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có liên quan tới hỗn số

15 và 3/4 ,5 và 4/9 , 7và 7/18 là hỗn số đấy bạn linh 

a) =3/11(-5/12+-7/12)-4/15

= 3/11.(-1)-4/15

=(-3)/11-4/15

=-89/165

a)

\(=\frac{3}{11}\left(\frac{-5}{12}+\frac{-7}{12}\right)-\frac{4}{15}\)

\(=\frac{3}{11}\left(\frac{-12}{12}\right)-\frac{4}{15}\)

\(=\frac{3}{11}\left(-1\right)-\frac{4}{15}\)

\(=\frac{3}{11}-\frac{4}{15}\)

\(=\frac{-89}{165}.\)

b) \(\left(\frac{3}{4}-\frac{4}{19}+\frac{2015}{2016}\right).\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)

 = \(\left(\frac{3}{4}-\frac{4}{19}+\frac{2015}{2016}\right).\left(\frac{3}{6}-\frac{2}{6}-\frac{1}{6}\right)\)

 = \(\left(\frac{3}{4}-\frac{4}{19}+\frac{2015}{2016}\right).0\)

 = 0.

1:

a: =12/10-7/10=5/10=1/2

b: \(=\dfrac{4}{13}-\dfrac{4}{13}+\dfrac{-5}{11}-\dfrac{6}{11}=-\dfrac{11}{11}=-1\)

2: 

a: x+2/7=-11/7

=>x=-11/7-2/7=-13/7

b: (x+3)/4=-7/2

=>x+3=-14

=>x=-17

3. are there any eggs?-No, there aren't some

4.is there any salt?- yes, there is any

5.are there any carrots?-yes, there are some

6.are there any apples?-no there aren't some

7.is there any suger?-yes, there is any

8.are there any cakes?-no there aren't some

9.is there any butter?-no. there isn't any

10. is there any mineral water?- yes. there is any

\(=\dfrac{3}{2}-\dfrac{2}{21}-\dfrac{7}{12}+\left[\dfrac{15}{21}-\dfrac{1}{3}+\dfrac{5}{4}-\dfrac{2}{7}-\dfrac{1}{3}\right]\)

=11/12-2/21+5/7-2/3+5/4-2/7

=11/12-2/3+5/4-2/21+3/7

=11/12-8/12+15/12-2/21+9/21

=18/12+7/21

=3/2+1/3

=9/6+2/6=11/6

\(B=\dfrac{3}{2}-\dfrac{2}{21}-\left\{\dfrac{7}{12}-\left[\dfrac{15}{21}-\left(\dfrac{1}{3}-\dfrac{5}{4}\right)-\left(\dfrac{2}{7}+\dfrac{1}{3}\right)\right]\right\}\)

\(B=\dfrac{3}{2}-\dfrac{2}{21}-\left\{\dfrac{7}{12}-\left[\dfrac{15}{21}-\left(-\dfrac{11}{12}\right)-\dfrac{13}{21}\right]\right\}\)

\(B=\dfrac{3}{2}-\dfrac{2}{21}-\left\{\dfrac{7}{12}-\dfrac{85}{84}\right\}\)

\(B=\dfrac{3}{2}-\dfrac{2}{21}-\left(-\dfrac{3}{7}\right)\)

\(B=\dfrac{11}{6}\)

Đặt : \(P=\frac{48^2\cdot8^5\cdot100^9}{12^2\cdot2^{15}\cdot4^2}\)

\(=\frac{\left(2^4\cdot3\right)^2\cdot\left(2^3\right)^5\cdot\left(2^2\cdot5^2\right)^9}{\left(2^2\cdot3\right)^2\cdot2^{15}\cdot\left(2^2\right)^2}\)

\(=\frac{2^8\cdot3^2\cdot2^{15}\cdot2^{18}\cdot5^{18}}{2^4\cdot3^2\cdot2^{15}\cdot2^4}\)

\(=\frac{2^{41}\cdot3^2\cdot5^{18}}{2^{23}\cdot3^2}=2^{18}\cdot5^{18}=\left(2\cdot5\right)^{18}=10^{18}\)

Vậy : \(P=10^{18}\)