X +5 .2-(32+16.3:15)=0
GIÚP TUI VỚI MN ƠI
a) (x – 5)(2x -32) = 0
b) 2(3x – 15)(5 – x) = 0
giúp em với
a) \(\left(x-5\right)\left(2x-3^2\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=5\\2x=9\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=5\\x=\dfrac{9}{2}\end{matrix}\right.\)
b) \(2\left(3x-15\right)\left(5-x\right)=0\)
\(\Rightarrow6\left(x-5\right)\left(5-x\right)=0\Rightarrow x=5\)
(x - 5)(2x - 32) = 0
=> \(\left[\begin{array}{} x - 5 = 0\\ 2x - 3^{2} = 0 \end{array} \right.\)=> \(\left[\begin{array}{} x = 0 - 5 = -5\\ 2x = 0 - 3^{2} = 0 - 9 = -9 => x = \dfrac{9}{2} \end{array} \right.\)
b) 2(3x - 15)(5 - x) = 0
(6x - 30)(5 - x) = 0
=> \(\begin{cases} 6x - 30 = 0\\ 5 - x =0 \end{cases} \) => \(\begin{cases} 6x = 0 + 30 = 30 => x = 5\\ x = 0 + 5 = 5 \end{cases} \)
Tìm x:
x - {[ -x + ( x + 3)]} - [( x + 3) - ( x - 2)] = 0
GIÚP EM VỚI MN ƠI!!!!!
\(\Leftrightarrow x-\left[3-x+3+x-2\right]=0\)
=>x=4
tìm x :
(2x + 5) :4 - (32 +16.3 : 6 - 15) = 0
(2x+5):4-(32+16.3:6-15)=0
(2x+5):4-25=0
(2x+5):4 =0+25
(2x+5):4 =25
(2x+5) =25:4
2x+5 =6,25
2x =6,25-5
2x =1,25
x =1,25:2
x =0,625
các bạn nhớ k cho mình nha
(2x + 5 ): 4 - ( 32 + 16.3 : 6 - 15 ) = 0
(2x + 5 ) : 4 - ( 32 + 48 : 6 - 15 ) = 0
(2x + 5 ) : 4 - ( 32 + 8 - 15 ) = 0
(2x + 5) : 4 - 25 = 0
(2x + 5) : 4 = 0 + 25
(2x + 5 ) : 4 = 25
2x + 5 = 25 x 4
2x + 5 = 100
2x = 100 - 5
2x = 95
=> x = 95 : 2 = 47,5
9- x mũ 2=0
giúp tui với
9-\(X^2\)=0
9-\(X^2\)=0:2
9-\(X^2\)=0
X=0+9
X=9
9=3.3
=\(3^2\)
VẬY X=3
MIK LM KO LOGIC CHO LẮM ĐÂU
Tìm x, biết:
(3x - 2)2-6x+4=0
giúp tui với
\(\left(3x-2\right)^2-6x+4=0\\ =>\left(3x-2\right)^2+2\left(-3x+2\right)=0\\ =>\left(2-3x\right)^2+2\left(2-3x\right)=0\\ =>\left(2-3x\right)\left(2-3x+2\right)=0\\ =>\left(2-3x\right)\left(4-3x\right)=0\\ \)
=> 2-3x=0 hoặc 4-3x=0
Nếu 2-3x=0 thì 3x=2 => \(x=\dfrac{2}{3}\)
Nếu 4-3x=0 thì 3x=4 => \(x=\dfrac{4}{3}\)
Vậy \(x=\dfrac{2}{3},x=\dfrac{4}{3}\)
x+5.2-(32+16.3:6-15)=0
x + 10 - (32 + 48 : 6 - 15) = 0
x + 10 - (32 + 8 - 15) = 0
x + 10 - 25 = 0
x = 0 + 25 - 10
x =15
bay gio mk ranh rui mk lam cho
x+5.2-(32+16.3:6-15)=0
x+5.2-(32+48:6-15) =0
x+5.2-(32+6-15) =0
x+5.2-(38-15) =0
x+5.2-23 =0
x+10-23 =0
x+10 =0+23
x+10 =23
x=23-10
x=13
chuc bn hoc gioi!
x+5.2-(32+16:3x6-15)=0
=> x+ 5+10-(32:32-15)=0
=> x+ 15- (-14)=0
=>x+15 +14=0
=> x= 0-14-15
=>x= -29
Tim x
x+5.2-(32+16.3:16-15)=0
x+5,2-(32+16.3:16-5)=0
(=)x+5,2-30=0
(=)x+5,2=30
x=24,8
chúc bạn học tốt ^_^
(x+2)(x- 4) = 0
Giúp mình với m.n ơi
\(\Rightarrow\left[{}\begin{matrix}x+2=0\\x-4=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-2\\x=4\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x+2=0\\x-4=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-2\\x=4\end{matrix}\right.\)
X+5.2—(32+16.3:6—15)=0
Tìm x
a) (x-140):7=33_22_3
b) x-6:2-(48-24):2:6-3=0
c) x+5-2-(32+16.3:6-15)=0
Làm ơn giúp mình với T-T
a)\(\left(x-140\right)\)\(\div\)7=27-4-3 =20\(\Rightarrow\) \(\left(x-140\right)\) =20x7=140\(\Rightarrow\) x=0