Phần này có cách nào làm thuận tiện hơn không ạ?! 11/15.12/13-7/15+14/15.11/13
a) 21/11 x 22/17 x 68/63 b) 5/14 x 7/13 x 26/25 (mấy cái này là phân số nhưng vì không viết đc nhe) tính bằng cách thuận tiện nhất
TÍNH BẰNG CÁCH THUẬN TIỆN NHẤT:
11+12+13+14+15+16+17+18+19.
Số số hạng là 19-11+1=9(số)
Tổng là: 10x9=90
=(11+19)+(12+18)+(13+17)+(14+16)+15
=30+30+30+30+15
=135
tính bằng cách thuận tiện nhất
11+12-13-14+15
11+12-13-14+15
=11+(12+15)-(13+14)
=11+(17-17)
=11+0
=11
11+12-13-14+15
=11+(12+15)-(13+14)
=11+0
=11
11 + 12 - 13 - 14 + 15
= 11 - ( 12 + 15 ) - ( 13 + 14 )
= 11 - 27 + 27
= 11
Tính bằng cách thuận tiện nhất: ( 6 x 8 – 48) : ( 10 + 11 + 12 + 13 + 14 + 15 )
( 6 x 8 – 48) : ( 10 + 11 + 12 + 13 + 14 + 15 )
= (48 – 48) : ( 10 + 11 + 12 + 13 + 14 + 15 )
= 0 : ( 10 + 11 + 12 + 13 + 14 + 15 )
= 0
câu trả lời là 0
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Tính bằng cách thuận tiện nhất 10-11+12-13+14-15+16-17+18-19+20
10-11+12-13+14-15+16-17+18-19+20
= (10+20)+(-11-19)+(12+18)+(-13-17)+(14+16)-15
= 30-30+30-30+30-15
= 15
(20 + 10) - (11 + 19) + ( 12 + 18 ) - ( 13 + 17 ) + ( 14 + 16 ) - 15
= 30 - 30 + 30 - 30 - 15
= -15
(20+10)-(11+19)+(12+18)-(13+17)+(14+16)-15
=30-30+30-30-15+30
=15
tính bằng cách thuận tiện nhất
a,4/15 x 7/8 + 4/15 x 2/9
b, 13/29 x 23/11 -13/19 x 8/11 - 13/19 x 4/11
Tính biểu thức sau bằng cách thuận tiện nhất :
( 6 x 8 – 48 ) : ( 10 + 11 + 12 + 13 + 14 + 15 )
a. ( 6 x 8 – 48 ) : ( 10 + 11 + 12 + 13 + 14 + 15 )
= (48 – 48) : ( 10 + 11 + 12 + 13 + 14 + 15 )
= 0 : ( 10 + 11 + 12 + 13 + 14 + 15 )
= 0
tính bằng cách thuận tiện nhất
14/13:1/2+3/13*2-2*7/13
GIÚP MIK VỚI Ạ
b,14/13:1/2+3/13*2-2*7/13=14/13*2+3/13*2-2*7/13
=2*(14/13+3/13-7/13)
=2*10/13
=20/13
bài 1 : tính bằng cách thuận tiện
a, 21 phần 11 x 22 phần 17 x 68 phần 63
b, 5 phần 14 x 7 phần 13 x 26 phần 25
tính bằng cách thuận tiện nhất:
a,7/4 x 11/21 + 11/21 x 5/4
b,23/14 x 6/13 -9/14 x 6/13
a, = \(\frac{11}{21}\)x \(\left(\frac{7}{4}+\frac{5}{4}\right)\)
= \(\frac{11}{21}\)x 3
= \(\frac{33}{21}\)
b) = \(\left(\frac{23}{14}-\frac{9}{14}\right)\)x \(\frac{6}{13}\)
= 1 x \(\frac{6}{13}\)
= \(\frac{6}{13}\)
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