x\(^2\) + 6x + 8
Những câu hỏi liên quan
c) A= x(x+2)(x+4)(x+6)+8
A= x(x+6)(x+2)(x+4)+8
A= (x2+6x)(x2+6x+8)+8
Gọi x2+6x = a
A= a(a+8)+8
A= a2+8a+8= (a-4)2-8
A= (a-4)2-8 = (x2+6x+4)2-8\(\ge\)-8
Dấu bằng khi x2+6x+4= 0\(\Leftrightarrow\)x= -3-\(\sqrt{5}\)
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31 tháng 8 2021 lúc 13:57
Tìm x
\(\sqrt{x^2-6x+10}+\sqrt{x^2-6x+8}+\sqrt{x^2-6x+12}=4+\sqrt{3}\)
bài 3
a. (6x+1)^2+(6x-1)^2-2(1+6x)(6x-1)
b. x(2x^2-3)-x^2(5x+1)+x^2
c. 3x(x-2)-5x(1-x)-8(x^2-3)
d. 3(2^2+1)(2^4+1)(2^8+1)(2^16+1)
a) Ta có: \(\left(6x+1\right)^2+\left(6x-1\right)^2-2\left(1+6x\right)\left(6x-1\right)\)
\(=\left(6x+1\right)^2-2\left(6x+1\right)\left(6x-1\right)+\left(6x-1\right)^2\)
\(=\left(6x+1-6x+1\right)^2=2^2=4\)
b) Ta có: \(x\left(2x^2-3\right)-x^2\left(5x+1\right)+x^2\)
\(=2x^3-3x-5x^3-x^2+x^2\)
\(=-3x-3x^3\)
c) Ta có: \(3x\left(x-2\right)-5x\left(1-x\right)-8\left(x^2-3\right)\)
\(=3x^2-6x-5x+5x^2-8x^2+24\)
\(=24-11x\)
d) Ta có: \(3\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2-1\right)\left(2+1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2^4-1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2^8-1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2^{16}-1\right)\left(2^{16}+1\right)\)
\(=2^{32}-1\)
Rút gọn biểu thức:
a) (6x + 1)^2 + (6x-1)^2 - 2(1+6x)(6x-1)
b) 3(2^2 +1) (2^4 +1) (2^8 +1)(2^16 +1)
c) x(2x^2 - 3) -x^2 (5x +1) +x^2
d) 3x(x-2) - 5x(1-x) - 8(x^2 - 3)
a) \(\left(6x+1\right)^2+\left(6x-1\right)^2-2\left(1+6x\right)\left(6x-1\right)\)
\(=36x^2+12x+1+36x^2-12x+1-72x^2+2\)
\(=4\)
c) \(x\left(2x^2-3\right)-x^2\left(5x+1\right)+x^2\)
\(=2x^3-3x-5x^3-x^2+x^2\)
\(=-3x^3-3x\)
d) \(3x\left(x-2\right)-5x\left(1-x\right)-8\left(x^2-3\right)\)
\(=3x^2-6x-5x+5x^2-8x^2+24\)
\(=-11x+24\)
Rút gọn phân thức
a) (6x+1)^2 + (6x-1)^2 - 2(1+6x).(6x-1)
b) x(2x^2 - 3) - x^2(5x+1) + x^2
c) 3(2^2+1).(2^4+1).(2^8+1).(2^16+1)
d) 3x(x - 2) - 5x(1 - x) - 8(x^2 - 3)
a) (6x+1)2 + (6x-1)2 - 2(1+6x)(6x-1)
= (6x+1+6x-1)2
=144x2
b) x(2x2 -3) - x2(5x+1) +x2
=2x3 - 3x - 5x3 -x2+x2
=-3x3-3x
=-3x(x2+1)
c) 3(22+1)(24+1)(28+1)(216+1)
= (22-1)(22+1)(24+1)(28+1)(216+1)
= (24-1)(24+1)(28+1)(216+1)
= (28-1)(28+1)(216+1)
= (216-1)(216+1)
= 232 -1
d) 3x(x-2) - 5x(1-x) - 8(x2 -3)
= 3x2-6x - 5x + 5x2 - 8x2 +24
= -11x +24
a) = (6x+1)2 -2(6x+1)(6x-1)+(6x-1)2=(6x+1-6x+1)2=22=4
rút gọn biểu thức
a.(6x+1)^2-(6x-1)-2(1+6x)(6x-1)
b . x(2x^2-3) -x^2(5x+1)+x^2
c.3(2^2+1)(2^4+1)(2^8+1)(2^16+1)
d.3x(x-2)-5x(1-x-8)(x^2-3)
giải ptvt:
căn (x^2-4x+5)+căn( x^2-4x+8)+căn (x^2-4x+9)= 3+căn 5
căn (2-x^2+2x)+căn(-x^2-6x-8)=1+căn 3
căn (9x^2-6x+2)+căn(45x^2-30x+9)=căn(6x-9x^2+8)
giải ptvt:
căn (x^2-4x+5)+căn( x^2-4x+8)+căn (x^2-4x+9)= 3+căn 5
căn (2-x^2+2x)+căn(-x^2-6x-8)=1+căn 3
căn (9x^2-6x+2)+căn(45x^2-30x+9)=căn(6x-9x^2+8)
a) x^2-6x+12x-8
b)x^3+6x^2y+12xy^2+8y^3
c)-x^3+3^x2-3x+1
d)-a^3-6a^2-12a-8
f)x^3+8+6x.(x+2)
Cảm ơn mn😊😊
Rút gọn phân thức sau: a) (3x-6)/(x^3-6x^2+12x-8) b) (x^3+2x^2)/(x^3+6x^2+12x+8)
a: \(=\dfrac{3\left(x-2\right)}{\left(x-2\right)^3}=\dfrac{3}{\left(x-2\right)^2}\)
b: \(=\dfrac{x^2\left(x+2\right)}{\left(x+2\right)^3}=\dfrac{x^2}{\left(x+2\right)^2}\)
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