Ta rút gọn hai phân số rồi so sánh:

\(\frac{200420042004}{200520052005}\) = \(\frac{200420042004:100010001}{200520052005:100010001}\) = \(\frac{2004}{2005}\)

\(\frac{20042004}{20052005}\) = \(\frac{20042004:10001}{20052005:10001}\)= \(\frac{2004}{2005}\)

Ta thấy: \(\frac{2004}{2005}\)= \(\frac{2004}{2005}\)

Vậy: hai phân số này bằng nhau

ta có:

\(\frac{200420042004}{200520052005}=\frac{200420042004:100010001}{200520052005:100010001}=\frac{2004}{2005}\)

\(\frac{20042004}{20052005}=\frac{20042004:10001}{20052005:10001}=\frac{2004}{2005}\)

\(\Rightarrow\frac{200420042004}{200520052005}=\frac{20042004}{20052005}\)

Rút gọn ta có:

\(=\frac{2003}{2004}x\frac{2003}{2005}x\frac{2004}{2005}\)

\(=\frac{2003x2003x2004}{2004x2005x2005}\)

Giản bước ta được: \(\frac{2003x2003}{2005x2005}\)

Ta có : \(\frac{2003}{2004}\)x\(\frac{200320032003}{200520052005}\)x\(\frac{20042004}{20052005}\)

=          \(\frac{2003}{2004}\)x\(\frac{2003x100010001}{2005x100010001}\)x\(\frac{2004x10001}{2005x10001}\)

=           \(\frac{2003x2003x2004}{2004x2005x2005}\)

=             \(\frac{2003x2003}{2005x2005}\)

Bạn rút gọn hộ mik nhaa !!!

A = 2007 x 2010/ 2008 x 2009

=> A = 2007 x (2009 + 1)/(2007+1) x 2009

=> A = 2009 x 2007 + 2007/ 2007 x 2009 + 2009

Có 2009 x 2007 + 2007 < 2007 x 2009 + 2009

=> A < 1

> vì 151515>0,........

151515 X 40104010 / 20052005 X 464646 =  15 / 23     

1751/2575 = 17/25 

Tìm Phân số trung gian :

15/23 = 1-15/23 = 8/23            17/25 = 1-8/25 

Vì 8/23 > 8 /25 Nên 15/23 < 17/25 Vậy 151515 X 40104010 / 20052005 X 464646 < 1751/2575

1)
B=27(56-43)+11.73
B=27.13+11.73
B=351+803=1154
2)
2(x-2)=x+4
2x-4=x+4
x=8
3)
A=100²
B=99.101=(100-1)(100+1)=100²-1
=>A>B
b)
\(3^{12}=9^6;2^6.5^6=10^6\)
=>\(3^{12}< 2^6.5^6\)