\(\frac{6^6+6^3.3^3+3^6}{-73}\)

\(=\frac{3^6.\left(2^6+2^3+1\right)}{-73}\)

\(=\frac{3^6.73}{-73}\)

\(=3^6.\left(-1\right)=-729\)

\(=\dfrac{3^6\cdot2^6+2^3\cdot3^6+3^6}{-73}=\dfrac{3^6\left(2^6+2^3+1\right)}{-73}=-3^6=-729\)

=−729

\(\frac{6^6+6^3.3^3+3^6}{-73}\)

\(=\frac{3^6.2^6+2^3.3^6+3^6}{-73}\)

\(=\frac{3^6.\left(2^6+2^3+1\right)}{-73}\)

\(=\frac{3^6.73}{-73}\)

\(=-729\)

\(A=\frac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}+\frac{16^3.3^{10}+120.6^9}{4^6.3^{12}+6^{12}}\)

\(=\frac{2^{12}.3^5-\left(2^2\right)^6.\left(3^2\right)^2}{2^{12}.3^6+\left(2^3\right)^4.3^5}-\frac{\left(2^4\right)^3.3^{10}+2^3.3.5.\left(2.3\right)^9}{\left(2^2\right)^6.3^{12}+\left(2.3\right)^{12}}\)

\(=\frac{2^{12}.3^5-2^{12}.3^4}{2^{12}.3^6-2^{12}.3^5}-\frac{2^{12}.3^{10}-2^3.3.5.2^9.3^9}{2^{12}.3^{12}+2^{12}.3^{12}}\)

\(=\frac{2^{12}.\left(3^5-3^4\right)}{2^{12}.\left(3^6-3^5\right)}-\frac{2^{12}.3^{10}-2^{12}.3^{10}.5}{2^{12}.3^{12}+2^{12}.3^{12}}\)

\(=\frac{3^5-3^4}{3^6-3^5}-\frac{2^{12}.3^{10}.\left(1-5\right)}{2^{13}.3^{12}}\)

\(=\frac{162}{486}-\frac{2^{12}.3^{10}.\left(-4\right)}{2^{13}.3^{10}.3^2}=\frac{1}{3}-\frac{2^{14}.3^{10}.\left(-1\right)}{2^{13}.3^{10}.9}\)

\(=\frac{1}{3}-\frac{2.1.\left(-1\right)}{1.1.9}=\frac{1}{3}-\frac{2}{9}=\frac{1}{9}\)

\(3^6:3^2+2^3.2^2-3^3.3\)

\(=3^4+2^5-3^4\)

\(=2^5=32\)

eo ôi t làm rồi mà bị xoá :v thôi  t hướng dẫn :v

Tạc TS và MS ra rồi gộp và triệt tiêu :) nếu k lm đc ibx t làm cho :)

Ta có:

\(A=\frac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}+\frac{16^3.3^{10}+120.6^9}{4^6.3^{12}+6^{12}}\)

\(A=\frac{2^{12}.3^5-\left(2^2\right)^6.9^2}{12^6+8^4.3^5}+\frac{16^3.3^9.3+120.3^9.2^9}{4^6.\left(3^2\right)^6+6^{12}}\)

\(A=\frac{2^{12}.3^5-2^{12}.9^2}{3^6.4^6+8^4.3^5}+\frac{3^9.\left[16^3.3+120.2^9\right]}{4^6.3^{12}+3^{12}.2^{12}}\)

\(A=\frac{2^{12}.162}{3^5.3.4^6+3^5.8^4}+\frac{3^9.73728}{3^{12}.\left(4^6+2^{12}\right)}\)

\(A=\frac{2^{12}.162}{3^5.\left(3.4^6+8^4\right)}+\frac{3^9.73728}{3^{12}.8192}\)

         Đến đây bn tự làm nha hoa mắt lắm ròi

=\(\frac{46656+216.27+729}{-73}\)

=\(\frac{46656+5832+729}{-73}\)

=\(\frac{52488+729}{-73}\)

=\(\frac{53217}{-73}\)=-729

\(n=\frac{6^{6+}6^3\times3^3+3^6}{-73}=\frac{2^6\times3^6+3^6\times2^3+3^6}{-73}=\frac{3^6\times\left(2^6+2^3+1\right)}{-73}=\frac{3^6\times73}{-73}=\left(-3\right)^6=3^6\)