k chia hết

\(\approx2318,7\)

2318,888888

Tìm các số tự nhiên: Các số tự nhiên x có thể là : 289 ; 290 ; 291 ; 292 ; 293 ; 294 ; 295

Đặt : \(A=\dfrac{4}{8\times11}+\dfrac{4}{11\times14}+...+\dfrac{4}{296\times299}\)

\(\dfrac{3\times A}{4}=\dfrac{3}{8\times11}+\dfrac{3}{11\times14}+...+\dfrac{3}{296\times299}\\ =\dfrac{1}{8}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{14}+...+\dfrac{1}{296}-\dfrac{1}{299}\\ =\dfrac{1}{8}-\dfrac{1}{299}\\ A=\left(\dfrac{1}{8}-\dfrac{1}{299}\right)\times4:3=\dfrac{97}{598}\)

Ta đặt

\(A=\dfrac{4}{8\times11}+\dfrac{4}{11\times14}+....+\dfrac{4}{296\times299}\)

\(\dfrac{3}{4}A=\dfrac{3}{8\times11}+\dfrac{3}{11\times14}+....+\dfrac{3}{296\times299}\)

\(\dfrac{3}{4}A=\dfrac{1}{8}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{14}+....+\dfrac{1}{296}-\dfrac{1}{299}\)

\(\dfrac{3}{4}A=\dfrac{1}{8}-\dfrac{1}{299}=\dfrac{291}{2392}\)

\(A=\dfrac{291}{2392}\div\dfrac{3}{4}\)

\(A=\dfrac{97}{598}\)

2180

74  * 11 - 74 * { 6 + 3 + 1}

= 74 * 11 - 74 * 10

= 74 * { 11 -10}

= 74 *1 = 74

   74 x 11 - ( 74 x 6 + 74 x 3 + 74 )

=   814   -   74 x ( 6 + 3 + 1 )

=  814   - 74 x 10

= 814  -  740

=74

ai tk mk mk tk lại

74 x 11 – (74 x 6 + 74 x 3 + 74)

= 74 x 11 – 74 x 6 + 74 x 3 + 74

= 74 x (11 – 6 – 3 )

= 74 x 2

= 148 

a. 2012 x ( 2011 - 1) + 2013 x ( 999 + 1 ) 

= 2012 x 2010 + 2013 x 1000 

= 4044120 + 2013000

= 6057120

b. ( 191 - 109) x 5 + ( 624 - 296) : 4

= 82 x 5 + 328 : 4

= 410 + 82 

= 492

b) = [5 x( 191 - 109 ) ] + [(624 - 296 ) : 4]

= (5 x 82) + (328 : 4)

= 410 + 82 

= 492

18/49

20/7

14/11

3/35

a) 24 × y : 20 = 480

24 × y = 480 × 20

24 × y = 9600

y = 9600 : 24

y = 400

b) 12862 : y - 296 = 61

12852 : y = 61 + 296

12852 : y = 357

y = 12852 : 357

y = 36