Bài 1:

a) \(24 - (-15) - 2\)

\(=39-2\)

\(=37\)

b) \((-85) + 10 - (-85) - 50\)

\(=[(-85)-(-85)]+10-50\)

\(=0+10-50\)

\(=10-50\)

\(=-40\)

c) \(71 - (-30) - (+18) + (-30)\)

\(=[(-30)-(-30)]+71-(+18)\)

\(=0+71-18\)

\(=71-18\)

\(=53\)

d) \(-(30) - (+37) + (+37) + (-85)\)

\(=[-(+37)+(+37)]-(30)+(-85)\)

\(=0-(30)+(-85)\)

\(=(-30)+(-85)\)

\(=-115\)

e) \((35-815) - (795-65)\)

\(=(-780)-730\)

\(=-1510\)

g) \((2002-79+15) + (-79+15)\)

\(=1938+(-64)\)

\(=1874\)

Bài 2:

a) \(25 - (30+x) = x - (27-8)\)

\(25-30-x=x-27+8\)

\(x+x=25-30+27-8\)

\(2x=14\)

\(x=14\div2\)

\(x=7\)

b) \((x-12) - 15 = (20-17) - (18+x) \)

\(x-12-15=13-18-x\)

\(x-27=-5-x\)

\(x+x=-5+27\)

\(2x=22\)

\(x=22\div2\)

\(x=11\)

c) \(15 - x = 7 - (-2)\)

\(15-x=9\)

\(x=15-9\)

\(x=6\)

d) \(x - 35 = (-12) - 3\)

\(x-35=-15\)

\(x=-15+35\)

\(x=20\)

e) \(\left|5-x\right|-26=-15\)

\(\left|5-x\right|=-15+26\)

\(\left|5-x\right|=11\)

Từ đây ta có:

*Nếu \(5-x=11\)

\(x=5-11\)

\(x=-6\)

*Nếu \(5-x=-11\)

\(x=5-(-11)\)

\(x=16\)

Vậy \(x=-6;x=16\)

a ) 

\(x+\frac{12}{15}=\frac{7}{5}\)

\(\Rightarrow x=\frac{7}{5}-\frac{12}{15}\)

\(\Rightarrow x=\frac{7}{5}-\frac{4}{5}\)

\(\Rightarrow x=\frac{3}{5}\)

Vậy \(x=\frac{3}{5}\)

b ) 

\(x-\frac{6}{8}=\frac{3}{15}\)

\(\Rightarrow x-\frac{3}{4}=\frac{1}{5}\)

\(\Rightarrow x=\frac{1}{5}+\frac{3}{4}\)

\(\Rightarrow x=\frac{4}{20}+\frac{15}{20}\)

\(\Rightarrow x=\frac{19}{20}\)

Vậy \(x=\frac{19}{20}\)

~ Ủng hộ nhé 

\(x+\frac{12}{15}=\frac{7}{5}\)

\(\Rightarrow x=\frac{7}{5}-\frac{12}{15}\)

\(\Rightarrow x=\frac{7}{5}-\frac{4}{5}\)

\(\Rightarrow x=\frac{3}{5}\)

c ) 

\(x:\frac{17}{25}=\frac{15}{34}\)

\(\Rightarrow x=\frac{15}{34}\times\frac{17}{25}\)

\(\Rightarrow x=\frac{3}{10}\)

Vậy \(x=\frac{3}{10}\)

d ) 

\(\frac{1}{5}\times x=\frac{9}{45}\)

\(\Rightarrow x=\frac{9}{45}:\frac{1}{5}\)

\(\Rightarrow x=\frac{9}{45}\times5\)

\(\Rightarrow x=\frac{9}{5}\)

Vậy \(x=\frac{9}{5}\)

~ Ủng hộ nhé 

A) 1000000 - 107492 : 154 x 28 + 1000

= 1000000 - 19544 + 1000

= 981456

B) 8/15 + 4/7 + 14/30 + 12/21 + 5

= 15/7 + 5

= 50/7

C) 9/13 : 6/11 - 5/12 : 6/11

= 9/13 x 11/6 - 5/12 x 11/6

= (9/13 - 5/12) x 11/6

= 43/156 x 11/6

= 473/936

Bài 2

1) X x2 + X x 1/5 = 8/5 

X x (2 + 1/5 ) = 8/5

X x 11/5 = 8/5

X = 8/5 x 5/11

X = 8/11

2) X : 3/8 = 4/3 : 3/6 

X : 3/8 = 8/3

X = 8/3 x 3/8

X = 1

a) 1 000 000 - 107 492 : 154 x 28 + 1000

=  1 000 000 -            698     x 28 + 1000

=  1 000 000 -                    19544 + 1000

=                    980 456                 + 1000

=                                       981 456

b) 8/15 + 4/7 + 14/30 + 12/21 + 5

  = ( 8/15 + 14/30 ) + ( 4/7 + 12/21 ) + 5

  = ( 16/30 + 14/30 ) + ( 12/21 + 12/21 ) + 5

  =            30/30      +          24/21         + 5

  =               1          +         24/21          + 5

  =           ( 1 + 5 ) + 24/21

  =                6      + 24/21

  =                     150/21

 =                         50/7        

\(-\frac{15}{12}+x+\frac{3}{7}=\frac{6}{5}x-\frac{1}{2}\)

<=>\(x-\frac{6}{5}x=-\frac{1}{2}+\frac{15}{12}-\frac{3}{7}\)

<=>\(-\frac{1}{5}x=\frac{9}{28}\)

<=>\(x=\frac{9}{28}:\left(-\frac{1}{5}\right)\)

<=>\(x=-\frac{45}{28}\)

3) \(-12+2x-9+x=0\\ -21+3x=0\\ 3x=21\\ x=7\)

4)
\(11+\left(15-x\right)=1\)
\(15-x=1-11\)
\(15-x=-10\)
\(x=15-\left(-10\right)\)
\(x=25\)

5) 
\(4-\left(27-3\right)=x-\left(13-4\right)\)
\(4-24=x-9\)
\(x-9=-20\)
\(x=-20+9\)
\(x=-11\)
 

\(3.-12+\left(2x-9\right)+x=0.\)

\(\Leftrightarrow-12+2x-9+x=0.\Leftrightarrow3x=21.\Leftrightarrow x=7.\)

Vậy \(x=7.\)

\(4.11+\left(15-x\right)=1.\Leftrightarrow11+15-x=1.\Leftrightarrow26-x=1.\Leftrightarrow x=25.\)

Vậy \(x=25.\)

\(5.4-\left(27-3\right)=x-\left(13-4\right).\Leftrightarrow4-24=x-9.\Leftrightarrow-20=x-9.\Leftrightarrow x=-11.\)

Vậy \(x=-11.\)

\(6.8-\left(x-10\right)=23-\left(-4+12\right).\Leftrightarrow8-x+10=23-8.\Leftrightarrow18-x=15.\Leftrightarrow x=3.\)

Vậy \(x=3.\)

\(7.105-5\left(10-5x\right)=-20.\Leftrightarrow105-50+25x=-20.\Leftrightarrow25x=-75.\Leftrightarrow x=-3.\)

Vậy \(x=-3.\)

\(8.\left(x-1\right)\left(8-2x\right)\left(3x+123\right)=0.\)

\(\Leftrightarrow\left[{}\begin{matrix}x-1=0.\\8-2x=0.\\3x+123=0.\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1.\\x=4.\\x=-41.\end{matrix}\right.\)

Vậy \(x\in\left\{1;4;-41\right\}.\)

\(9.\left(x^2-25\right)\left(x+10\right)=0.\)

\(\Leftrightarrow\left(x-5\right)\left(x+5\right)\left(x+10\right)=0.\)

\(\Leftrightarrow\left[{}\begin{matrix}x-5=0.\\x+5=0.\\x+10=0.\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=5.\\x=-5.\\x=-10.\end{matrix}\right.\)

Vậy \(x\in\left\{5;-5;-10\right\}.\)

\(10.x\left(x^2+5\right)=0.\Leftrightarrow x=0.\)

Bài 2:

\(a,45+170+25+30\)

\(=\left(45+25\right)+\left(170+30\right)\)

\(=60+200=260\)

Bài 3:

\(a,\left(x-6\right).5=150\)

\(x-6=150:5\)

\(x-6=30\)

\(x=30+6\)

\(x=36\)

\(b,2^5.\left(3x-2\right)=2^3.2^6\)

\(2^5.\left(3x-2\right)=2^{3+6}\)

\(2^5.\left(3x-2\right)=2^9\)

\(3x-2=2^9:2^5\)

\(3x-2=2^4=16\)

\(3x=16+2\)

\(3x=22\)

\(x=22:3\)

\(x\approx7,3\)

\(c,100-7.\left(x-5\right)=51\)

\(7.\left(x-5\right)=100-51\)

\(7.\left(x-5\right)=49\)

\(x-5=49:7\)

\(x-5=7\)

\(x=7+5\)

\(x=12\)

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