\(15,5\cdot20,8-3,5\cdot9,2-15,5\cdot9,2+3,5\cdot20,8\)

\(=15,8\left(20,8-9,2\right)+3,5\left(-9,2+20,8\right)\)

\(=15,5\cdot11,6+3,5\cdot11,6\)

\(=11,6\left(15,5+3,5\right)=11,6\cdot19=220,4\)

Ta có: \(15,5.20,8-3,5.9,2-15,5.9,2+3,5.20,8\)

\(=\left(15,5.20,8+3,5.20,8\right)-\left(3,5.9,2+15,5.9,2\right)\)

\(=20,8\left(15,5+3,5\right)-9,2\left(3,5+15,5\right)\)

\(=395,2-174,8=220,4\)

\(=-15.5\left(20.8+9.2\right)+3.5\left(9.2+20.8\right)\)

\(=30\cdot\left(-15.5+3.5\right)\)

\(=-12\cdot30=-360\)

a: \(=\dfrac{1.3-1.6}{2.6}-\dfrac{5}{6}:2\)

\(=-\dfrac{3}{26}-\dfrac{5}{12}\)

\(=\dfrac{-83}{156}\)

b: \(=20.8\left(-15.5+3.5\right)+9.2\left(3.5-15.5\right)\)

\(=-12\left(20.8+9.2\right)\)

\(=-12\cdot30=-360\)

kết quả là -360 nhé bn

Dễ mà bạn:

a) Cho A=1/100-1/100.99-1/99.98-...-1/3.2-1/2.1

\(A=\frac{1}{100}-\left(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{98.99}+\frac{1}{99.100}\right)\)

\(A=\frac{1}{100}-\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{98}-\frac{1}{99}+\frac{1}{99}-\frac{1}{100}\right)\)

\(A=\frac{1}{100}-\left(1-\frac{1}{100}\right)=\frac{1}{100}-\frac{99}{100}=-\frac{98}{100}=-\frac{49}{50}\)

b) \(-15,5.20,8+3,5.9,2-15,5.9,2+3,5.20,8=-15,5.\left(20,8+9,2\right)+3,5\left(9,2+20,8\right)\)

\(=-15,5.30+3,5.30=30\left(3,5-15,5\right)=30.\left(-12\right)=-360\)

e) và g) đều là dãy số viết theo qui luật

we ckoi vc