=>(x-2)(3x+5)=0

=>x=2 hoặc x=-5/3

3x(x-2)+5x-10=0

3x²-6x+5x-10=0

3x²-x-10=0

\(\Rightarrow\)\(\left\{{}\begin{matrix}x=2\\x=\dfrac{-5}{3}\end{matrix}\right.\)

Bai lam

\(3^{x+1}=9^x\Leftrightarrow3^{x+1}=3^{2x}\)

\(\Leftrightarrow x-1=2x\Leftrightarrow-x-1=0\Leftrightarrow x=-1\)

viết sai đầu bài

\(\frac{5}{2}\)x\(\frac{1}{3}\)+\(\frac{1}{4}\)= \(\frac{5}{6}\)+\(\frac{1}{4}\)= \(\frac{10}{12}\)+\(\frac{3}{12}\)= \(\frac{13}{12}\)

\(\frac{5}{2}\)-\(\frac{1}{3}\):\(\frac{1}{4}\)= \(\frac{5}{2}\)-\(\frac{1}{3}\)x\(\frac{4}{1}\)= \(\frac{5}{2}\)-\(\frac{4}{3}\)= \(\frac{15}{6}\)-\(\frac{8}{6}\)=\(\frac{7}{6}\)

Chi tiết lun nha, nhớ k đúng cho mik nha :33

\(\frac{5}{2}\times\frac{1}{3}+\frac{1}{4}\)

\(=\frac{5}{6}+\frac{1}{4}\)

\(=\frac{10}{12}+\frac{3}{12}\)

\(=\frac{13}{12}\)

\(\frac{5}{2}-\frac{1}{3}\div\frac{1}{4}\)

\(=\frac{5}{2}-\frac{1}{3}\times\frac{4}{1}\)

\(=\frac{5}{2}-\frac{4}{3}\)

\(=\frac{15}{6}-\frac{8}{6}\)

\(=\frac{7}{6}\)

( x - 3 ) . ( 2x - 5 ) > 3

=> x > 3 . Vì nếu x bé hơn hoặc = 3 thì x - 3 = 0 kéo theo ( x - 3 ) ( 2x - 5 ) = 0 

(x-3).(2x-5)>0

(4-x)⁵- (x-2)⁵=2⁵

(4-x)-(x-2)=2

4-x-x+2=2

4-x-x=2-2

4-x-x=0

x-x=4

x=4

vậy x=4

sai roi x=2 moi dung

o ti k hieu