\(=\dfrac{5^{102}\cdot\left(5-1\right)}{5^{99}\cdot5^2\cdot2-5^{101}}=\dfrac{5^{102}\cdot4}{5^{101}\cdot1}=5\cdot4=20\)

\(\left(5^{103}-5^{102}-5^{101}\right):\left(5^{99}.26-5^{99}\right)\)

\(=5^{101}.\left(5^2-5-1\right):5^{99}.\left(26-1\right)\)

\(=5^{101}.\left(25-5-1\right):5^{99}.25\)

\(=5^{101}.19:5^{99}.5^2\)

\(=5^{101}.19:5^{99+2}\)

\(=\frac{5^{101}.19}{5^{101}}\)

\(=19\)

j mà  nhìu zu zậy làm bao giờ mới xong

Ủng hộ mk đi các bạn
 

có tất cả số cặp là: (103-3):2=50( cặp)

Tổng dãy trên là:

3-4+5-6+.....-102

=-1+-1+...+-1

=-1(50)

=-50

A = 1 + (-2) + (-3) + 4 + 5 + (-6) + (-7) + 8 + .......... + 99 - 100 - 101 + 102 + 103

A = 1 - 2 - 3 + 4 + 5 - 6 - 7 + 8 + ................ + 99 - 100 - 101 + 102 + 103

A = ( 1 - 2 - 3 + 4 ) + ( 5 - 6 - 7 + 8 ) + ............. + ( 99 - 100 - 101 + 102 ) + 103

A = 0 + 0 + ............. + 0 + 103

A = 0 + 103

A = 103

\(3\times10^3+2\times10^2+5\times10^1\\ =3\times1000+2\times100+5\times10\\ =3000+200+50\\ =3250\)

`@` `\text {Ans}`

`\downarrow`

\(3\cdot10^3+2\cdot10^2+5\cdot10^1\)

\(=10\cdot\left(3\cdot10^2+2\cdot10+5\right)\)

\(=10\cdot\left[10\left(3\cdot10+2\right)+5\right]\)

\(=10\cdot\left[10\left(30+2\right)+5\right]\)

\(=10\cdot\left(320+5\right)\)
\(=10\cdot325\)

\(=3250\)

A= [(1+101)x101:2]-(102-103)
A= 5151+1
A=5152

B= [1+(-3)]+[4+(-5)]+.......[101+(-103)]+105
B= (-2)+(-2)...........+(-2)+105

=> A>B
B=(-2)x26+105
B=(-56)+105
B= 49