3.|x| + 9 = 24

=> 3.|x| = 24 -9 

=> 3.|x| = 15 

=>|x| = 15 : 3 

=> |x| = 5

=> x\(\in\) { -5 ; 5}

\(3\left|x\right|+9=24\\ \Rightarrow3\left|x\right|=24-9\\ \Rightarrow3\left|x\right|=15\\ \Rightarrow\left|x\right|=\dfrac{15}{3}\\ \Rightarrow\left|x\right|=5\\ \Rightarrow x=\pm5\)

Vậy \(x\in\left\{5;-5\right\}\)

\(24+\frac{x}{50}+x=\frac{3}{5}\)

\(24+\frac{x}{50}+\frac{50x}{50}=\frac{3}{5}\)

\(24+\frac{51x}{50}=\frac{3}{5}\)

\(\frac{51x}{50}=-\frac{175}{5}\)

\(\Rightarrow255x=-8750\)

\(\Rightarrow x=-\frac{1750}{51}\)

x + x/3       = 24

x/1 + x/3   = 24

3x/3 + x/3 = 24

4x/3           = 24

4x               = 24 . 3

4x               = 72

  x               = 72 : 4

  x               = 18

\(x+\frac{x}{3}=24\)

\(\frac{x}{1}+\frac{x}{3}=24\)

\(\frac{3x}{3}+\frac{x}{3}=24\)

\(\frac{4x}{3}=24\)

\(4x=24\times3\)

\(4x=72\)

\(x=72:4\)

\(x=18\)

X + \(\frac{x}{3}\)= 24

\(\frac{x}{1}\)+  \(\frac{x}{3}\) = 24

\(\frac{3x}{3}\)+  \(\frac{x}{3}\) =24

\(\frac{4x}{3}\) =24

4x= 24x3

4x=72

x =72:4 

x=18

tk nhé

\(3^{x+2}-3^x=24\)

\(3^x.3^2-3^x.1=24\)

\(3^x.\left(3^2-1\right)=24\)

\(3^x.\left(9-1\right)=24\)

\(3^x.8=24\)

\(3^x=24:8\)

\(3^x=3\)

\(3^x=3^1\)

\(\Rightarrow x=1\)

435+24:x = 500 - 65 + 24:3

435+24:x = 435+24:3

=> 24:x= 24:3 (vì chung số hạng 435)

=> x = 3

Theo đề bài ta thấy:

435+24:x=500-65+24:3

Mà 435=500-65 nên chỉ còn 24:x=24:3

\(\Rightarrow\)X=3

x+x/3 =24

x/1+x/3=24

3x+x/3=24

4x/3=24

4x=24.3

4x=72

x=72/4

x=18

\(+\frac{x}{3}=24\)

\(=>x+x.\frac{1}{3}\)\(=24\)

\(=>x.1+x.\frac{1}{3}=24\)

\(=>x.\left(1+\frac{1}{3}\right)=24\)

\(=>x.\frac{4}{3}\)\(=24\)

\(=>x=24:\frac{4}{3}\)

\(=>x=24.\frac{4}{3}\)

\(=>x=18\)

mk ko bt

k mk nhé

Tao không biết và tao cũng chẳng quan tâm

\(x+\frac{x}{3}=24\)

\(x+x.\frac{1}{3}=24\)

\(x\left(\frac{1}{3}+1\right)=24\)

\(x.\frac{4}{3}=24\)

\(x=24:\frac{4}{3}\)

\(x=18\)

x+x/3=24                                mà x/3 hay chia z ?

     x/3=

      x/3=

      x    =

       x    =