tinh nhanh
6^3+3x6^2+3^3/-13
tinh
B=3+3x6^2+6^2/13
63+3x6233/-13
Tìm giá trị của các biểu thức sau:
a) 2 mũ 7 x 9 mũ 3/6 mũ 5 x 8 mũ 2
d)6 mũ 3+3x6 mũ 2+3 mũ 3/-13
a)
= \(\dfrac{128.9^3}{65.8^2}\)
= \(\dfrac{128.729}{7776.64}\)
=\(\dfrac{93312}{497664}\)
= \(\dfrac{1}{3}\)
a)\(\dfrac{\left(0,6\right)^5}{\left(0,2\right)^6}\)
b)\(\left(1+\dfrac{2}{3}-\dfrac{1}{4}\right)x\left(\dfrac{4}{5}-\dfrac{3}{4}\right)\)
c)\(2:\left(\dfrac{1}{2}-\dfrac{2}{3}\right)^2\)
d)\(\dfrac{6^3+3x6^2+3^3}{-13}\)
a) \(\dfrac{\left(0,6\right)^5}{\left(0,2\right)^6}=\dfrac{\left(0,2.3\right)^5}{\left(0,2\right)^5.\left(0,2\right)}=\dfrac{\left(0,2\right)^5.3^5}{\left(0,2\right)^5.\left(0,2\right)}=\dfrac{3^5}{0,2}=\dfrac{243}{0,2}=1215\)
c) \(2:\left(\dfrac{1}{2}-\dfrac{2}{3}\right)^2=2:\left(\dfrac{3}{6}-\dfrac{4}{6}\right)^2=2:\left(-\dfrac{1}{6}\right)^2=2:\dfrac{1}{36}=72\)
3/3x6 + 3/6x9 + 3/9x12 + 3/12x15 + 3/15x18
3/3x6 + 3/6x9 + 3/9x12 + 3/12x15 + 3/15x18
= 1/3 - 1/6 + 1/6 - 1/9 + ... + 1/15 - 1/18
= 1/3 - 1/18
= 5/18
\(\frac{3}{3\times6}+\frac{3}{6\times9}+\frac{3}{9\times12}+\frac{3}{12\times15}+\frac{3}{15\times18}\)
=\(3\times\left(\frac{1}{3\times6}+\frac{1}{6\times9}+\frac{1}{9\times12}+\frac{1}{12\times15}+\frac{1}{15\times18}\right)\)
=\(3\times\left(\frac{1}{3}\times\frac{1}{6}+\frac{1}{6}\times\frac{1}{9}+\frac{1}{9}\times\frac{1}{12}+\frac{1}{12}\times\frac{1}{15}+\frac{1}{15}\times\frac{1}{18}\right)\)
=\(3\times\left(\frac{1}{3}\times\frac{1}{18}\right)\)
=\(3\times\frac{1}{54}=\frac{3}{54}=\frac{1}{18}\)
3+3x6
Tính)
a) 5+3x52/-8
b)103+5x102+53/63+3x62+33
\(b,\frac{10^3+5x10^2+5^3}{6^3+3x6^2+3^3}\)
\(=\frac{5\left(200+10^2+5^2\right)}{3\left(72+6^2+3^2\right)}\)
\(=\frac{5\left(200+100+25\right)}{3\left(72+36+9\right)}\)
\(=\frac{5.325}{3.117}\)
\(=\frac{125}{27}\)
tính nhanh
6/ 6,9 + 8,4 + 3,1 + 1,6 + 5,5 + 9,8 + 4,5 + 0,2
\(6,9+8,4+3,1+1,6+5,5+9,8+4,5+0,2\\ =\left(6,9+3,1\right)+\left(8,4+1,6\right)+\left(5,5+4,5\right)+9,8\\ =10+10+10+9,8\\ =39,8\)
Tính giá trị biểu thức sau:
2/1x3+3/3x6+4/6x10+5/10x15+6/15x21
\(\frac{2}{1.3}+\frac{3}{3.6}+\frac{4}{6.10}+\frac{5}{10.15}+\frac{6}{15.21}\)
= \(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{6}+\frac{1}{6}-\frac{1}{10}+\frac{1}{10}-\frac{1}{15}+\frac{1}{15}-\frac{1}{21}\)
= \(1-\frac{1}{21}\)
= \(\frac{20}{21}\)
Ủng hộ mk nha !!! ^_^