tìm x,y biết : a) x+(-31/12)^2= (-49/12)^2-x = y^2
b) 5^x . (5^3)^2 = 625
c) (12/25)^2=(5/3)^-2 - (-3/5)^4
1, Tính :
a, 5-(-3)mu2-14(-8)+(-31)
b, 6(-2 ) mu3 +5(-4)-(-12)
c, -31-[82-(-17)
2, Tìm các số nguyên x,y biết (x-1)(x+y)=3
3,Tìm x thuộc Z biết :
a, 12-|x+7|=12
b, 48:|-x+3|=12
c,|x-5|=5-x
\(12-\left|x+7\right|=12\)
\(\Rightarrow\left|x+7\right|=12-12\)
\(\Rightarrow\left|x+7\right|=0\)
\(\Rightarrow x+7=0\)
\(\Rightarrow x=0-7\)
\(\Rightarrow x=-7\)
2 TÌM X BIẾT
a, (5x+1)^2 = 36/49
b, (12/25)^x =(5/3)^2 -(-3/5)^4
c, (-3/4)^ 3x-1 = 256/81
d, 172 .x ^2 -7^9 :98^3 =2^3
e,5^x .(5^3)^2 =625
f, (x-2/9)^3 =(2/3)^6
a)\(\left(5x+1\right)^2=\frac{36}{49}\\ \left(5x+1\right)^2=\left(\frac{6}{7}\right)^2\\ \Rightarrow\left[{}\begin{matrix}5x+1=\frac{6}{7}\\5x+1=\frac{-6}{7}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\frac{-1}{35}\\x=\frac{-13}{35}\end{matrix}\right.\)
vậy...
2.
a) \(\left(5x+1\right)^2=\frac{36}{49}\)
⇒ \(5x+1=\pm\frac{6}{7}\)
⇒ \(\left[{}\begin{matrix}5x+1=\frac{6}{7}\\5x+1=-\frac{6}{7}\end{matrix}\right.\) ⇒ \(\left[{}\begin{matrix}5x=\frac{6}{7}-1=-\frac{1}{7}\\5x=\left(-\frac{6}{7}\right)-1=-\frac{13}{7}\end{matrix}\right.\) ⇒ \(\left[{}\begin{matrix}x=\left(-\frac{1}{7}\right):5\\x=\left(-\frac{13}{7}\right):5\end{matrix}\right.\)
⇒ \(\left[{}\begin{matrix}x=-\frac{1}{35}\\x=-\frac{13}{35}\end{matrix}\right.\)
Vậy \(x\in\left\{-\frac{1}{35};-\frac{13}{35}\right\}.\)
Chúc bạn học tốt!
bài 1: Tìm x,y biết rằng:
\(x+(-\frac{31}{12})^2=\left(\frac{49}{12}\right)^2-x=y^2\)
bài 2: tìm x biết:
a.\(5^x.\left(5^3\right)^2=625\) b.\(\left(\frac{12}{25}\right)^x=\left(\frac{5}{3}\right)^{-2}-\left(-\frac{3}{5}\right)^4\) c.\(\left(-\frac{3}{4}\right)^{3x-1}=\frac{256}{81}\)
d.\(172x^2-7^9:98^3=2^{-3}\)
Bài 3: Tìm x \(\varepsilon\)N biết:
a.\(8< 2^x\le2^9\times2^{-5}\) b.\(27< 81^3:3^x< 243\) \(\left(\frac{2}{5}\right)^x>\left(\frac{5}{2}\right)^{-3}\times\left(-\frac{2}{5}\right)^2\)c.
Bài 1:
Ta có: \(x+\left(-\frac{31}{12}\right)^2=\left(\frac{49}{12}\right)^2-x\)
\(\Leftrightarrow2x=\frac{1440}{144}=10\)
\(\Rightarrow x=5\)
Khi đó: \(y^2=\left(\frac{49}{12}\right)^2-5=\frac{1681}{144}\)
=> \(\hept{\begin{cases}y=\frac{41}{12}\\y=-\frac{41}{12}\end{cases}}\)
1 : Tính :
a, 5 - ( -3 ) mu 2 - 14 -(-8)+(-31)
b, 6(-2)mu3 + 5(-4)-(-12)
c, -31-[82-(-17)]
2: Tìm các số nguyên x , y biết : (x-1) (x+y)=3
3: Tìm x thuộc Z biết :
a, 12-|x+7|=12
b, 48:|-x+3|=12
c,|x-5|=5-x
Bài 3:
a: =>|x+7|=0
=>x+7=0
hay x=-7
b: =>|x-3|=4
=>x-3=4 hoặc x-3=-4
=>x=7 hoặc x=-1
c: =>x-5<=0
hay x<=5
a)5^x : (5^2)^2= 625
b)(12/25)^x= (3/5)^2-(-3/5)^49: 45
c) (-3/4)^3 xX = 337
d) (x-1)^4-(x-1)^7=0
giúp mk nha mk tick cho
a) \(5^x:\left(5^2\right)^2=625\)
\(5^x:625=625\)
\(5^x=5^8\)=> x = 8
Mấy câu kia tương tự
d) \(\left(x-1\right)^4-\left(x-1\right)^4\cdot\left(x-1\right)^3=0\)
\(\left(x-1\right)^4\cdot\left[1-\left(x-1\right)^3\right]=0\)
\(\Rightarrow\orbr{\begin{cases}x-1=0\\\left(x-1\right)^3=1\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=1\\x-1=1\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=1\\x=2\end{cases}}\)
Vậy,..........
1: Tính :
a, 5-(-3)mu2 -14(-8)+(-31)
b,6(-2)mu 3+5(-4)-(-12)
c,-31-[82-(-17)]
2: Tìm các số nguyên x,y biết (x-1)(x+y)=3
3: Tìm x thuộc Z biết :
a,12-|x+7|=12
b,48:|-x+3|=12
c,|x-5|=5-x
Bài 3:
a: =>|x+7|=12-12=0
=>x+7=0
hay x=-7
b: =>|x-3|=4
=>x-3=4 hoặc x-3=-4
=>x=7 hoặc x=-1
c: =>x-5<=0
hay x<=5
(12/25)^x=(5/3)^-2-(-3/5)^4
(12/25)^x=144/625
(12/25)^x=(12/25)^2
=>x=2
bài 1: Tính
a} 5/12 + 1/3 x 3/5 =
B 7/5 - 4/9 : 2/5 =
C 2/5 x 1/4 : 2/5 =
bài 2: Tìm y
a 42/25 : y/5 = 5/6
b 27/y : 9/4 = 3/7
bài 2
a)42/25:y/5=5/6
y=10,08
b)27/y:9/4=3/7
y=28
1)a)2x-13=25+6x
b)12-x=3x+6
c)40-(25-2x)=x
d)|x-3|=5
e)|x-3|+(x+2)+(x+1)=12
2)tính
a)(-1).(-2).(-3).(-4).(-5).[(-3)-(-5)]
b)1-2+3-4+5-6+...-98+99
3)tim x
a)(x-1).(y-2)=5
b)x.(y-3)=12