68:4+158-1025-(128:4)
Tìm x: a)128-3.(x+4)=23
b)(158-x):7=20
a) \(128-3\cdot\left(x+4\right)=23\)
\(\Leftrightarrow3\cdot\left(x+4\right)=105\)
\(\Leftrightarrow x+4=35\)
\(\Leftrightarrow x=31\)
b) \(\left(158-x\right):7=20\)
\(\Leftrightarrow158-x=140\)
\(\Leftrightarrow x=18\)
\(a,128-3.\left(x+4\right)=23\)
\(\Rightarrow3.\left(x+4\right)=128-23\)
\(\Rightarrow3.\left(x+4\right)=105\)
\(\Rightarrow\left(x+4\right)=105:3\)
\(\Rightarrow\left(x+4\right)=35\)
\(\Rightarrow x=35-4\)
\(\Rightarrow x=31\)
\(b,\left(158-x\right):7=20\)
\(\Rightarrow\left(158-x\right)=20.7\)
\(\Rightarrow\left(158-x\right)=140\)
\(\Rightarrow x=158-140\)
\(\Rightarrow x=18\)
128-[68+8937-12250:4
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128-[68+8(37-35)^2]:4
Lời giải:
$128-[68+8(37-35)^2]:4=128-(68+8.2^2):4$
$=128-100:4=128-25=103$
Bài 2: Tính hợp lí
1) 125.(-24) + 24.225
2) 512.(2 – 128) – 128. (-512)
3) (187 -23) – (20 – 180)
4) (-37 – 17). (-9) + 35. (-9 – 11)
5) (-50 +19 +143) – (-79 + 25 + 48)
6) (-8).25.(-2). 4. (-5).125
7) 3784 + 23 – 3785 – 15
8) 215 +(-38) – (-58) –15
9) 5.(-3)2 –14.(-8)+(-40)
10) 215 + (-38) – (- 58) + 90 – 852)
Bài 3*: Tìm các cặp số nguyên (x;y) thỏa mãn xy2 + 2x – y2 =
1) 125.(-24) + 24.225.
\(=24\left(-125+225\right)=24.100=2400.\)
2) 512.(2 – 128) – 128. (-512).
\(=512\left(2-128+128\right)=512.2=1024.\)
A2=128-[68+8(37-35)2]:4
128 - [ 68 + 8 ( 37 - 35 )^2 ] : 4
Ai làm nhanh mik tick
=128 - [68+8.4]:4
= 128 - 100:4
= 128 - 25
= 103
128 - [68 + 8(37 - 35)2 ] : 4
= 128 - [68 + 8.22 ] : 4
= 128 - [68 + 32] : 4
= 128 - 100 : 4
= 128 - 25
= 103
\(128-\left[68+8.\left(37-35\right)^2\right]:4\)
\(=128.\left[68+8.4\right]:4\)
\(=128.100:4\)
\(=32025\)
1.Tính nhanh:
a)1+2+3+4+...+2001+2002
b)2+4+6+8+...+100
c)132+128+124+...+76+72+68
GIÚP MÌNH NHA
a, 1+2+3+4+....+2001+2002=(2002+1).[(2002-1)+1] :2
=2003.1001
= 2005003
Bài 1: Thực hiện phép tính:
a) 3.52 + 15.22 – 26:2
b) 53.2 – 100 : 4 + 23.5
c) 62 : 9 + 50.2 – 33.3
d) 2345 – 1000 : [19 – 2(21 – 18)2]
e) 128 – [68 + 8(37 – 35)2] : 4
f) 568 – {5[143 – (4 – 1)2] + 10} : 10
e: \(=128-\left[68+8\cdot4\right]:4=128-25=103\)
\(a.3.5^2+15.2^2-26:2\) \(b.5^3.2-100:4+2^3.5\)
\(=75+60-13\) \(=250-25+40\)
\(=135+13=148\) \(=265\)
\(c.6^2:9+50.2-3^3.3\) \(d.2345-1000:\left[19-2.\left(21-18\right)^2\right]\)
\(=4+100-81\) \(=2345-1000:\left[19-2.3^2\right]\)
\(=23\) \(=2345-1000:\left[19-18\right]\)
\(=2345-1000:1\)
\(=2345-1000=1345\)
\(e.128-\left[68+8.\left(37-35\right)^2\right]:4\)
\(=128-\left[68+8.2^2\right]:4\)
\(=128-\left[68+32\right]:4\)
\(=128-100:4\)
\(=128-25=103\)
\(f.568-\left\{5.\left[143-\left(4-1\right)^2\right]+10\right\}:10\)
\(=568-\left\{5.\left[143-3^2\right]+10\right\}:10\)
\(=568-\left\{5.134+10\right\}:10\)
\(=568-\left\{670+10\right\}:10\)
\(=568-680:10\)
\(=568-68=500\)
a) 3.52 + 15.22 – 26:2 b) 53.2 – 100 : 4 + 23.5
c) 62 : 9 + 50.2 – 33.3 d) 32.5 + 23.10 – 81:3
e) 2345 – 1000 : [19 – 2(21 – 18)2] f) 128 – [68 + 8(37 – 35)2] : 4
g) 568 – {5[143 – (4 – 1)2] + 10} : 10 h) 107 – {38 + [7.32 – 24 : 6+(9
\(a.3.52+15.22-26:2\\ 156+330-13\\ =486-13\\ =473\)
\(b.53.2-100:4+23.5\\ =106-25+115\\ =81+115\\ =196\)