-23/7.3/10+13/7.3/10
Những câu hỏi liên quan
( 3^12 + 3^11) :3^10
(2^23 + 2^24+2^25) : ( 2^18 + 2^19 +2^20)
7.3^9 +3^10+51. 3^8
1, Thực hiện phép tính'
\(A=\frac{155-\frac{10}{7}-\frac{5}{11}+\frac{5}{23}}{403-\frac{26}{7}-\frac{13}{11}+\frac{13}{23}}+\frac{\frac{3}{5}+\frac{3}{13}-0,9}{\frac{7}{91}+0,2-\frac{3}{10}}\)
\(B=\frac{30.4^7.3^{29}-5.14^5.2^{12}}{54.6^{14}.9^7-12.8^5.7^5}\)
\(A=\frac{155-\frac{10}{7}-\frac{5}{11}+\frac{5}{23}}{403-\frac{26}{7}-\frac{13}{11}+\frac{13}{23}}-\frac{\frac{3}{5}+\frac{3}{13}-0,9}{\frac{7}{91}+0,2-\frac{3}{10}}\)
\(A=\frac{155-5\left(\frac{2}{7}-\frac{1}{11}+\frac{1}{23}\right)}{403-13\left(\frac{2}{7}-\frac{1}{11}+\frac{1}{23}\right)}-\frac{\frac{3}{5}+\frac{3}{13}-\frac{9}{10}}{\frac{7}{91}+\frac{2}{10}-\frac{3}{10}}\)
\(A=\frac{155-5}{403-13}-\frac{3\left(\frac{1}{5}+\frac{1}{13}\right)-\frac{9}{10}}{\frac{7}{91}+\left(-\frac{1}{10}\right)}\)
\(A=\frac{5}{13}-\frac{\left(-\frac{9}{130}\right)}{\left(-\frac{3}{130}\right)}=\frac{5}{13}-\frac{\frac{9}{130}}{\frac{3}{130}}\)
\(A=\frac{5}{13}-\frac{9}{130}\cdot\frac{130}{3}\)
\(A=\frac{5}{13}-3=-\frac{34}{13}\)
\(B=\frac{30\cdot4^7\cdot3^{29}-5\cdot14^5\cdot2^{12}}{54\cdot6^{14}\cdot9^7-12\cdot8^5\cdot7^5}\)
\(B=\frac{30\cdot\left(2^2\right)^7\cdot3^{29}-5\cdot\left(2\cdot7\right)^5\cdot2^{12}}{54\cdot\left(2\cdot3\right)^{14}\cdot\left(3^2\right)^7-12\cdot\left(2^3\right)^5\cdot7^5}\)
\(B=\frac{30\cdot2^{14}\cdot3^{29}-5\cdot2^5\cdot7^5\cdot2^{12}}{54\cdot2^{14}\cdot3^{14}\cdot3^{14}-12\cdot2^{15}\cdot7^5}\)
\(B=\frac{30\cdot3^{29}-5\cdot2^{17}\cdot7^5}{54\cdot3^{28}-12\cdot2^{15}\cdot7^5}=\frac{30\cdot3-5\cdot2^2}{54-12}=\frac{5}{3}\)
Thực hiện phép tính :
1) A = \(\dfrac{155-\dfrac{10}{7}-\dfrac{5}{11}+\dfrac{5}{23}}{403-\dfrac{26}{7}-\dfrac{13}{11}+\dfrac{13}{23}}+\dfrac{\dfrac{3}{5}+\dfrac{3}{13}-0,9}{\dfrac{7}{91}+0,2-\dfrac{3}{10}}\)
2) B = \(\dfrac{30.4^7.3^{29}-5.14^5.2^{12}}{54.6^{14}.9^7-12.8^5.7^5}\)
1: \(A=\dfrac{5\left(31-\dfrac{2}{7}-\dfrac{1}{11}+\dfrac{1}{23}\right)}{13\left(31-\dfrac{2}{7}-\dfrac{1}{11}+\dfrac{1}{23}\right)}+\dfrac{3\left(\dfrac{1}{5}+\dfrac{1}{13}-\dfrac{3}{10}\right)}{\dfrac{1}{13}+\dfrac{1}{5}-\dfrac{3}{10}}\)
=5/13+3
=5/13+39/13
=44/13
2: \(B=\dfrac{2^{15}\cdot3^{30}\cdot5-5\cdot2^5\cdot7^5\cdot2^{12}}{3^3\cdot2\cdot2^{14}\cdot3^{14}\cdot3^{14}-2^2\cdot3\cdot2^{15}\cdot7^5}\)
\(=\dfrac{5\cdot2^{15}\left(3^{30}-2^2\cdot7^5\right)}{3^{31}\cdot2^{15}-2^{17}\cdot3\cdot7^5}\)
\(=\dfrac{5\cdot2^{15}\left(3^{30}-2^2\cdot7^5\right)}{3\cdot2^{15}\cdot\left(3^{30}-2^2\cdot7^5\right)}=\dfrac{5}{3}\)
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thực hiện phép tính :
\(A=\dfrac{155-\dfrac{10}{7}-\dfrac{5}{11}+\dfrac{5}{23}}{403-\dfrac{26}{7}-\dfrac{13}{11}+\dfrac{13}{23}}+\dfrac{\dfrac{3}{5}+\dfrac{3}{13}-0,9}{\dfrac{7}{91}+0,2-\dfrac{3}{10}}\)
\(B=\dfrac{30.4^7.3^{29}-5.14^5.2^{12}}{54.6^{14}.9^7-12.8^5.7^5}\)
a: \(A=\dfrac{5\left(31-\dfrac{2}{7}-\dfrac{1}{11}+\dfrac{1}{23}\right)}{13\left(31-\dfrac{2}{7}-\dfrac{1}{11}+\dfrac{1}{23}\right)}+\dfrac{3\left(\dfrac{1}{5}+\dfrac{1}{13}-\dfrac{3}{10}\right)}{\left(\dfrac{1}{5}-\dfrac{3}{10}+\dfrac{1}{13}\right)}\)
=5/13+3
=5/13+39/13
=44/13
b: \(B=\dfrac{3^{30}\cdot2^{15}\cdot5-5\cdot2^5\cdot7^5\cdot2^{12}}{2\cdot3^3\cdot2^{14}\cdot3^{14}\cdot3^{14}-3\cdot2^2\cdot2^{15}\cdot7^5}\)
\(=\dfrac{2^{15}\cdot5\left(3^{30}-7^5\cdot2^2\right)}{2^{15}\cdot3^{31}-3\cdot2^{17}\cdot7^5}\)
\(=\dfrac{2^{15}\cdot5\left(3^{30}-7^5\cdot2^2\right)}{2^{15}\cdot3\left(3^{30}-7^5\cdot2^2\right)}=\dfrac{5}{3}\)
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1.tính nhanh (nếu có thể)
a)29.(19-13)-19.(29-13)
b)31.(-18)+31.(-81)-31
c)(7.3-3):(-6)
d)72:[(-6).2+4)]
2 tính nhanh (nếu có thể)
a)(-12).47+(-12).52+(-12)
b)13.(23+22)-3.(17+28)
c)18-10:(-2)-7
d)99:[(-7).2+5)
a)29 . (19 – 13) – 19 . (29 – 13)
= 29 . 6 – 19 . 16
= 174 – 304
= –130.
b)31.(-18)+31.(-81)-31
= 31. [-18 + (-81) - 1 ]
= 31. (-100)
= -3100
c)(7.3-3):(-6)
(7.3-3):(-6)
= (21-3):(-6)
= 18 : (-6)
= 3
d)72:[(-6).2+4)]
= 72 : ( -12 + 4 )
= 72 : -8
= -9
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Bài 2:
a)(-12).47+(-12).52+(-12)
= (-12).(47+52+1)
= -1200
b)13.(23+22)-3.(17+28)
13 . (23 + 22) - 3 . (17 + 28)
= 13 . 45 - 3 . 45
= ( 13 - 3 ) . 45
= 10 . 45
= 450
c)18-10:(-2)-7
= 18-5+7
= 13+7
= 20
d)99:[(-7).2+5)
= 99: (-7).7= - 99
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1. Tính nhanh
a) 29 . (19 – 13) – 19 . (29 – 13)
= 29 . 6 – 19 . 16
= 174 – 304
= –130.
b) 31 . (-18) + 31 . (-81) - 31
= 31. [-18 + (-81) - 1 ]
= 31. (-100)
= -3100
c) (7 . 3 - 3) : (-6)
= (21 - 3) : (-6)
= 18 : (-6)
= 3
d) 72 : [(-6) . 2 + 4)]
= 72 : ( -12 + 4 )
= 72 : -8
= -9
2. Tính nhanh
a) (-12) . 47 + (-12) . 52 + (-12)
= (-12) . (47 + 52 + 1)
= (-12) . 100
= -1200
b) 13 . (23 + 22) - 3 . (17 + 28)
= 13 . 45 - 3 . 45
= (13 - 3) . 45
= 10 . 45
= 450
c) 18 - 10 : (-2) - 7
= 18-5+7
= 13+7
= 20
d) 99 : [(-7) . 2 + 5]
= 99 : -9
= -11
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\(\frac{2^{18}.18^7.3^3+3^{15}.2^{15}}{2^{10}.6^{15}+3^{14}.15.4^{13}}\)= ?
\(=\frac{2^{18}.2^7.3^{14}.3^3+3^{15}.2^{15}}{2^{10}.2^{15}.3^{15}+3^{14}.3.5.2^{26}}=\frac{2^{25}.3^{17}+3^{15}.2^{15}}{2^{25}.3^{15}+3^{15}.2^{26}.5}=\frac{2^{15}.3^{15}\left(2^{10}.3^2+1\right)}{2^{25}.3^{15}\left(1+2.5\right)}\)
\(=\frac{2^{10}.3^2+1}{2^{10}\left(1+2.5\right)}=\frac{2^{10}.3^2+1}{11.2^{10}}\)
\(\dfrac{2^7.3+2^{10}}{13.2^7-14.2^6}\)
\(=\dfrac{2^7\left(3+2^3\right)}{13.2^7-7.2^7}=\dfrac{2^7\left(3+8\right)}{2^7\left(13-7\right)}=\dfrac{11}{6}\)
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ℓ. 500 – {5[409 – (2³.3 – 21)²] + 10³} : 15 m. 67 – [8 + 7.3² – 24 : 6 + (9 – 7)³] : 15
n. (–23) + 13 + (–17) + 57 o. (–123) + |–13| + (–7) p. |–10| + |45| + (–|–455|) + |–750|
q. –|–33| + (–15) + 20 – |45 – 40| – 57. h. 9.|40 – 37| – |2.13 – 52|
ℓ. 500 – {5[409 – (2³.3 – 21)²] + 10³} : 15
= 500 - {5[409-(8.3-21)2]+103}:15
= 500-{5[409-(24-21)2]+1000}:15
= 500-{5[409-32]+1000}:15
= 500-{5[409-9]+1000}:15
= 500-{[5.400]+1000}:15
= 500-{2000+1000}:15
= 500-3000:15
= 500-200
= 300
m. 67 – [8 + 7.3² – 24 : 6 + (9 – 7)³] : 15
= 67 – [8 + 7.9 – 4 + 23] : 15
= 67 – [8 + 63 – 4 + 8] : 15
= 67 – [71 – 4 + 8] : 15
= 67 – [67 + 8] : 15
= 67 – 75 : 15
= 67 – 5
= 62
n. (–23) + 13 + (–17) + 57
= (–10) + [(–17) + 57]
= (–10) + 40
= 30
o. (–123) + |–13| + (–7)
= [(–123) + (–7)] + |–13|
= (–130) + 13
= (–117)
p. |–10| + |45| + (–|–455|) + |–750|
= 10 + 45 + (–455) + 750
= (10 + 45 + 750) + (–455)
= 805 + (–455)
= 350
q. –|–33| + (–15) + 20 – |45 – 40| – 57 = (–33) + (–15) + 20 – |5| – 57 = (–48) + (20 + 5 + 57) = (–48) + 82 = 34 h. 9.|40 – 37| – |2.13 – 52| = 9.|3| – |26 – 52| = 9.3 – |–26| = 27 – 26 = 1
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thực hiện phép tính; a.\(\frac{2^{18}.18^7.3^3+3^{15}.2^{15}}{2^{10}.6^{15}+3^{14}.15.4^{13}}\)
Ta có:
\(A=\frac{2^{18}.18^7.3^3+3^{15}.2^{15}}{2^{10}.6^{15}+3^{14}.15.4^{13}}=\frac{2^{18}.\left(2.3^2\right)^7.3^3+3^{15}.2^{15}}{2^{10}.\left(2.3\right)^{15}+3^{14}.3.5.\left(2^2\right)^{13}}\)
\(=\frac{2^{18}.2^7.3^{14}.3^3+3^{15}.2^{15}}{2^{10}.2^{15}.3^{15}+3^{15}.5.2^{16}}=\frac{2^{25}.3^{17}+2^{15}.3^{15}}{2^{25}.3^{15}+3^{15}.2^{16}.5}=\frac{2^{15}.3^{15}.\left(3^2.2^{10}+1\right)}{2^{16}.3^{15}.\left(2^9+5\right)}\)
\(=\frac{3^2.2^{10}+1}{2^{10}+10}=\frac{9.1024+1}{1024+10}=\frac{9217}{1025}\)
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Tính giá trị biểu thức
\(\frac{9^{10}.27^7}{81^7.3^{15}}\) \(\frac{2^{10}.3^{13}.16^3}{4^{10}.9^6}\)
Giúp em với
\(\frac{9^{10}\cdot27^7}{81^7\cdot3^{15}}=\frac{3^{20}\cdot3^{21}}{3^{28}\cdot3^{15}}=\frac{3^{41}}{3^{43}}=\frac{1}{9}\)
\(\frac{2^{10}\cdot3^{13}\cdot16^3}{4^{10}\cdot9^6}=\frac{2^{10}\cdot3^{13}\cdot2^{12}}{2^{20}\cdot3^{12}}=\frac{2^{22}\cdot3^{13}}{2^{20}\cdot3^{12}}=2^2\cdot3=12\)
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