\(\frac{x}{4}\)=\(\frac{26}{26}\)
Những câu hỏi liên quan
x - \(\frac{26}{11.13}-\frac{26}{13.15}-...-\frac{26}{53.55}=\frac{3}{11}\)
tính
\(\frac{13}{45}x\frac{15}{26}-\frac{13}{45}x\left(1\frac{1}{26}\right)+\frac{11}{26}x\frac{13}{45}\)
= \(\frac{13}{45}x\left(\frac{15}{26}-1\frac{1}{26}+\frac{11}{26}\right)=\frac{13}{45}x\left(\frac{15}{26}-\frac{27}{26}+\frac{11}{26}\right)=\frac{13}{45}x\left(\frac{27}{26}-\frac{27}{26}\right)=\frac{13}{45}x0=0\)
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Tính nhanh:\(\frac{11}{3}x\frac{26}{7}-\frac{26}{7}x\frac{8}{3}\)
Giải phương trình:\(\frac{x+73}{27}+\frac{x+74}{26}=\frac{x+27}{73}+\frac{x+26}{74}\)
\(\frac{x+73}{27}+1+\frac{x+74}{26}+1=\frac{x+27}{73}+1+\frac{x+26}{74}+1\)
\(\frac{x+73+27}{27}+\frac{x+74+26}{26}=\frac{x+27+73}{73}+\frac{x+26+74}{74}\)
\(\frac{x+100}{27}+\frac{x+100}{26}=\frac{x+100}{73}+\frac{x+100}{74}\)
\(\left(x+100\right)\left(\frac{1}{27}+\frac{1}{26}-\frac{1}{73}-\frac{1}{74}\right)=0\)
mà \(\frac{1}{27}+\frac{1}{26}-\frac{1}{73}-\frac{1}{74}\ne0\)
\(\Rightarrow x+100=0\Rightarrow x=-100\)
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Gpt \(\frac{x+24}{1996}+\frac{x+25}{1995}+\frac{x+26}{1994}+\frac{x+27}{1993}+\frac{x+2036}{4}=0\)
\(\frac{x+24}{1996}+\frac{x+25}{1995}+\frac{x+26}{1994}+\frac{x+27}{1993}+\frac{x+2036}{4}=0\)
\(\Leftrightarrow\frac{x+24}{1996}+1+\frac{x+25}{1995}+1+\frac{x+26}{1994}+1+\frac{x+27}{1993}+1+\frac{x+2036}{4}-4=0\)
\(\Leftrightarrow\frac{x+2020}{1996}+\frac{x+2020}{1995}+\frac{x+2020}{1994}+\frac{x+2020}{1993}+\frac{x+2020}{4}=0\)
\(\Leftrightarrow\left(x+2020\right)\left(\frac{1}{1996}+\frac{1}{1995}+\frac{1}{1994}+\frac{1}{1993}+\frac{1}{4}\right)=0\)
Mà \(\frac{1}{1996}+\frac{1}{1995}+\frac{1}{1994}+\frac{1}{1993}+\frac{1}{4}\ne0\)
\(\Rightarrow x+2020=0\Leftrightarrow x=-2020\)
Vậy . . . . . . . .
a) frac{x-23}{24}+frac{x-23}{25}frac{x-23}{26}+frac{x-23}{27}Leftrightarrowfrac{x-23}{24}+frac{x-23}{25}-frac{x-23}{26}-frac{x-23}{27}0Leftrightarrowleft(x-23right)left(frac{1}{24}+frac{1}{25}-frac{1}{26}-frac{1}{27}right)0Leftrightarrow x-230( vì frac{1}{24}+frac{1}{25}-frac{1}{26}-frac{1}{27}ne0)Leftrightarrow x23Vậy nghiệm của pt x23
Đọc tiếp
a) \(\frac{x-23}{24}+\frac{x-23}{25}=\frac{x-23}{26}+\frac{x-23}{27}\)
\(\Leftrightarrow\frac{x-23}{24}+\frac{x-23}{25}-\frac{x-23}{26}-\frac{x-23}{27}=0\)
\(\Leftrightarrow\left(x-23\right)\left(\frac{1}{24}+\frac{1}{25}-\frac{1}{26}-\frac{1}{27}\right)=0\)
\(\Leftrightarrow x-23=0\)( vì \(\frac{1}{24}+\frac{1}{25}-\frac{1}{26}-\frac{1}{27}\ne0\))
\(\Leftrightarrow x=23\)
Vậy nghiệm của pt x=23
left(x^2-4xright)^2-left(x-2right)^2+100.left(x-2right)tLeftrightarrow xt+2thay xt+2 ta đượcleft{left(t+2right)^2-4left(t+2right)right}^2-t^2+100left(t^2-4right)^2-t^2+100t^4-8t^2+16-t^2+100t^4-9t^2+260t^2m m^2-9m+260left(m^2-9m+frac{81}{4}right)-left(frac{81}{4}+26right)0left(m-frac{9}{2}right)^2-left(frac{81}{4}+26right)0left(m-frac{9}{2}+sqrt{frac{81}{4}+26}right)left(m-frac{9}{2}-sqrt{frac{81}{4}+26}right)0
Đọc tiếp
\(\left(x^2-4x\right)^2-\left(x-2\right)^2+10=0.\)
\(\left(x-2\right)=t\Leftrightarrow x=t+2\)
thay x=t+2 ta được
\(\left\{\left(t+2\right)^2-4\left(t+2\right)\right\}^2-t^2+10=0\)
\(\left(t^2-4\right)^2-t^2+10=0\)
\(t^4-8t^2+16-t^2+10=0\)
\(t^4-9t^2+26=0\)
\(t^2=m\)
\(m^2-9m+26=0\)
\(\left(m^2-9m+\frac{81}{4}\right)-\left(\frac{81}{4}+26\right)=0\)
\(\left(m-\frac{9}{2}\right)^2-\left(\frac{81}{4}+26\right)=0\)
\(\left(m-\frac{9}{2}+\sqrt{\frac{81}{4}+26}\right)\left(m-\frac{9}{2}-\sqrt{\frac{81}{4}+26}\right)=0\)
Tui chả hiểu bài lớp 1 sao mà ảo thật đấy
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\(\frac{\left(27\frac{5}{19}-26\frac{4}{13}\right).\left(\frac{3}{4}+\frac{19}{59}-\frac{3}{118}\right)}{\left(\frac{3}{4}+x\right)\frac{27}{33}}\) =1. Tìm x
\(\frac{\left(\frac{518}{19}-\frac{342}{13}\right).\left(\frac{177}{236}+\frac{76}{236}-\frac{6}{236}\right)}{\left(\frac{3}{4}+x\right).\frac{27}{33}}=1\)
=>\(\frac{\left(\frac{6734}{247}-\frac{6498}{247}\right).\frac{247}{236}}{\left(\frac{3}{4}+x\right).\frac{27}{33}}=1\)
=>(3/4+x)*27/33=236/247*247/236=1
3/4+x=1:27/33=33/27
x=33/27-3/4=132/108-81/108
x=51/108
Vậy x=51/108
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Giải phương trình
\(\frac{x+24}{1996}+\frac{x+25}{1995}+\frac{x+26}{1994}+\frac{x+27}{1993}+\frac{x+2036}{4}=0\)