\(\left(\sqrt{7+3x}-4\right)+\left(\sqrt{13-3x}-2\right)+5.\left(\sqrt{\left(7+3x\right)\left(13-3x\right)}-8\right)=0\)

=) \(\frac{7+3x-16}{\sqrt{7+3x}+4}+\frac{13-3x-4}{\sqrt{13-3x}+2}+5.\left(\sqrt{91+18x-9x^2}-8\right)=0\)

=) \(\frac{3\left(x-3\right)}{\sqrt{7+3x}+4}+\frac{3\left(3-x\right)}{\sqrt{13-3x}+2}+\frac{5\left(27+18x-9x^2\right)}{\sqrt{91+18x-9x^2}+8}=0\)

=) \(\frac{3\left(x-3\right)}{\sqrt{7+3x}+4}-\frac{3\left(x-3\right)}{\sqrt{13-3x}+2}-\frac{45\left(x+1\right)\left(x-3\right)}{\sqrt{91+18x-9x^2}+8}=0\)

=) đến đây chắc là tự làm đc rồi

Đặt \(\sqrt{7+3x}=a;\sqrt{13-3x}=b\)

=>a+b+5ab=46

=>(a+b)^2=46-5ab

=>a^2+b^2+2ab=2116-460ab+25a^2b^2

=>25a^2b^2-460ab+2116=7+3x+13-3x+2ab

=>25a^2b^2-462ab+2096=0

=>\(\left[{}\begin{matrix}ab=\dfrac{262}{25}\\ab=8\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}\left(7+3x\right)\cdot\left(13-3x\right)=109.8304\\\left(7+3x\right)\left(13-3x\right)=64\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}91-21x+39x-9x^2=109.8304\\91-21x+39x-9x^2=64\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}-9x^2+18x-18.8304=0\\-9x^2+18x+27=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-1\end{matrix}\right.\)

a)5-(13-3x)=109-(32+109)

   5-(13-3x)=-32

       13-3x  =37

            3x  =-24

            3x  =-6

a)5-(13-3x)=109-(32+109)

   5-13+3x  =109-32-109

         -8+3x=-32

              3x=-32-(-8)

              3x=-24

                x=-24:3

                x=-8

b)|3x-6|+(x-2²)=0

   (3x-6)+(x-2²)=0

        3x-6+x-2²=0

                3x+x=0+6+2²

                    4x=10

                      x=\(\dfrac{5}{2}\)

c)/7-2x/=-13-5.(-8)

   |7-2x|=27

⇒7-2x=27 hoặc 7-2x=-27

        x=-10 hoặc x=-17

\(a)xy+3x-2y=11\)

\(\Leftrightarrow xy+3x-2y-6=5\)

\(\Leftrightarrow x\left(y+3\right)-2\left(y+3\right)=5\)

\(\Leftrightarrow\left(y+3\right)\left(x-2\right)=5\)

\(\Leftrightarrow\hept{\begin{cases}y+3=-1\\x-2=-5\end{cases}}\Leftrightarrow\hept{\begin{cases}y=-4\\x=-3\end{cases}}\)

\(\Leftrightarrow\hept{\begin{cases}y+3=1\\x-2=5\end{cases}}\Leftrightarrow\hept{\begin{cases}y=-2\\x=7\end{cases}}\)

\(\Leftrightarrow\hept{\begin{cases}y+3=-5\\x-2=-1\end{cases}}\Leftrightarrow\hept{\begin{cases}y=-8\\x=1\end{cases}}\)

\(\Leftrightarrow\hept{\begin{cases}y+3=5\\x-2=1\end{cases}}\Leftrightarrow\hept{\begin{cases}y=2\\x=3\end{cases}}\)

\(b)2x^2-2xy+x-y=12\)

\(\Leftrightarrow2x\left(x-y\right)+\left(x-y\right)=12\)

\(\Leftrightarrow\left(x-y\right)\left(2x+1\right)=12\)

\(\Rightarrow\left(x-y\right);\left(2x+1\right)\inƯ\left(12\right)\)

\(\RightarrowƯ\left(12\right)\in\left\{-1;1;-2;2;-3;3;-4;4;-6;6;-12;12\right\}\)

Vì 2x+1 luôn lẻ

\(\Rightarrow2x+1\in\left\{-1;1;-3;3\right\}\)

\(\Leftrightarrow\hept{\begin{cases}2x+1=-1\\x-y=-12\end{cases}}\Leftrightarrow\hept{\begin{cases}x=-1\\y=11\end{cases}}\)

\(\Leftrightarrow\hept{\begin{cases}2x+1=1\\x-y=12\end{cases}}\Leftrightarrow\hept{\begin{cases}x=0\\y=-12\end{cases}}\)

\(\Leftrightarrow\hept{\begin{cases}2x+1=-3\\x-y=-4\end{cases}}\Leftrightarrow\hept{\begin{cases}x=-2\\y=2\end{cases}}\)

\(\Leftrightarrow\hept{\begin{cases}2x+1=3\\x-y=4\end{cases}}\Leftrightarrow\hept{\begin{cases}x=1\\y=-3\end{cases}}\)

\(c)2xy-10y-x=13\)

\(\Leftrightarrow x\left(2y-1\right)-2y.5+5=18\)

\(\Leftrightarrow x\left(2y-1\right)-5\left(2y-1\right)=18\)

\(\Leftrightarrow\left(2y-1\right)\left(x-5\right)=18\)

\(\Leftrightarrow2y-1;x-5\inƯ\left(18\right)\)

\(\RightarrowƯ\left(18\right)\in\left\{-1;1;-2;2;-3;3;-6;6;-9;9;-18;18\right\}\)

Vì 2y-1  luôn lẻ

=>2y-1 thuộc {-1;1;-3;3;-9;9}

=> Làm  tương tự nhé

\(e)xy-2y^2+8y-3x=13\)

\(\Leftrightarrow xy-2y^2+2y+6y-3x-6=7\)

\(\Leftrightarrow y\left(x-2y+2\right)+3\left(-x+2y-2\right)=7\)

\(\Leftrightarrow y\left(x-2y+2\right)-3\left(x-2y+2\right)=7\)

\(\Leftrightarrow\left(x-2y+2\right)\left(y-3\right)=7\)

Tự khai triển như các câu trên.

Mình đg bận nên ko lm đc hết câu.

\(\left[5^3.\left(3x+2\right)\right]:13=5^5:\left(13^5:13^4\right)\)

\(\left[5^3\left(3x+2\right)\right]:13=5^5:13\)

\(\left[5^3\left(3x+2\right)\right]:13=\frac{3125}{13}\)

\(\left[5^3\left(3x+2\right)\right]=3125\)

\(3x+2=3125:5^3\)

\(3x+2=25\)

\(3x=25-2\)

\(3x=23\)

\(x=\frac{23}{3}\)

\(5^3.\left(3x+2\right):13=5^5:\left(13^5:13^4\right)\)

\(5^3.\left(3x+2\right):13=3125:13\)

\(5^3.\left(3x+2\right):13=\frac{3125}{13}\)

125 . ( 3x + 2 ) : 13 =\(\frac{3125}{13}\)

125 . ( 3x + 2 ) =\(\frac{3125}{13}.\frac{13}{1}=3125\)

3x + 2              = 3125 : 125

3x + 2              = 25

3x                    = 25 -2

3x                    = 23

x                    =  23 : 3 

x                    = \(\frac{23}{3}\)

bài này tui làm cho cậu cậu tick rồi mà

\(5^3\left(3x+2\right)\div13=10^3\div\left(13^5\div13^4\right)\)

\(\Rightarrow125\left(3x+2\right)\div13=1000\div13\)

\(\Rightarrow125\left(3x+2\right)=1000\)

\(\Rightarrow3x+2=1000\div125\)

\(\Rightarrow3x+2=8\)

\(\Rightarrow3x=8-2\)

\(\Rightarrow3x=6\Rightarrow x=6\div3\Rightarrow x=2\)

Vậy : x = 2

\(\left[5^3\left(3x+2\right)\right]:13=5^5:\left(13^5:13^4\right)\)

\(\left[5^3\left(3x+2\right)\right]:13=5^5:13\)

\(5^3\left(3x+2\right)=5^5:13.13\)

\(5^3\left(3x+2\right)=5^5\)

\(3x+2=5^5:5^3\)

\(3x+2=25\)

\(3x=25-2\)

\(3x=23\)

\(\Rightarrow x=\frac{23}{3}\)

 ( 375x+250 ) :13=3125;13

375x+250=3125

375x=2875

x=23/3

x = 60 nha bn !!!

có cần cách giải ko , mik ghi cho

\(a,\frac{7}{3}x+5=\frac{9}{6}x-7\)

\(\frac{7}{3}x-\frac{9}{6}x=-7-5\)

  \(\left(\frac{7}{3}-\frac{9}{6}\right).x=-12\)

                  \(\frac{5}{6}.x=-12\)

                        \(x=\left(-12\right):\frac{5}{6}\)

                        \(x=-\frac{72}{5}\)

\(b,3x+\frac{6}{4}=5-\frac{7x}{6}\)

\(3x+\frac{7x}{6}=5-\frac{6}{4}\)

\(\left(3+\frac{7}{6}\right).x=\frac{7}{2}\)

\(\frac{25}{6}.x=\frac{7}{2}\)

\(x=\frac{7}{2}:\frac{25}{6}\)

\(x=\frac{21}{25}\)

\(c,\frac{12}{5}x+6=\frac{17}{3}x+12\)

\(\frac{12}{5}x-\frac{17}{3}x=12-6\)

            \(-\frac{49}{15}x=6\)

                       \(x=6:\left(-\frac{49}{15}\right)\)

                       \(x=-\frac{90}{49}\)

\(d,6\left(3x+7\right)=12\left(2x-4\right)\)

       \(18x+42=24x-48\)

     \(18x-24x=-48-42\)

                 \(-6x=-90\)

                        \(x=15\)

\(e,13\left(2x-9\right)=8\left(3x-13\right)\)

      \(26x-117=24x-104\)

      \(26x-24x=-104+117\)

                      \(2x=13\)

                        \(x=\frac{13}{2}\)