5x^3+3x^2+3x+1=-23x^3
Thực hiện phép chia
a) (5x^4+3x-1-3x^5):(1+x-x^2)
b) ( 2-4x +3x^4+7x^2-5x^3):(1+x^2-x)
c) ( 17x^2-6x^4+5x^3-23x+7):(7-3x^2-2x)
tìm x biết
\(5x^3+3x^2+3x-1=-23x^3\)
Tìm x :
a) x3 - 3x2 + 3x - 1 = 0
b) 5x3 + 3x2 + 3x + 1 = -23x
a) x3 - 3x2 + 3x - 1 = 0
<=>x3-x2-2x2-2x-x-1=0
<=>x2(x-1)-2x(x-1)+(x-1)=0
<=>(x2-2x+1)(x-1)=0
<=>(x-1)(x-1)(x-1)=0
<=>(x-1)3=0
<=>x=1
1) Tìm x :
a) 5x3 + 3x2 + 3x + 1 = -23x
b) x3 - 5x2+ 4x -20 = 0
b) \(x^3-5x^2+4x-20=0\)
\(=\left(x^3-5x^2\right)+\left(4x-20\right)=0\)
\(=x^2\left(x-5\right)+4\left(x-5\right)=0\)
\(=\left(x^2+4\right)\left(x-5\right)=0\)
\(x^2\ge0\)
\(\Rightarrow x^2+4\ge4>0\)
\(\Rightarrow x-5=0\)
\(\Rightarrow x=5\)
1) Tìm x :
a) 5x3 + 3x2 + 3x + 1 = -23x
b) x3 - 5x2 + 4x -20 = 0
Phân tích đa thức sau thành nhân tử
5x3+3x2 +3x +1 +23x3
=x3+3x2+3x+1+27x3
=(x+1)3 +(3x)3
=(x+1+3x) ( (x+1)2-(x+1).3x+(3x)2)
=(4x+1) (x2+2x+1-3x2-3x+9x2)
=(4x+1)(7x2-x+1)
Làm phép chia
5x4-3x5+3x-1):(x+1-x2)
(2-4x+3x4+7x2-5x3):(1+x2-x)
17x2+6x4+5x3-23x+7):(7-3x2-2x)
(3x4+11x3-5x2-19x+10):(x2+3x-2)
tìm x biết
\(5x^3+3x^2+3x-1=-23x^3\)
2x ^3 -5x^2+4x-1) : (2x+1)
(x63 -2x+4) ; (x+2)
(6x^3 - 19x^2+23x-12):(2x-3)
(x^4 - 2 x ^3 - 1+ 2 x ):(x^2 - 1)
(6x^3 - 5x^2 + 4x -1 ) : (2x^2-x+1)
(x^4 -5x^2+4):(x^2-3x+2)
d: \(\dfrac{x^4-2x^3+2x-1}{x^2-1}\)
\(=\dfrac{\left(x^2-1\right)\left(x^2+1\right)-2x\left(x^2-1\right)}{x^2-1}\)
\(=x^2-2x+1\)
\(=\left(x-1\right)^2\)
Thực hiện phép tính:
a.(2x^2 + 2x - 4) : (x + 2)
b. ( 2x^3 - 5x^2 - x +1 ) : (2x + 1 )
c. (x^3 - 2x + 4)/(x + 2)
d. (x^3- 3x^2): (x - 3)
e. (x^4- x- 14): (x- 2)
f. (x^4- x- 14): (x- 2)
g. (17x^2- 6x^4+ 5x^3- 23x+ 7): (7- 3x^2- 2x)
giúp mik đi ạ mik đang cần gấp T-T
a: \(=\dfrac{2\left(x+2\right)\left(x-1\right)}{x+2}=2x-2\)
b: \(=\dfrac{2x^3+x^2-6x^2-3x+2x+1}{2x+1}=x^2-3x+1\)
c: \(=\dfrac{x^3+2x^2-2x^2-4x+2x+4}{x+2}=x^2-2x+2\)
d: \(=\dfrac{x^2\left(x-3\right)}{x-3}=x^2\)
`@` `\text {Ans}`
`\downarrow`