau: Al->Al2O3->Al(SO4)->AlCl3->Al(OH)3->Al2O3->Al/NaAlO2
\(2Al+3O_2\underrightarrow{^{^{t^o}}}2Al_2O_3\)
\(Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\)
\(Al_2\left(SO_4\right)_3+3BaCl_2\rightarrow2AlCl_3+3BaSO_4\)
\(AlCl_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaCl\)
\(2Al\left(OH\right)_3\underrightarrow{^{^{t^o}}}Al_2O_3+3H_2O\)
\(2NaOH+Al_2O_3\rightarrow2NaAlO_2+H_2O\)