-12(x-5)+7(3-x)=5

=>-12x-(-60)+21-7x=5

=>-12x+60-7x=5-21

=>-12x-7x=5-21-60

=>(-12-7).x=-76

=>-19x=-76

=>x=(-76):(-19)

=>x=4

Ta có:12(x-5)+7(3-x)=5

12x+-60+21+-7x=5

(12x+-7x)+(-60+21)=5

5x+-39=5

5x=5-(-39)

5x=44

x=44:5

x thuộc rỗng

Vậy không tồn tại x.

-12(x-5)+7(3-x)=5

-12.x+60+21-7.x=5

-19.x=76

=> không có x

Minh cung giai giong nhu vay nhung khuc cuoi

-19.x=76

suy ra x=-4

a: \(\Leftrightarrow\dfrac{x}{-4}=\dfrac{21}{y}=\dfrac{z}{-80}=\dfrac{3}{4}\)

=>x=-3; y=28; z=-60

b: 5/12=x/-72

=>x=-72*5/12=-6*5=-30

c: =>x+3=-5

=>x=-8

=> -12x+60+21x=5
=>9x -55=0
=>x=\(\frac{55}{9}\)

\(-12\left(x-5\right)+7\left(3x\right)=5\)

\(\Rightarrow-12x+60+21x=5\)

\(\Rightarrow-12x+21x+60=5\)

\(\Rightarrow9x+60=5\)

\(\Rightarrow9x=5-60\)

\(\Rightarrow9x=-55\)

\(\Rightarrow x=\frac{-55}{9}\)

-12(x-5)+7(x-3)=5

-12x-60+7x-21=5

-12x-7x+21+50=5

-19x+71=5

-19x=5-71

-19x=-66

x=66/19

Ta có : -12(x - 5) + 7(3 - x) = 5

<=> -12x - (-60) + 21 - 7x = 5

<=> -12x - 7x + 50 + 21 = 5

<=> -19x + 71 = 5

<=> -19x = 5 - 71

<=> -19x = -66

<=> x = 66/19

x = 66/19