\(\frac{-8}{3x-1}\)=\(\frac{4}{-7}\)
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Ai giúp vs !!!
\(a.\frac{3x-7}{5}=\frac{2x-1}{3}\\ b.\frac{4x-7}{12}-x=\frac{3x}{8}\\ c.\frac{x-2009}{1234}+\frac{x-2009}{5678}-\frac{x-2009}{197}=0\\ d.\frac{5x-8}{3}=\frac{1-3x}{2}\\ e.\frac{x-5}{6}-\frac{x-9}{4}=\frac{5x-3}{8}+2\\ f.\frac{x-1}{\frac{2}{5}}-3-\frac{3x-2}{\frac{5}{4}}-2=1\)
\(\frac{3x-7}{5}=\frac{2x-1}{3}\)
\(\Leftrightarrow9x-21=10x-5\)
\(\Leftrightarrow-x=16\Leftrightarrow x=-16\)
\(\frac{4x-7}{12}-x=\frac{3x}{8}\)
\(\Leftrightarrow\frac{4x-7-12x}{12}=\frac{3x}{8}\)
\(\Leftrightarrow\frac{-7-8x}{12}=\frac{3x}{8}\)
\(\Leftrightarrow-56-64x=36x\)
\(\Leftrightarrow-56=100x\Leftrightarrow x=\frac{-14}{25}\)
\(\frac{x-2009}{1234}+\frac{x-2009}{5678}-\frac{x-2009}{197}=0\)
\(\Leftrightarrow\left(x-2019\right)\left(\frac{1}{1234}+\frac{1}{5678}-\frac{1}{197}\right)=0\)
Vì \(\left(\frac{1}{1234}+\frac{1}{5678}-\frac{1}{197}\right)\ne0\)nên x - 2019 = 0
Vậy x = 2019
\(\frac{5x-8}{3}=\frac{1-3x}{2}\)
\(\Leftrightarrow10x-16=3-9x\)
\(\Leftrightarrow19x=19\Leftrightarrow x=1\)
\(\frac{x-5}{6}-\frac{x-9}{4}=\frac{5x-3}{8}+2\)
\(\Rightarrow\frac{4x-20-6x+54}{24}=\frac{5x-3+16}{8}\)
\(\Rightarrow\frac{-2x+34}{24}=\frac{5x+13}{8}\)
\(\Rightarrow-16x-272=120x+312\)
\(\Leftrightarrow-136x=584\Leftrightarrow x=\frac{-73}{17}\)
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\(a.\frac{4x-7}{12}-x=\frac{3x}{8}\\ b.\frac{5x-8}{3}=\frac{1-3x}{2}\\ c.\left(\frac{x-1}{\frac{2}{5}}-3\right)-\left(\frac{3x-2}{\frac{5}{4}}-2\right)=1\)
ai quen thì kb cả 2 tk nhé
a) \(\frac{4x-7}{12}-x=\frac{3x}{8}\)
\(\Rightarrow\frac{4x-7-12x}{12}=\frac{3x}{8}\)
\(\Rightarrow\frac{-7-8x}{12}=\frac{3x}{8}\)
\(\Rightarrow-56-64x=36x\)
\(\Leftrightarrow100x=-56\Leftrightarrow x=\frac{-14}{25}\)
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giai phuong trinh
a) \(\frac{3}{2x-16}+\frac{3x-20}{x-8}+\frac{1}{8}=\frac{3x-102}{3x-24}\)
b) \(\frac{1}{3-x}+\frac{14}{x^2-9}=\frac{x-4}{3+x}+\frac{7}{3+x}\)
a) \(\frac{3}{2x-16}+\frac{3x-20}{x-8}+\frac{1}{8}=\frac{3x-102}{3x-24}\) \(ĐK:x\ne8\)
\(\Leftrightarrow\frac{3}{2\left(x-8\right)}+\frac{3x-20}{x-8}+\frac{1}{8}=\frac{3x-102}{3\left(x-8\right)}\)
\(\Leftrightarrow\frac{3.3}{6.\left(x-8\right)}+\frac{6.\left(3x-20\right)}{6\left(x-8\right)}-\frac{2\left(3x-102\right)}{6\left(x-8\right)}=\frac{-1}{8}\)
\(\Leftrightarrow\frac{9+18x-120-6x+204}{6\left(x-8\right)}=\frac{-1}{8}\)
\(\Leftrightarrow\frac{12x+93}{6\left(x-8\right)}=\frac{-1}{8}\)
\(\Leftrightarrow8\left(12x+93\right)=-6\left(x-8\right)\)
\(\Leftrightarrow96x+744=-6x+48\)
\(\Leftrightarrow102x=-696\)
\(\Leftrightarrow x=\frac{-116}{17}\) (nhận)
Vậy .....
b) \(\frac{1}{3-x}+\frac{14}{x^2-9}=\frac{x-4}{3+x}+\frac{7}{3+x}\) \(ĐK:x\ne\pm3\)
\(\Leftrightarrow\frac{1}{3-x}+\frac{14}{\left(x-3\right)\left(3+x\right)}=\frac{x-4}{3+x}+\frac{7}{3+x}\)
\(\Leftrightarrow-\frac{3+x}{\left(x-3\right)\left(3+x\right)}+\frac{14}{\left(x-3\right)\left(3+x\right)}=\frac{\left(x-4\right)\left(x-3\right)}{\left(3+x\right)\left(x-3\right)}+\frac{7\left(x-3\right)}{\left(3+x\right)\left(x-3\right)}\)
\(\Leftrightarrow\frac{-3-x+14}{\left(x-3\right)\left(x+3\right)}=\frac{\left(x-4\right)\left(x-3\right)}{\left(3+x\right)\left(x-3\right)}+\frac{7\left(x-3\right)}{\left(3+x\right)\left(x-3\right)}\)
\(\Leftrightarrow-3-x+14=x^2-3x-4x+12+7x-21\)
\(\Leftrightarrow x=-5\) (nhận)
Vậy ....
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1)2x(25x-4)-(5x-2)(5x+1)8 / 5)2left(x-2right)-3left(3x-1right)left(x-3right)
2)x(4x-3)-(2x-2)(2x-1)5 / 6)frac{2}{x+1}-frac{1}{x-2}frac{3x-11}{left(x+1right)left(x-2right)}
3)frac{5}{2x+3}+frac{3}{9-x^2}frac{8}{7left(x3right)} / 7)frac{5x-2}{6}+frac{3-4x}{2}2-frac{x+7}{3}
4)frac{2}{3left(x-2right)}+frac{5}{12-3x^2}frac{3}{4left(x+2right)} /...
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1)2x(25x-4)-(5x-2)(5x+1)=8 / 5)\(2\left(x-2\right)-3\left(3x-1\right)=\left(x-3\right)\)
2)x(4x-3)-(2x-2)(2x-1)=5 / 6)\(\frac{2}{x+1}-\frac{1}{x-2}=\frac{3x-11}{\left(x+1\right)\left(x-2\right)}\)
3)\(\frac{5}{2x+3}+\frac{3}{9-x^2}=\frac{8}{7\left(x=3\right)}\) / 7)\(\frac{5x-2}{6}+\frac{3-4x}{2}=2-\frac{x+7}{3}\)
4)\(\frac{2}{3\left(x-2\right)}+\frac{5}{12-3x^2}=\frac{3}{4\left(x+2\right)}\) / 8)\(\frac{2}{x+1}-\frac{1}{x-2}=\frac{3x-11}{\left(x+1\right)\left(x-2\right)}\)
Đây là lớp 8 nha các b giúp mk với
Do mk viết nhầm
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Tìm x, biết: \(\frac{7}{8}.\left(\frac{4}{7}-1\frac{1}{7}x\right)=0,75-3x\)
\(\frac{7}{8}\cdot\left(\frac{4}{7}-1\frac{1}{7}x\right)=0,75-3x\)
\(\Rightarrow\frac{1}{2}-x=0,75-3x\)
\(\Rightarrow-4x=0,75-\frac{1}{2}\)
\(\Rightarrow-4x=0,25\)
\(\Rightarrow x=0,25:\left(-4\right)=-0,0625\)
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mấy chế ai biết giải thì giải dùm mik mấy bài nè vs.Giải phương trình: 1) frac{1}{x^2+3x+2}+frac{1}{x^2+5x+6}+frac{1}{x^2+7x+12}frac{1}{6}2) frac{1}{x^2-6x+8}+frac{1}{x^2-10x+24}+frac{1}{x^2-14x+48}frac{1}{9}3) frac{1}{x^2-3x+3}+frac{2}{x^2-3x+4}frac{6}{x^2-3x+5}4) frac{6}{left(x+1right)left(x+2right)}+frac{8}{left(x-1right)left(x+4right)}15) 4left(x^3+frac{1}{x^3}right)13left(x+frac{1}{x}right)6) frac{4x}{4x^2-8x+7}+frac{3x}{4x^2-10x+7}17) frac{x^2-3x+5}{x^2-4x+5}-frac...
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mấy chế ai biết giải thì giải dùm mik mấy bài nè vs.
Giải phương trình:
1) \(\frac{1}{x^2+3x+2}+\frac{1}{x^2+5x+6}+\frac{1}{x^2+7x+12}=\frac{1}{6}\)
2) \(\frac{1}{x^2-6x+8}+\frac{1}{x^2-10x+24}+\frac{1}{x^2-14x+48}=\frac{1}{9}\)
3) \(\frac{1}{x^2-3x+3}+\frac{2}{x^2-3x+4}=\frac{6}{x^2-3x+5}\)
4) \(\frac{6}{\left(x+1\right)\left(x+2\right)}+\frac{8}{\left(x-1\right)\left(x+4\right)}=1\)
5) \(4\left(x^3+\frac{1}{x^3}\right)=13\left(x+\frac{1}{x}\right)\)
6) \(\frac{4x}{4x^2-8x+7}+\frac{3x}{4x^2-10x+7}=1\)
7) \(\frac{x^2-3x+5}{x^2-4x+5}-\frac{x^2-5x+5}{x^2-6x+5}=\frac{-1}{4}\)
8) \(x\frac{8-x}{x-1}.\left(x-\frac{8-x}{x-1}\right)=15\)
Tìm x biết
\(\frac{4}{3x+1}+\frac{8}{6x+1}+\frac{9}{9x+3}=\frac{5}{7}\)
giải các phương trình và hệ phương trình sau
1 , 4 ( x + 5 ) ( x + 6 ) ( x + 10 ) ( x + 12 ) 3x2
2 , ( 2x - 1 ) ( 4x + 5 ) ( 8x + 3 ) ( 16x - 15 ) 99x2
3 ,( x - 1 ) ( x - 2 ) ( x - 4 ) ( x - 8 ) frac{10}{9} x2
4, frac{3x}{x^2-x+4} + frac{x}{2x^2-6x+8} 1
5 , frac{3x}{x^2-4x+1} - frac{2x}{x^2+x+1} frac{8}{3}
6, frac{3x}{x^2-3x+1} + frac{7x}{x^2+x+1} -4
7, frac{4x}{4x^2-8x+7} + frac{3x}{4x^2-10x+7} 1
8, frac{2x}{x^2-3x+1} + frac{7x}{x^2+x+1} 6
9, frac{x^2-10x+15}{x^2-6x+15} - fr...
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giải các phương trình và hệ phương trình sau
1 , 4 ( x + 5 ) ( x + 6 ) ( x + 10 ) ( x + 12 ) = 3x2
2 , ( 2x - 1 ) ( 4x + 5 ) ( 8x + 3 ) ( 16x - 15 ) = 99x2
3 ,( x - 1 ) ( x - 2 ) ( x - 4 ) ( x - 8 ) =\(\frac{10}{9}\) x2
4, \(\frac{3x}{x^2-x+4}\) + \(\frac{x}{2x^2-6x+8}\) = 1
5 , \(\frac{3x}{x^2-4x+1}\) - \(\frac{2x}{x^2+x+1}\) = \(\frac{8}{3}\)
6, \(\frac{3x}{x^2-3x+1}\) + \(\frac{7x}{x^2+x+1}\) = -4
7, \(\frac{4x}{4x^2-8x+7}\) + \(\frac{3x}{4x^2-10x+7}\)= 1
8, \(\frac{2x}{x^2-3x+1}\) + \(\frac{7x}{x^2+x+1}\) = 6
9, \(\frac{x^2-10x+15}{x^2-6x+15}\) - \(\frac{4x}{x^2-12x+15}\)= 2
Câu 3: Giải các phương trình sau bằng cách đưa về dạng ax+b0
1. a, frac{5x-2}{3}frac{5-3x}{2}; b, frac{10x+3}{12}1+frac{6+8x}{9}
c, 2left(x+frac{3}{5}right)5-left(frac{13}{5}+xright); d, frac{7}{8}x-5left(x-9right)frac{20x+1,5}{6}
e, frac{7x-1}{6}+2xfrac{16-x}{5}; f, 4 (0,5-1,5x)frac{5x-6}{3}
g, frac{3x+2}{2}-frac{3x+1}{6}frac{5}{3}+2x; h, frac{x+4}{5}.x+4frac{x}{3}-frac{x-2}{2}
i, frac{4x+3}{5}-frac{6x-2}{7}fr...
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Câu 3: Giải các phương trình sau bằng cách đưa về dạng ax+b=0
1. a, \(\frac{5x-2}{3}=\frac{5-3x}{2}\); b, \(\frac{10x+3}{12}=1+\frac{6+8x}{9}\)
c, \(2\left(x+\frac{3}{5}\right)=5-\left(\frac{13}{5}+x\right)\); d, \(\frac{7}{8}x-5\left(x-9\right)=\frac{20x+1,5}{6}\)
e, \(\frac{7x-1}{6}+2x=\frac{16-x}{5}\); f, 4 (0,5-1,5x)=\(\frac{5x-6}{3}\)
g, \(\frac{3x+2}{2}-\frac{3x+1}{6}=\frac{5}{3}+2x\); h, \(\frac{x+4}{5}.x+4=\frac{x}{3}-\frac{x-2}{2}\)
i, \(\frac{4x+3}{5}-\frac{6x-2}{7}=\frac{5x+4}{3}+3\); k, \(\frac{5x+2}{6}-\frac{8x-1}{3}=\frac{4x+2}{5}-5\)
m, \(\frac{2x-1}{5}-\frac{x-2}{3}=\frac{x+7}{15}\); n, \(\frac{1}{4}\left(x+3\right)=3-\frac{1}{2}\left(x+1\right).\frac{1}{3}\left(x+2\right)\)
p, \(\frac{x}{3}-\frac{2x+1}{6}=\frac{x}{6}-x\); q, \(\frac{2+x}{5}-0,5x=\frac{1-2x}{4}+0,25\)
r, \(\frac{3x-11}{11}-\frac{x}{3}=\frac{3x-5}{7}-\frac{5x-3}{9}\); s, \(\frac{9x-0,7}{4}-\frac{5x-1,5}{7}=\frac{7x-1,1}{6}-\frac{5\left(0,4-2x\right)}{6}\)
t, \(\frac{2x-8}{6}.\frac{3x+1}{4}=\frac{9x-2}{8}+\frac{3x-1}{12}\); u, \(\frac{x+5}{4}-\frac{2x-3}{3}=\frac{6x-1}{3}+\frac{2x-1}{12}\)
v, \(\frac{5x-1}{10}+\frac{2x+3}{6}=\frac{x-8}{15}-\frac{x}{30}\); w, \(\frac{2x-\frac{4-3x}{5}}{15}=\frac{7x\frac{x-3}{2}}{5}-x+1\)
Đây là những bài cơ bản mà bạn!
\(\frac{5x-2}{3}=\frac{5-3x}{2}\)
\(< =>\frac{\left(5x-2\right).2}{6}=\frac{\left(5-3x\right).3}{6}\)
\(< =>\left(5x-2\right).2=\left(5-3x\right).3\)
\(< =>10x-4=15-9x\)
\(< =>10x+9x=15+4\)
\(< =>19x=19< =>x=1\)
\(\frac{10x+3}{12}=1+\frac{6+8x}{9}\)
\(< =>\frac{\left(10x+3\right).3}{36}=\frac{36}{36}+\frac{\left(6+8x\right).4}{36}\)
\(< =>\left(10x+3\right).3=36+\left(6+8x\right).4\)
\(< =>30x+9=36+24+32x\)
\(< =>32x-30x=9-36-24\)
\(< =>2x=9-60=-51< =>x=-\frac{51}{2}\)
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