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`[124 - (20 - 4x)] \div 30 = 40`

`\Rightarrow 124 - (20 - 4x) = 40 \times 30`

`\Rightarrow 124 - (20 - 4x) = 120`

`\Rightarrow 20- 4x = 124 - 120`

`\Rightarrow 20 - 4x = 4`

`\Rightarrow 4x= 20 -4`

`\Rightarrow 4x = 16`

`\Rightarrow x = 16 \div 4`

`\Rightarrow x = 4`

Vậy, `x = 4.`

[124-(20-4.x)]:30=40

=>124-(20-4x)=40*30

=>124-(20-4x)=120

=>20-4x=124-120

=>20-4x=4

=>4x-20-4

=>4x=16

=>x=16:4

=>x=4

[124-(20-4.x)]:30=40

=>124-(20-4x)=40*30

=>124-(20-4x)=120

=>20-4x=124-120

=>20-4x=4

=>4x-20-4

=>4x=16

=>x=16:4

=>x=4

\(\Rightarrow124-\left(20-4x\right)=120\\ \Rightarrow20-4x=24\\ \Rightarrow4x=-4\\ \Rightarrow x=-1\)

[ 124 - ( 20 - 4x ) ] : 30 = 4 

=> [ 124 - ( 20 - 4x ) ] : 30 = 4

=> 124 - ( 20 - 4x ) = 120

=> 20 - 4x = 124 - 120

=> 20 - 4x = 4

=>4x = 20 - 4

=>4x = 16

=> x = 16 : 4

=> x = 4

Vậy x = 4 .

\(\left[124-\left(20-4x\right)\right]:30=4\)

\(\Leftrightarrow20-4x=4\)

hay x=4

a. 4(2x+7)-3(3x-2)=24

 => 8x+28-9x+6=24

=> -x+34=24

=> -x=-10=> x=10

b. 2(x-1)+3(x-2)=x-4

=> 2x-2+3x-6=x-4

=> 5x-8=x-4

=> 5x-x=-4+8

=> 4x=4=> x=1

c. [124-(20-4x)]:30+7=11

=> (124-20+4x):30=4

=> (104+4x):30=4

=> 104+4x=120

=> 4x=96 => x=24

uytu tyuyt

cho mình đi xong mình làm cho ^^

Đề có đúng không bạn?

Bài 2: 

a: =>x-45=-20

hay x=25

b: =>35+30-5x=-12+112

=>65-5x=100

=>5x=-35

hay x=-7

c: =>x-124=1000

hay x=1124

d: \(\Leftrightarrow46-\left(3x-2\right)^3=-18\)

\(\Leftrightarrow\left(3x-2\right)^3=64\)

=>3x-2=4

hay x=2

Bài 2: 

a: =>x-45=-20

hay x=25

b: =>35+30-5x=-12+112=100

=>65-5x=100

=>5x=-35

hay x=-7

c: =>x-124=1000

hay x=1124

d: \(\Leftrightarrow46-\left(3x-2\right)^3=-18\)

\(\Leftrightarrow\left(3x-2\right)^3=64\)

=>3x-2=4

hay x=2

ta co (x-2163)(1/2011+1/28+1/124)=0

vi 1/2011+1/28+1/124khac0

x-2163=0

x=2163