\(A=x\left(9x^2-16\right)-9\left(x^3+8\right)+16x\\ A=9x^3-16x-9x^3-72+16x\\ A=-72\)

\(A=x\left(3x-4\right)\left(3x+4\right)-9\left(x+2\right)\left(x^2-2x+4\right)+16x\)

\(=x\left(9x^2-16\right)-9\left(x^3+8\right)+16x\)

\(=9x^3-16x-9x^3-72+16x=-72\)

\(A=x\left(3x-4\right)\left(3x+4\right)-9\left(x+2\right)\left(x^2-2x+4\right)+16x\)

\(=x\left(9x^2-16\right)-9\left(x^3+8\right)+16x\)

\(=9x^3-16x-9x^3-72+16x\)

=-72

Lời giải:

$A=x[(3x)^2-4^2]-9(x^3+2^3)+16x$

$=x(9x^2-16)-9(x^3+8)+16x$

$=9x^3-16x-9x^3-72+16x$

$=-72$

\(A=x\left(3x-4\right)\left(3x+4\right)-9\left(x+2\right)\left(x^2-2x+4\right)+16x\)

\(=9x^3-16x-9x^3-72+16x\)

=-72

B = (x – 2)( x 2 + 2x + 4) – x(x – 1)(x + 1) + 3x

B = (x – 2)( x 2 + x.2 + 2 2 ) – x( x 2 – 1) + 3x

B   =   x 3   –   2 3   –   x . x 2   +   x . 1   +   3 x     B   =   x 3   –   8   –   x 3   +   x   +   3 x

B = 4x – 8

Đáp án cần chọn là: D

câu b mình viết nhầm nha 
b,(x+1)^3-(x-2)(x^2+2x+4)

Bài 6:

c: \(9x^2+6x+1=\left(3x+1\right)^2\)

d: \(4x^2-9=\left(2x-3\right)\left(2x+3\right)\)

e: \(x^3+27=\left(x+3\right)\left(x^2-3x+9\right)\)

Ta có: P = x − x + 2 ( x + 1 ) ( x − 2 ) − x x ( x − 2 ) : 1 − x 2 − x = x − x + 2 − x ( x + 1 ) ( x + 1 ) ( x − 2 ) . 2 − x 1 − x = 2 − 2 x ( x + 1 ) ( x − 1 ) = 2 ( 1 − x ) ( x + 1 ) ( x − 1 ) = − 2 x + 1  

a. \(\left(x+2\right)^{^2}-\left(x-4\right)^{^2}+x^{^2}-3x+1=x^{^2}+4x+4-x^{^2}+8x-16+x^{^2}-3x+1=x^{^2}+9x-11\)

b. \(\left(2x+2\right)^{^2}-4x\left(x+2\right)=4x^{^2}+8x+4-4x^{^2}-8x=4\)

a) Ta có: \(\left(x+2y\right)\left(x^2-2xy+4y^2\right)-\left(x-y\right)\left(x^2+xy+y^2\right)\)

\(=x^3+\left(2y\right)^3-\left(x^3-y^3\right)\)

\(=x^3+8y^3-x^3+y^3\)

\(=9y^3\)

b) Ta có: \(\left(x+1\right)\left(x-1\right)^2-\left(x+2\right)\left(x^2-2x+4\right)\)

\(=\left(x+1\right)\left(x^2-2x+1\right)-\left(x+2\right)\left(x^2-2x+4\right)\)

\(=x^3-2x^2+x+x^2-2x+1-\left(x^3+8\right)\)

\(=x^3-x^2-x+1-x^3-8\)

\(=-x^2-x-7\)

`a)(2x-1)^2+(x+3)^2-5(x-7)(x+7)`

`=4x^2-4x+1+x^2+6x+9-5(x^2-49)`

`=5x^2-5x^2-4x+6x+1+9+245`

`=2x+255`

`b)(x-2)(x^2+2x+4)-(25+x^3)`

`=x^3-8-x^3-25=-33`

Lời giải:

a. 

$(2x-1)^2+(x+3)^2-5(x-7)(x+7)$

$=4x^2-4x+1+(x^2+6x+9)-5(x^2-49)$

$=5x^2+2x+10-(5x^2-245)=2x+255$

b.

$(x-2)(x^2+2x+4)-(25+x^3)=(x^3-2^3)-(25+x^3)$

$=-8-25=-33$

a: \(\left(2x-1\right)^2+\left(x+3\right)^2-5\left(x-7\right)\left(x+7\right)\)

\(=4x^2-4x+1+x^2+6x+9-5x^2+245\)

\(=2x+255\)

b: \(\left(x-2\right)\left(x^2+2x+4\right)-\left(x^3+25\right)\)

\(=x^3-8-x^3-25\)

=-33