Bài 1: 

a: x/-2=-18/x

=>x²=36

=>x=6 hoặc x=-6

b: x/2+x/5=17/10

=>7/10x=17/10

hay x=17/7

`x xx 6/7=5/14`

`=>x=5/14:6/7`

`=>x=5/14xx7/6`

`=>x=35/84`

`=>x=5/12`

Vậy `x=5/12`

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`x:2/3=4/9`

`=>x=4/9xx2/3`

`=>x=8/27`

Vậy `x=8/27`

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`x-1/4=3/2`

`=>x=3/2+1/4`

`=>x=6/4+1/4`

`=>x=7/4`

Vậy `x=7/4`

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`x+4/5=8/9`

`=>x=8/9-4/5`

`=>x=40/45-36/45`

`=>x=4/45`

Vậy `x=4/45`

\(x\cdot\dfrac{6}{7}=\dfrac{5}{14}\)

\(x\)         \(=\dfrac{5}{14}:\dfrac{6}{7}\)

\(x\)           \(=\dfrac{5}{12}\)

\(x:\dfrac{2}{3}=\dfrac{4}{9}\)

\(x\)        \(=\dfrac{4}{9}\cdot\dfrac{2}{3}\)

\(x\)          \(=\dfrac{8}{27}\)

\(x-\dfrac{1}{4}=\dfrac{3}{2}\)

\(x\)          \(=\dfrac{3}{2}+\dfrac{1}{4}\)

\(x\)            \(=\dfrac{7}{4}\)

\(x+\dfrac{4}{5}=\dfrac{8}{9}\)

\(x\)          \(=\dfrac{8}{9}-\dfrac{4}{5}\)

\(x\)            \(=\dfrac{4}{45}\)

bài2 \(x\times\dfrac{15}{16}-x\times\dfrac{4}{16}=2\) 

     \(x\times\dfrac{11}{16}=2\) 

     \(x=2:\dfrac{11}{16}\) 

    \(x=\dfrac{32}{11}\)

Bài 1 : 

 \(\dfrac{x}{16}\times\left(2017-1\right)=2\)

          \(\dfrac{x}{16}\times2016=2\)

                      \(\dfrac{x}{16}=\dfrac{2}{2016}\)

                         \(x=\dfrac{2}{2016}\times16\)

                         \(x=\dfrac{1}{63}\)

1- (5\(\dfrac{4}{9}\) +x+7\(\dfrac{7}{18}\)) : 15\(\dfrac{3}{4}\) = 0 

1- (\(\dfrac{49}{9}+x+\dfrac{133}{18}\)) : \(\dfrac{63}{4}=0\) 

 (\(\dfrac{49}{9}+\dfrac{133}{18}\)+\(x\) ) : \(\dfrac{63}{4}\) = 1 - 0 

       (\(\dfrac{77}{6}\) + \(x\) ) : \(\dfrac{63}{4}\) = 1

         \(\dfrac{77}{6}+x\)         = 1 x \(\dfrac{63}{4}\) 

          \(\dfrac{77}{6}\) + \(x\)          = \(\dfrac{63}{4}\)

                  \(x\)            = \(\dfrac{63}{4}\) - \(\dfrac{77}{6}\)

                  \(x=\) \(\dfrac{35}{12}\)

bài 1 : a,ta có 3/x-1 =4/y-2=5/z-3 =>  x-1/3=y-2/4=z-3/5 

áp dụng .... => x-1+y-2+z-3 / 3+4+5 = x+y+z-1-2-3/3+4+5 = 12/12=1

do x-1/3 = 1 => x-1 = 3 => x= 4 ( tìm y,z tương tự

Bài 1: 

a) Ta có: 3/x - 1 = 4/y - 2 = 5/z - 3 => x - 1/3 = y - 2/4 = z - 3/5 áp dụng ... =>x - 1 + y - 2 + z - 3/3 + 4 + 5 = x + y + z - 1 - 2 - 3/3 + 4 + 5 = 12/12 = 1 do x - 1/3 = 1 => x - 1 = 3 => x = 4 ( tìm y, z tương tự )

cũng dễ thôi

\(\frac{x+1}{3}=\frac{y+2}{4}=\frac{z+3}{5}\)

Áp Dụng tính chất của dãy tỉ số bằng nhau ta có :

\(\frac{x+1}{3}=\frac{y+2}{4}=\frac{z+3}{5}=\frac{x+y+z+6}{12}=\frac{24}{12}=2\)

=> \(\frac{x+1}{3}=2\Rightarrow x+1=6\Rightarrow x=5\)

=> \(\frac{y+2}{4}=2\Rightarrow y=6\)

=> \(\frac{z+3}{5}=2\Rightarrow z=7\)

\(\frac{x+1}{2}=\frac{y+3}{4}=\frac{z+5}{6}\)

Áp dụng tính chất của dãy tỉ số bằng nhau ta có :

\(\frac{x+1}{2}=\frac{y+3}{4}=\frac{z+5}{6}=\frac{2x+3y+4z}{4+12+24}=\frac{9}{40}\)

=>\(\frac{x+1}{2}=\frac{9}{40}\Rightarrow x=-0,55\)

=> \(\frac{y+3}{4}=\frac{9}{40}\Rightarrow y=-2,1\)

=>\(\frac{z+5}{6}=\frac{9}{40}\Rightarrow z=-3,65\)

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\(x+\frac{2}{3}=2\frac{1}{2}\)

\(x+\frac{2}{3}=\frac{5}{2}\)

\(x=\frac{5}{2}-\frac{2}{3}\)

\(x=\frac{11}{6}\)

\(8,75.x+1,25.x=26,3\)

\(x.\left(8,75+1,25\right)=26,3\)

\(x.10=26,3\)

\(x=26,3\div10\)

\(x=2,63\)

\(x-4\frac{5}{6}=2\frac{1}{6}+\frac{5}{6}\)

\(x-\frac{29}{6}=3\)

\(x=\frac{47}{6}\)

\(5\frac{4}{5}+x-7\frac{7}{18}=15\frac{3}{4}\)

\(\frac{29}{5}+x-\frac{133}{18}=\frac{63}{4}\)

\(\frac{29}{5}+x=\frac{63}{4}+\frac{133}{18}\)

\(\frac{29}{5}+x=\frac{259}{8}\)

\(x=\frac{259}{8}-\frac{29}{5}\)

\(x=\frac{1063}{40}\)