\(\frac{21^2.14.126}{35^5.6}\)

\(=\frac{21^2.14.21.6}{35^5.6}\)

\(=\frac{3^3.7^3.7.2}{35^5}\)

\(=\frac{3^3.7^4.2}{5^4.7^4.35}\)

\(=\frac{9.2}{5^4.35}=\frac{18}{21875}\)

\(C=\frac{21^2.14.126}{35^5.6}=\frac{3^2.7^2.2.7.2.3^2.7}{5^5.7^5.2.3}=\frac{3^4.7^4.2^2}{5^5.7^5.2.3}=\frac{3^3.1.2}{5^5.4.1.1}=\frac{54}{12500}=\frac{27}{6250}\)

\(A=\dfrac{21^2.14.125}{35^5.6}=\dfrac{3^2.7^2.2.7.5^3}{7^5.5^5.2.3}=\dfrac{3^2.7^3.2.5^3}{7^5.5^5.2.3}=\dfrac{3}{7^2.5^2}=\dfrac{3}{1225}\)

rut gon , mk goi y z

\(\frac{21^2.14.125}{35^5.6}=\frac{\left(3.7\right)^2.7.2.5^3}{\left(5.7\right)^5.2.3}=\frac{3^2.7^2.7.2.5^3}{5^5.7^5.2.3}\)

\(=\frac{3^2.7^3.2.5^3}{5^5.7^5.2.3}=\frac{3.1.1.1}{5^2.7^2.1.1}\)

\(=\frac{3}{35^2}=\frac{3}{1225}\)

a=78/35

b=22/12

c=1/1

d=40202090/4040090

e=1,24025667172...

f=871,82

ko biết đúng ko [0_0'] hihi

G=(21².14.125):35⁵.6

=\(\frac{\left(3.7\right)^2.7.2.5^{^3}}{\left(7.5\right)^5.2.3}\)=\(\frac{3^2.7^2.7.5^3}{7^5.5^5.3}\)=\(\frac{3}{7^2.5^2}\)=\(\frac{3}{49.25}\)=\(\frac{3}{1225}\)

\(G=\frac{21^2.14.125}{35^5.6}\)

\(G=\frac{\left(3.7\right)^2.7.2.5^3}{\left(7.5\right)^5.2.3}=\frac{3}{7^2.5^2}=\frac{3}{49.25}=\frac{3}{1225}\)

bn biết làm phần H k

A= \(\dfrac{1}{1.2}\)+ \(\dfrac{1}{2.3}\)+ \(\dfrac{1}{3.4}\)+ \(\dfrac{1}{4.5}\)+ \(\dfrac{1}{5.6}\)

= 1-\(\dfrac{1}{2}\)+ \(\dfrac{1}{2}\)- \(\dfrac{1}{3}\)+ \(\dfrac{1}{3}\)- \(\dfrac{1}{4}\)+ \(\dfrac{1}{4}\)- \(\dfrac{1}{5}\)+\(\dfrac{1}{5}\)- \(\dfrac{1}{6}\)

= 1 - \(\dfrac{1}{6}\)= \(\dfrac{5}{6}\)

mk chỉ bt làm câu 1 thôi ak

mong bn thông cảm

\(A=\frac{21^2.14.125}{35^5.6}=\frac{3^2.7^2.7.2.5^3}{5^5.7^5.6}=\frac{3^2.7^3.2.5^3}{5^5.7^5.2.3}=\frac{3}{5^2.7^2}=\frac{3}{1225}\)

\(P=\dfrac{32}{64}\cdot\dfrac{-57}{19}+\dfrac{35}{21}\cdot\dfrac{22}{44}=\dfrac{1}{2}\left(-3+\dfrac{5}{3}\right)=\dfrac{1}{2}\cdot\dfrac{-4}{3}=\dfrac{-2}{3}\)

\(Q=\dfrac{75}{125}\cdot\dfrac{82}{164}+\dfrac{49}{98}\cdot\dfrac{-35}{105}=\dfrac{1}{2}\left(\dfrac{3}{5}-\dfrac{1}{3}\right)=\dfrac{1}{2}\cdot\dfrac{4}{15}=\dfrac{2}{15}\)