\(x+x:0.2=1.35\)

\(x+x:\frac{1}{5}=1.35\)

\(x+5x=1.35\)

\(6x=1.35\)

\(x=1.35:6\)

\(x=0.225\)

\(x+x:0,2=1.35\)

\(x:1+x:0,2=1,35\)

\(x:\left(1+0,2\right)=1,35\)

\(x:1,2=1,35\)

\(x=1,35\cdot1,2=1,62\)

\(x\left(1+\frac{1}{0.2}\right)=1,35\)

\(6x=1,35\)

\(x=1,35:6=0,225\)

X + X chia 0,2 =1,35

=> 2x : 0,2 = 1,35

=> 2x = 1,35 * 0,2 

=> 2x = 0,27

=> x = 0,135

x + x : 0,2 = 1,35

x * 1 + x * 5 = 1,35

x * ( 1 + 5 ) = 1,35

x * 6 = 1,35

x = 1,35 : 6

x = 0,225

X + X : 0,2 = 1,35

X + X.        = 1,35 x 0,2

X + X         =  0,27

X.               = 0,3

  x + x : 0,2 = 1,35

  x . 1 + x . 5 = 1,35

  x . ( 1 + 5 ) = 1,35

            x . 6 = 1,35

                 x = 1,35 : 6

                 x = 0,225

​Vậy x=0,225

Lời giải:

$x+\frac{x}{0,2}=1,35$

$x+x\times 5=1,35$

$x\times (1+5)=1,35$

$x\times 6=1,35$

$x=1,35:6=0,225$

x:1+x:0.2=1.35

x:(1+0.2)=1.35

1:1.2=1.35

x=1.35*1.2

x=1.62

x+x:0,2=1,35
2x : 0,2=1,25
2x=1,35 x 0,2
2x=0,27
x=0,27:2
x= 0, 135

x + x : 0,2 = 1,35

x + \(\frac{x}{0,2}\)= 1,35

x*(1+\(\frac{1}{0,2}\)) =1,35

x*6=1.35

x= 1.35 : 6

x=0.225

= 0,135 đúng không bạn tích nha

x =0,225

\(x+\frac{x}{0,2}=1,35\)

\(\frac{x\times0,2+x}{0,2}=1,35\)

\(\frac{1,2\times x}{0,2}=1,35\)

\(1,2\times x=1,35\times0,2\)

\(1,2\times x=0,27\)

\(x=0,27:1,2\)

\(x=0,225\)

d: Ta có: \(3^{x+2}\cdot2^{x-1}=36^3\)

\(\Leftrightarrow3^x\cdot9\cdot2^x\cdot\dfrac{1}{2}=6^6\)

\(\Leftrightarrow6^x=6^6:\dfrac{9}{2}=10368\)

=> Đề sai rồi bạn

\(a,\Rightarrow\left[{}\begin{matrix}x-\dfrac{2}{3}=\dfrac{5}{4}\\\dfrac{2}{3}-x=\dfrac{5}{4}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{23}{12}\\x=-\dfrac{7}{12}\end{matrix}\right.\\ b,\Rightarrow0,1x\cdot1,35=0,2\cdot1,25=0,25\\ \Rightarrow0,135x=0,25\Rightarrow x=\dfrac{50}{27}\\ c,ĐK:x\ge0\\ PT\Leftrightarrow-2\sqrt{x}=-6\Leftrightarrow x=9\left(tm\right)\\ d,\Leftrightarrow3^{x+2}\cdot2^{x-1}=\left(3^2\cdot2^2\right)^3=3^6\cdot2^6\\ \Leftrightarrow\left\{{}\begin{matrix}x+2=6\\x-1=6\end{matrix}\right.\Leftrightarrow x\in\varnothing\)

a) I\(x - \dfrac{2}{3} \)I \(- \dfrac{5}{4} = 0\)

    I\(x - \dfrac{2}{3} \)I = 0 +\(\dfrac{5}{4} \)

    I\(x - \dfrac{2}{3} \)I = \(\dfrac{5}{4} \)

    I\(x - \dfrac{2}{3} \)I = \(\begin{cases} \dfrac{5}{4} + \dfrac{2}{3}\\ \dfrac{-5}{4} + \dfrac{2}{3}\\ \end{cases} \)

    \(x \) = \(\begin{cases} \dfrac{23}{12} \\ \dfrac{-7}{12} \end{cases} \)

b) \(\dfrac{1,35}{0,2} = \dfrac{1,25}{0,1x}\)

     1,35 . 0,1x = 1,25 . 0,2

     1,35 . 0,1x = 0,25

      0,1x = 0,25 : 1,35 

      \(\dfrac{1}{10}\)x = \(\dfrac{5}{27}\)

       x = \(\dfrac{5}{27} : \dfrac{1}{10}\)

       x = \(\dfrac{5}{27} . \dfrac{10}{1}\)

       x = \(\dfrac{50}{27}\)

\(a.\frac{1,35}{0,2}=\frac{1,25}{0,1x}\)

\(\frac{0,2\cdot1,25}{1,35}=0,1x\)

0,8 = 0,1x

x=8

b. 2x - 3 = x + 1/2

2x - 3 - x - 1/2=0

x-3,5 = 0

x= 3,5

c. (3x - 1/4 ) * ( x+ 1/2)=0