alo anh em 

a) https://hoc247.net/hoi-dap/toan-7/thuc-hien-phep-tinh-5-5-27-7-23-0-5-5-27-16-23-faq218258.html

b) https://hoidap247.com/cau-hoi/1507941

b) \(\dfrac{10^9.49^4}{14^8.25^5}=\dfrac{\left(2.5\right)^9.\left(7^2\right)^4}{\left(7.2\right)^8.\left(5^2\right)^5}=\dfrac{2^9.5^9.7^6}{7^8.2^8.5^{10}}=\dfrac{2}{7.7.5}=\dfrac{2}{245}\)

\(a,=\left(\dfrac{140}{27}+\dfrac{1}{2}\cdot\dfrac{5}{27}\right)+\left(\dfrac{7}{23}+\dfrac{16}{23}\right)\\ =\left(\dfrac{140}{27}+\dfrac{5}{54}\right)+1=\dfrac{285}{54}+1=\dfrac{339}{54}=\dfrac{113}{18}\\ b,=\dfrac{2^9\cdot5^9\cdot7^8}{7^8\cdot2^8\cdot5^{10}}=\dfrac{2}{5}\)

cách 1: 20 + 3 = 23

cách 2: 20 + (3\(^3\): 3\(^2\)) = 20 + 3 = 23

cách 3: 20 + (9.3 : 9) = 20 + 3 = 23

\(\dfrac{2}{1\times3}+\dfrac{2}{3\times5}+\dfrac{2}{5\times7}+...+\dfrac{2}{13\times15}+\dfrac{2}{15\times17}\)

\(=1-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+...+\dfrac{1}{13}-\dfrac{1}{15}+\dfrac{1}{15}-\dfrac{1}{17}\)

\(=1-\dfrac{1}{17}\)

\(=\dfrac{16}{17}\)

\(\dfrac{2}{1\cdot3}+\dfrac{2}{3\cdot5}+...+\dfrac{2}{15\cdot17}\)

\(=2-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+...+\dfrac{1}{15}-\dfrac{1}{17}\)

\(=2-\dfrac{1}{17}\)

\(=\dfrac{33}{17}\)

nhan 2 ve cho 5^3

5^2.5^2x=5^2x+5^6.24

5^2x(5^2-1)=5^6.24

5^2x=5^6=> x=3

tên hay tên hay

bn tên rất hay max hay

5^2x-1-5^2x-3=5³.2³.3

5^2x-1-5^2x-1-2=125.24

5^2x-1-5^2x-1:5²=125.24

5^2x-1-5^2x-1.\(\frac{1}{25}\)=125.24

5^2x-1.(1-\(\frac{1}{25}\))=125.24

5^2x-1.\(\frac{24}{25}\)=125.24

5^2x-1=(125.24):\(\frac{24}{25}\)

5^2x-1=125.25

5^2x-1=5³.5²=5⁵

-> 2x-1=5

2x=6

x=3

x=3 cach giai da co